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costheta=√1-sin^2theta=√1-225/289=√289-225/289=8/17hence sectheta=17/8hence the given expression=(17/8-1)(1+8/17)/(17/8+1)(1-8/17)=(17-8/8)(17+8/17)/(17+8/8)(17-8/17)=(9/8)(25/17)/(25/8)(9/17)=1

cost of 25 newspaper are = cost of 1 * 25 = (37.50/15)*25 = 62.5 rs

25×4.8

but in option answer is giving west

through 1 right angle

44 Times; This follows logically from the the following1) Between one occurrence of the minute and hour hand alining and the next there will be two times that right angles form2) Between each hour stroke the hands will line up except during the 11:00 to 12:00 period (take 12:00 alinement to be included 12:00 to 1:00)3) In each 12 hour period there are 11 alinements - take two 12 hour periods and two right angles per alignment to find 11⋅2⋅2 = 44hence option 2

2pq + 7pq = 9pq

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If we turn from north to south, we make half revolution so we make 2 right angles.

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Curved surface are of cylinder =2πrh2πrh=704cm^22π×r×8=704r=704/2π8r=704/50.28r=14cm

Thanks

5xy(3x*x+xy) = 15x*x*xy + 5x*xy*y

good

70.4 is the correct answer of the given question

352÷5=352/5=70.4 correct answer

70.4 is correct answer

1st

2nd

It is of form integral e^x(f(X)+f'(X)=e^xf(X)henceas d/dx(1/X)=-1/x^2henceintegral will.be e^x(1/X)+c

2

1.

2,3,4,5,6 question solution bhejo

The diameter of wheel =28cm The radius = 14cm The circumference of circle = 2*22/7*14=88cm Therefore in one revolution it will cover 88cm distance Therefore, number of revolution=352/88=4

answer will de 400

1/i-1 = (i+1)/-2

its conjugate is 1/(i+1/-2) = -2/(1+i) = -2(1-i)/2 = i-1

none of the above

sin2A = 2sinA cosAcos2A = 2cos²A - 1 = 1 - 2sin²A∫ sinx dx = -cosx + C∫ cosx dx = sinx + C

∫ sin⁴x cos⁶x dx= ∫ sin⁴x cos⁴x cos²x dx= (1/16) ∫ 16 sin⁴x cos⁴x cos²x dx= (1/16) ∫ (2 sinx cosx)⁴ [ (cos2x + 1)/2] dx= (1/32) ∫ (2 sinx cosx)⁴ (cos2x + 1) dx= (1/32) ∫ (sin2x)⁴ (cos2x + 1) dx= (1/32) ∫ (sin⁴2x cos2x + sin⁴2x) dx= (1/32) ∫ sin⁴2x cos2x dx + (1/32) ∫ sin⁴2x dx= (1/32) ∫ sin⁴2x cos2x dx + (1/32) ∫ (sin²2x)² dx= (1/32) ∫ sin⁴2x cos2x dx + (1/32) ∫ [ (1 - cos4x)/2 ]² dx= (1/32) ∫ sin⁴2x cos2x dx + (1/32) ∫ (1 - cos4x)²/4 dx= (1/32) ∫ sin⁴2x cos2x dx + (1/128) ∫ (1 - cos4x)² dx= (1/32) ∫ sin⁴2x cos2x dx + (1/128) ∫ (cos²4x - 2cos4x + 1) dx= (1/32) ∫ sin⁴2x cos2x dx + (1/128) ∫ cos²4x dx - (1/64) ∫ cos4x dx + (1/128) ∫ dx= (1/32) ∫ sin⁴2x cos2x dx + (1/128) ∫ [(cos8x + 1)/2] dx - (1/64) ∫ cos4x dx + (1/128) ∫ dx= (1/32) ∫ sin⁴2x cos2x dx + (1/256) ∫ (cos8x + 1) dx - (1/64) ∫ cos4x dx + (1/128) ∫ dx= (1/32) ∫ sin⁴2x cos2x dx + (1/256) ∫ cos8x dx + (1/256) ∫ dx - (1/64) ∫ cos4x dx + (1/128) ∫ dx= (1/32) ∫ sin⁴2x cos2x dx + (1/256) ∫ cos8x dx - (1/64) ∫ cos4x dx + (3/256) ∫ dx

the only problem here is to solve the first integral in the above expression∫ sin⁴2x cos2x dxlet u = sin2x ==> du/dx = 2cos2x ==> dx = du/(2cos2x)

∫ sin⁴2x cos2x dx= ∫ u⁴ cos2x [du/(2cos2x)]= (1/2) ∫ u⁴ du= (1/2)(1/5) u⁵ + C= (1/10) u⁵ + C= (1/10) sin⁵2x + C

The finishing step:∫ sin⁴x cos⁶x dx= (1/32) ∫ sin⁴2x cos2x dx + (1/256) ∫ cos8x dx - (1/64) ∫ cos4x dx + (3/256) ∫ dx= (1/32) (1/10) (sin⁵2x) + (1/256) (1/8)(sin8x) - (1/64) (1/4)(sin4x) + (3/256) x + C= (1/320) sin⁵2x + (1/2048) sin8x - (1/256) sin4x + (3/256) x + C ⇦ ANSWER

AB is straight line so 40+35+angle at o=180si angle at o=105so AOC=180-105-40=35so COF=180-40-35=105

probability of sure is 1

60° is the correct answer of the given question

if f(x1)=y1 and f(x2)=y2then slope of line y=f(x) is given bym={f(x1)-f(x2)}/(x1-x2)so the required slope is m={f(1)-f (-1)}/(1-(-1))m=16-12/1+1=4/2=2