Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

vl 5! &nigavyot vL=Qc J\/I./#. ५१९३) 1

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Sum of angle 140 how

2.

Iwo ropes, one 8 metres long and the other 12 metres long are to be cut into piecesVir of the same length. What will the maximum possible length of each piece be ?

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take the HCF of 8 and 12

you get 4 answer which is the maximum possible lengthhope this will help you like my answer and make it best answer

HCF of 8 & 12you will get 4

HCF of 8 and 12 is 4

hcf of 8 and 12 is 4

3.

0COLULILI6. An electric pole casts a shadow of length 20 metres at a time when a tree 6 mhigh casts a shadow of length 8 metres. Find the height of the pole.

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Let ratio of electic pole:shadow=tree:shadowX:20=6:8X*8=20*6 =120X=120/8 =15m

4.

A tree 8 metres high casts a shadow of length24 metres. Find the height of a pole which casts aShadow 30 metres at the same time.

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5.

8. A piece of rope 'p' metres long is cut into 5 equal parts, (a) Find the length of each part, (b) If the lengthof each part is 4 metres, find the length of the whole piece of rope.

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6.

r,8. A spherical glass vessel has a cylindrical neck 8 cm long, 2 cm in diameter; the diaofthe spherical part is 8.5 cm. By measuring the amount of water it holds, a child find itsvolume to be 345 cm. Check whether she is correct, taking the above as the inmeasurements, and n 3.14

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7.

A spherical glass vessel has a cylindrical neck 8 cm long, 2 cm in diameter, the diametsl part is 8.5 cm. By measuring the amount of water it holds, a child findsisvolume to be 345 cm3. Check whether she is correct, taking the above as the insidemeasurements, and n 3.14.

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8.

8. Fig. 12.26 depicts a racing track whose left and right ends are sem icircular.Fig. 12.26The distance between the two inner parallel linesegments is 60 m and they are each 106 m long. Ifthe track is 10m wide, find:

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9.

3. A wooden toy rocket is in the shape of acone mounted on a cylinder, as shownin figure. The height of the entire rocketis 26 cm, while the height of the conicalpart is 6 cm. The base of the conicalportion has a diameter of 5 em, whilethe base diameter of the eylindricalportion is 3 cm. If the conical portion isto be painted orange and the cylindricalportion yellow, find the area of therocket painted with each of theseColours. (Take π= 3.14)6 cm26 cm3 cm!5 cmBase of cylinderBase of cone

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10.

13x2 ,一31x2 , 25x2

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Please post a clear picture!

Please specify the question!

11.

25x2 + 30x + 9 = 0

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25x² + 30x + 9 = 0

(5x)² + 2 × (5x) × 3 + 3² = 0

( 5x + 2)² = 0

x = -2/5

12.

CO) 25x2-by-rada

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25x^2 -1/9y^2z^2(5x)^2-(1/3yz)^2(5x+1/3yz)(5x-1/3yz)

13.

Talk to your partner about the following.1. The author's grandmother was a religious person. What are the differentways in which we come to know this?ntuoan the author and his

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14.

by changingof 10.

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4/5 = (4×2)/(5×2) = 8/10

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15.

iii) 25x2 30x+7-0

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Comparing the equation to ax^2+bx+c=0a=25b=-30c=7b^2-4ac = (900)-4(25)(7)=900-700 =200So the roots are x=-b+-√b^2-4ac/2a= 30+√200/50 or 30-√200/50=30+10√2/50 or 30-10√2/50=3+√2/5 or 3-√2/5

16.

Find the roots of quadratic equation 25x2+ 20x + 7 = 0

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17.

5. Alternators are usually operated at apower angle of about(a) 10°(c) 60°(b) 40°(d) 90

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An alternator power output is directly proportional to the sine of its load angle.

So the maximum power output from the alternator would occur when the load angle is 90 degrees.

18.

176MATHEMATICS9.Expand using Binomial Theorem | | +--いは0

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thank u

19.

12. Using binomial theorem, evaluate (101)

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20.

5. What should be subtracted from 10 to get 3 - ?

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let x be subtracted according to the question 10-x=15/410-15/4=x40-15/4=x4x=25X=25/4

25/4 is the correct answer

25/4 is right anawer of this question. p

21.

Using binomial theorem, prove that32n+2- 8n-9 is divisible by 64. [

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pura answer snd kro

22.

Using binomial theorem, prove that 34-1, isdivisible by 8.

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23.

8. Using Binomial theorem evaluate (0.99)^15 correctto four places of decina

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tq

24.

10. Using Binomial Theorem, indicate which number is larger (1.1) 10000 or 1000

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Very good question from 11th Ncert

25.

0. The table shows the relationship betweenthe number of songs Alishc hos purchased ondthe cost of her purchase. Find the rote ofchange, or slope.NUMBER OFCOST OFPURCHASE$3.27$6.24$9.21$11.19SONGS2810

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Rate of change or slope= (y1-y2)/(x1-x2)= (6.24-3.27)/(5-2)= .99

26.

Multiplying the equation throughout by 5, we get25x^2-30x-10 = 0

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25x^2-30x-10=0lets divide by 55x^2-6x-2=0so roots=(6+-root(36+40))/10=6+-root(76)/10

27.

1. What are the coordinates of the centroid of the triangle ABC if A12.3), B(65, 8) ancC(2, 1)?

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Explanation : coordinates of x = (average of x coordinates of 3 points , average of y coordinates of 3 points) = ((2+5+2)/3 , (3+8+1)/3) = (9/3 , 12/3) = (3,4)

Solution : (3,4)

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28.

