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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A solid spherical ball of the metal is divided into two hemispheres and joined as shownthe figure. The solid is placed in a cylindrical tub full of water in ssolid is submerged in water. The radius and height of cylindrical tub are 4 emrespectively and the radius of spherical ball is 3 cm. Find the volume of water left in thecylindrical tub.inuch a way that the wholeand 11 cm |
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Answer» 4/3πr³= 12π cm³(vol.of 2 hemispheres)πr²h=176π cm³(vol. of cylinder)vol. displaced = vol. of 2 hemisphere=> vol.of water remaining isvol.of cylinder-vol. of 2 hemisphere= 176π-12π=154π = 484 cm³ ans: the remaining vol. of water in the cylinder is 484 cm³ Like my answer if you find it useful! |
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| 2. |
I.PindthevolumeofaspherewhosetadiusisUi) 063mFind the amount of water displaced by a solid spherical ball of diameterG0 021 m2.t0 28cm |
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| 3. |
Which of the following is a prime number?(A) 29(C) 1 |
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Answer» 29 (A) is a prime number |
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| 4. |
29) A die is thrown once. Find the probability of getting anumber lying between 2 and 6. |
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| 5. |
23. The image of an object placed at apoint A before a plane mirror LM isseen at the point B by an observer at LMD, as shown in the figure. Prove thatthe image is as far behind the mirroras the object is in front of the mirror. |
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| 6. |
23. The image of an object placed at apoint A before a plane mirror LM isseen at the point B by an observer atD, as shown in the figure. Prove thatthe image is as far behind the mirroras the object is in front of the mirror.L |
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Answer» 2 |
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| 7. |
he same as the remaindervisionsd) 79 +9h) 39+9 |
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Answer» 39/9= 13/3= 4 and 1 as remaindernow79/9= 8 ans and 7 as remainder |
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| 8. |
Ranjan starts his travelling at 7:30 a.m. from Delhi to Chandigarh by his car. If hereached Chandigarh at 1:40 p.m. at the speed of 75 km/hr, find the distance ofChandigarh from Delhi. |
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| 9. |
Write the whole number part and decimal part of given num(a) 14.25(b) 99.09(c) 178.752 |
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Answer» a) 14.25 whole number : 14 decimal part : 25 b) 99.09 whole number : 99 decimal part : 09 c) 178.752 whole number : 178 decimal part : 752 |
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| 10. |
\sqrt { 10 + \sqrt { 25 + \sqrt { 108 + \sqrt { 154 + \sqrt { 225 } } } } } |
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Answer» √10+√25+√108+√154+√225 = √10+√25+√108+√154+15 = √10+√25+√108+√169 = √10+√25+√108+13 = √10+√25+√121 = √10+√25+11 = √10+√36 = √10+6 = √16 = 4 thank u |
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| 11. |
\frac{\sqrt{10+\sqrt{25+\sqrt{108+\sqrt{154+\sqrt{225}}}}}{3 \sqrt{8}}}=? |
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| 12. |
Example 2. Write the realthe following complex num(i) 7 3i(ii) V5 +0iSolution, (i) The given complex1 |
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Answer» i) real part = 7 , complex part = 3iii) real part = √5 , complex part = 0 |
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| 13. |
. is a possihle to design a rectangular park of perimeter 80m and area 400 m1f oand breadth |
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| 14. |
when added to its 3(b)beris equal to 65. The number ivs29(c) 39(a) 39 |
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Answer» Let the number be xx+(2/3)x=655x/3=655x=195x=195/5x=39 |
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| 15. |
5. A Vertical pole of length 6m casts a shadow 4m long on the ground and at the same a tower casts ashadow 28m long. Find the Height of the tower.(A) 40(8) 42(C) 38(D) 44 |
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| 16. |
hrice a number increased by 6 equals 39. Find the number |
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Answer» ty |
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| 17. |
Three times a number decreased by 9 gives 39.Find the number. |
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Answer» let the number be x9-3x=39-3x=39-9-3x=30x=-30/3x=-10 |
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| 18. |
2. Three times a number decreased by 9 gives 39.Find the number |
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| 19. |
डिक कि जरा हि एक...” जी न ले16. हल कीजिए : 2 51 n‘ o+ Sin2 20221 |
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Answer» From which book have you taken this question? Please tell us so that we can provide you faster answer. thanks |
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| 20. |
AEgiven figure DE//BC. Find the values of x and y55°в <140。 |
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Answer» As given DE || BC so Alternate angle must be angles so x = 40° and y = 55° |
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| 21. |
10. An electric pole casts a shadow of length 20 m at a time when a tree 6 m high casts a shadovof length 8 m. Find the height of the pole.Hint (height of thρ trp) . (length of its shado |
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| 22. |
13. A godown is in the form of a cuboid of measures60 m x 40 m x 30 m. How many cuboidal boxescan be stored in it if the volume of one box is0.8 m3? |
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Answer» Volume of cubiodal godown = 60 × 40 × 30 m³ = 72, 000 m³ So, No. of box stored = Volume of godown/ volume of box = 72,000/0.8 = 90,000 |
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| 23. |
Solve this logic number sequence puzzle by the correct digit8080 = 61357 = 02022 = 11999 = 36666 = ? |
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Answer» 4 as we are counting No Of circles in the number. |
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| 24. |
(10) -48= a +5 of in a sit bhinसार करें |
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| 25. |
(A) 12 (B)9 C)1s (D) 105. A Vertical pole of length 6m casts a shadow 4m long on the ground and at the same a tower casts ashadow 28m long. Find the Height of the tower.(A) 40(B) 42(C) 38(D) 44 |
