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Find the number nearest to 110000 but greater than 100000 which is exactlydivisible by each of 8, 15 and 21. |
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Answer» The number which is divisible by 8, 15 and 21 is also divisible by the L.C.M. of the number. The L.C.M. of 8, 15 and 21 is =8 = 2× 2× 215 = 3× 521 = 3× 7L.C.M. = 2× 2× 2× 3× 5× 7 = 840If we divide 110000 by 840, we willfind out that it is not exactly divisible and we get 800 asremainder.Thus the number nearest to 110000 but greater than 100000 which is exactly divisible by 840 and also divisible by 8, 15 and 21 is= 110000 - 840 = 109200Hence 109200 is exactly divisible by 8, 15 and 21. 110000 - 840 =109200 ? |
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