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A solid spherical ball of the metal is divided into two hemispheres and joined as shownthe figure. The solid is placed in a cylindrical tub full of water in ssolid is submerged in water. The radius and height of cylindrical tub are 4 emrespectively and the radius of spherical ball is 3 cm. Find the volume of water left in thecylindrical tub.inuch a way that the wholeand 11 cm |
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Answer» 4/3πr³= 12π cm³(vol.of 2 hemispheres)πr²h=176π cm³(vol. of cylinder)vol. displaced = vol. of 2 hemisphere=> vol.of water remaining isvol.of cylinder-vol. of 2 hemisphere= 176π-12π=154π = 484 cm³ ans: the remaining vol. of water in the cylinder is 484 cm³ Like my answer if you find it useful! |
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