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[{(5/6)^1/5}^-1/6]^30={(5/6)^1/5}^-5=(5/6)^-1=6/5

Let the sides be 5x and 3x.Given,height=16cmarea=960 cm960=1/2×16×(5x+3x)960=8×8x64x=960x=960/64x=15

The parallel sides are 45 and 75.

Ans :- 183 × 30 = 549

A/B = 5/7Or, 185/B = 5/7Or, B = (185 × 7)/5Or, B = 1295/5Or, B = 255

let the ratio factor be x. then A = 5x and B = 7x now, 5x = 185x = 185/5 = 37

B = 7x = 7 *37 = 259B = 259

A/B = 5/7Or, 185/B = 5/7Or, B = (185×7)/5Or, B = 1295/5Or , B = 259

B=(185x7)/5 B =255 Correct

259 is the right answer

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15m => 900 rupee 1m => (900/15) rupee12m => (900/15) × 12 = 720 rupee

if 15m cost=rs900therefore,1m=900/15then12m=(900/15)*12=720 rupees ans

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Elevation=xtanx=h√3/h=√3So x is 60°

1085 is the answer to that question

730+998

1728

38 estimated to the nearest ten = 4063 estimated to the nearest ten = 60∴ The required estimation = (40××60) = 2400

700+900 agar digit =1600

700+1000

The number which is divisible by 8, 15 and 21 is also divisible by the L.C.M. of the number. The L.C.M. of 8, 15 and 21 is =8 = 2× 2× 215 = 3× 521 = 3× 7L.C.M. = 2× 2× 2× 3× 5× 7 = 840If we divide 110000 by 840, we willfind out that it is not exactly divisible and we get 800 asremainder.Thus the number nearest to 110000 but greater than 100000 which is exactly divisible by 840 and also divisible by 8, 15 and 21 is= 110000 - 840 = 109200Hence 109200 is exactly divisible by 8, 15 and 21.

110000 - 840 =109200 ?

In management accounting,fixed costsare defined asexpensesthat do not change as a function of the activity of a business, within the relevant period. For example, a retailer must pay rent and utility bills irrespective of sales.The expenses made for setting up the production plant are the fixed cost. It doesn’t change in the short time period and also doesn’t depend on the quantity of production. For e.g.: cost of machinery, building, managerial team etc. are the fixed cost. It is also known as overhead cost or supplementary cost.

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Given AP: 0.6, 1.7, 2.8, ............a = 0.6d = 1.7 - 0.6 = 1.1n = 100Sn = n/2[ 2a + (n-1)d] = 100/2 [ 2(0.6) + (100 - 1)×(1.1)] = 50[ 1.2 + (99× 1.1)] = 50[ 1.2 + 108.9] =50[110.1] = 5505

Formulas used =1. Circumference = 2 pie r2. Area of Quadrant = 1/4 Pie r²

Circumference = 2 Pie r 22 = 2 * 22/7 r r = 22 * 7 / 22 * 2 r = 7/2 or 3.5 cm

Area Of Quadrant = 1/4 Pie r² = (1/4) * (22/7 ) * 3.5 * 3.5 = 1 * 22 * 35 * 35 / 4 * 7 * 10 * 10 = 1 * 11 * 35 / 4 * 10 = 9.625 cm²

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First part of the question is incomplete as angle is not mentioned.

1/5 of 551/5*55112)2/7*492*7143)1/6*36060

32.67 the first 29.33 second 17.4 third

98 ÷ 3 = 32 88 ÷ 3 = 2987 ÷ 5 = 17

o is the correct answer.

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Area= 1/2* diagonal 1* diagonal 2= 1/2*20*28= 280cm^2

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since the sides of the two triangles are in the same ratio then the triangle are similar.then they could lie on the same line