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15(sec θ-1) (1 + cos θ)B) If sin θ--> then find the value of17(sec θ + 1)(1-cos θ)Turn Over |
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Answer» costheta=√1-sin^2theta=√1-225/289=√289-225/289=8/17hence sectheta=17/8hence the given expression=(17/8-1)(1+8/17)/(17/8+1)(1-8/17)=(17-8/8)(17+8/17)/(17+8/8)(17-8/17)=(9/8)(25/17)/(25/8)(9/17)=1 |
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