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| 26. |
thesametimea4 cm apart on the maps. At1b.At a certain time a tree 6 m high casts a shadow of length 8 metrecasts a shadow of length 20 metres. Find the height of the pole |
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| 27. |
A vertical pole of length 6 m casts a shadow 4 m long onand at the same time a tower casts a shadow 28 m long. Firheightof the tower. |
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| 28. |
6. Vertical pole is 10mts high. The length of its shadow is 10/3 mts. What iangle of elevation of the Sun ? |
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| 29. |
48÷6+12×2÷10 |
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Answer» by BODMAS rule48÷6+12×2÷10=8+2.4=10.4 |
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| 30. |
15.5,5540x+yx-y |
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| 31. |
(-8)*(10-5-48+98) |
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Answer» (-8)✖(10-5-48➕98)=(-8)❌(-5-48➕96)=(-8)✖(-53➕96)=(-8)❌45=-8✖45-360 =answer |
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| 32. |
In the adjoining figure, in ABC ADfind x and y.3.BCx 4555" |
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Answer» in ADC D=90 y+90+45=180 so y=45 in ABD D=90 x+55+90=180so x=35 |
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| 33. |
9. A mirror, 15 cm long and 12 cm wide is to be framed with a 3 cm wide frame. Find the area ofthe frame. If the cost of the frame is Rs 25 per cm^2, find the cost of the frame. |
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Answer» hi but your answer is wrong |
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| 34. |
4. A godown is in the form of a cuboid of measures 55 m x 45 m x 30 m. How manycuboidal boxes can be stored in it if the volume of one box is 1.25 m3?uar dug and 1000 bricks |
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Answer» According to the question Volume of godown = 55×45×30 = 74250 m³volume of a box = 1.25 m³so,number of boxes = 74250/1.25 =59400 boxex |
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| 35. |
Sspherical glass vessel has a cylindrical neck 8 cm long, 2 cm in diameter: thediameter of the spherical part is 8.5 em. By measuring the amount of water it holdschild finds its volume to be 345 cm Check whether she is correct, taking the abovas the inside measurements, and 3.14 |
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| 36. |
Fill in the blanks:(1) 32 Ă 34 Ă 33(2) x (S(3) 92+ 918(4) (-4)10+(-4)6(5) (55 x 55) +5835 |
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| 37. |
25.Solve for x and y44 30+=1055 40x+y x-y=13 : |
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Answer» hit like if you find it useful |
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| 38. |
55 x 78 |
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Answer» by basic multiplication78×55=4290 |
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| 39. |
25.Solve for x and y:44 30- = 1055 40=13 |
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Answer» hit like if you find it useful |
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| 40. |
I. Simplify by converting into expon1) 72 x 55 x 45 |
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Answer» 72 = 2³ × 3²55 = 11×545 = 3²× 572×55×45 = 2³×3⁴×5²×11 that's answer is6535 |
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| 41. |
55 + 1048 + 10 |
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Answer» first questions answer is 5.5second questions answer is 4.8 55 ÷ 10 = 5.5 48 ÷ 10 = 4.8 If you find this answer helpful then like it. |
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| 42. |
16. At a certain time a tree 6m high casts a shadow of length 8m at the same time a pole casts a shadow of length 20 mfind the height of the poleS10g co that the remainders are in orooortion?. |
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Answer» Let the height of the pole be x. Then, 6 : 8 = x : 20 ⇒ 6 / 8 = x / 20 ⇒ 8x = 20 × 6 ⇒ 8x = 120 ⇒ x = 120 / 8 ⇒ x = 15 m Hence, Required height of the pole is 15 m |
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| 43. |
5o Apole 14 m high casts a shadow of com. At theSame time, what will be the height of a treeength of whose shadow is 1m2 |
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| 44. |
8. How long will a man take to make a round of a circular field of radius 21 m, cycling at thespeed of 8 km/h?a A racetrack is in the form of a rino whose inner circumference is 528 m and the outer |
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| 45. |
through a cylindrical pipe, whose inner radius is 1 cm, at the rate of 80 cm/secinan empty cylindrical tank, the radius of whose base is 40 cm. What is the rise of water level intank in half an hour? |
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| 46. |
21. Water flows through a cylindrical pipe, whose inner radius is 1 cm, at the rate of 80 cm/secin |
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| 47. |
Water flows through a cylindrical pipe, whose inner radius is 1 cm, at the rate of 80 cm/secan empty cylindrical tank, the radius of whose base is 40 cm. What is the rise of water level intank in half an hour?inOR |
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| 48. |
Find the area of a circular ring whose inner and outer diameters are 20 cm and 22 cm, Tespectively |
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Answer» diameter of inner circle=20cm therefore radius=20/2=10cm diameter of outer circle=22cm therefore radius=22/2=11cm area of inner circle=πr² =22/7×10×10 =2200/7cm² area of outer circle=πr² =22/7×11×11 =2662/7cm² hence, area of the ring=2662-2200/7 =462/7 =66cm² |
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| 49. |
7. The below figure depicts a racing track whose left and right ends are semicircular.e between the two inner parallel line segments is 60 m and they are each 106 m long.If the track is 10 m wide, find(6) the distance around the track aloag its inner edge(i) the area of the track. |
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Answer» please like my answer if you find it useful |
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| 50. |
Fig. 12.26 depicts a racing track whose left and right ends are semicircular.Fig. 12.26The distance between the two inner parallel linesegments is 60 m and they are each 106 m long. Ifthe track is 10 m wide, find:0 the distance around the track along its inner edge() the area of the track |
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