The equation of parabola whose focus is (3. - 4) and directrixx - y + 5 = 0 is(A) (x + y)2 = 11X – 13y - 25(B) (x + y)2 = 22x - 26y - 25(C) (x + y)2 = 12x + 14y - 26(D) (x + y)2 = 22x - 26y - 30

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I don't knowwwwwwwwwwwwwww

29.

What should be multiplied with (-3x -5) to get 3-11x-10)?

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30.

2x^3 - 11x^2 +44x +27 , if x = 25/3-4i

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2(25/3-4×3×2×1)=2(25/3-24)=2(24/-21)=2(-3)=-6

-6 is the correct answer

2(25/3-4×3×2×1)-11(25/3-4×3×2×1)+44(25/3-4×3×2×1)+27=2(25/3-24)-11(25/3-24)+44(25/3-24)=2(25/21)-11(25/3-24)+44(25/3-24)=50/21-275/21+44(25/21)=50-275+1100/21=875/21=41.66667

31.

10, 2x2 + 11x+15 = 0

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Here We used Shri dharacharya formulaHIT THE LIKE BUTTON

32.

34 The number v18 308 can be written in the form va b where a and b are whole numbers ancab. The value of (a-b), is(2) 12(3) 16(4) 18

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33.

write the formulaused to find the total surface area of a right circular cylinder

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Total surface area of a right circular cylinder = Surface area of curved surface + Surface area of two bases= 2πrh + 2πr²

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34.

500+ 15 conrert into olacimalsanc

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500+15/100=500+0.15=500.15

35.

a) at (+,If the roots of the equation x2 - 2ax + a² + a-3 = 0 are real and less than 3, thenc) 3<a <d) a > 4b) 2 <a <34a) a <23.

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36.

The ratio between the curved surface area and the total surface area of aright circular cylinder is 1: 2. Find the volume of the cylinder if its totalsurface area is 616 cm2

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37.

17. The ratio between the curved surface area and the total surfacearea of atotaright circular cylinder is 1:2. Find the volume of the cylinder if itssurface area is 616 cm2

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38.

the ratio of the curved surface area to the total surface area of the right circular cylinder is 1: 3 find the volume of the cylinder if its total surface area is 1848 CM square

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Curved surface area/Total surface area = 2πr(r+h)/2rh

=>1/3=2πr(r+h)/2πrh=>r=2h (after calculating)

Total surface area is 1848cm^2=>2πr(r+h) =1848cm^2=>2π x 2h x(2h+h) =1848cm^2 (r=2h)=>h^2=49=>h=7

if h=7cm than r = 2x7=14cm

Volume of cylinder =πr^2h=(22/7) x (14)^2 x 7 = 4312cm^3 (ans)

39.

8. The ratio between the curved surface area and the total surface area of a right circular cylinder is1:2. Find the ratio between the height and radius of the cylinder.area(a) 1: 2 tne ratid

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40.

area of atotalright circular cylinder is 1:2. Find the volume of the cylinder if itssurface area is 616 cm17. The ratio between the curved surface area and the total surface

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41.

PLUSThe freezing point of a mercury is - 39°C and freezing of athe difference between the freezing point of mercury and allfreezing of an alcohol is -120°С. Fi

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difference is -39-(-120) -39 + 120120-3981 degree celsius

difference is -39-(-120)-39+120120-3981 degree celcius

81 ° C is the correct answer of the given question

42.

. Show at uiyIfa and β are the zeroes of the polynomial 6y2-7 y + 2, find a quadratic polynomial whose14.zeroes are- and.rden whose length is 4 m more than its width, is 36 m. Find the

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43.

5. Show that,' 'L-(2a +36) (2a -3b) 24ab

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44.

\frac{36^{\frac{7}{2}}-36^{\frac{9}{2}}}{36^{\frac{5}{2}}}

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((6^2)^(7/2)-(6^2)^(9/2))/(6^2)^(5/2)=(6^7-6^9)/(6^5)=6^7(1-6^2)/6^5=6^2(1-36)=36×(-35)=-1260

45.

36. If LA and ZP are acute angles such that tan A = tan p , then show that < A

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tan (A-P)= tan(A)-tan (P) /{1 - tan(A)tanP}

tan (A-P) = 0so tan (A-P) = tan (0)A -P = 0A = P

46.

2√3-3÷2√3+3

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2√3-3/2√3+32√3-3/2√3+3*(2√3-3)/(2√3-3)=12+9-12√3/12-9=21-12√3/3=7-4√3

47.

6.If ι and β are the zeroes of the polynomial x2 +4x+ 3,find the polynomial wherezeroes are 1 +and 1+R6

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First of all, factorize the given polynomial:

x^2+4x+3=0(x+3)(X+1)=0x=-3,-1

Let the -3 be the α, and the -1 be the β.

It is required to find the polynomials which have the roots of:

and .X=1+b/a and X=1+a/b

Substitute by α=-3, and β=-1:

Therefore, the roots are: x = 0 and x = 2

Therefore, the polynomial must be: x(x-2)=0

Polynomial:

x^2-2x=0

48.

1031ax + bx +c dx2ax + b(ax2 + bx + c)2ax +b-(2ax+ b)(ax2 + bx+ c)2(C) ody is, then2ax + b(B)2ax + b(ax2 + bx + c)(C) 0(D) (2ax+ b(ax2 + bx+ c)

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49.

If the polynomial 6 x^{4}+8 x^{3}-5 x^{2}+a x+b is exactly divisible by the polynomial 2x^2-5,thenfind the value of a and b.

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50.

5.3.3.3 Chebyshev's Inequality

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It's in the probability theorem

it says that fraction of data in any distribution that lies within k stnanderd deviation of the mean is 1-1/k^2