Explore topic-wise InterviewSolutions in Current Affairs.

AB = 5CM , AC = 9CM , BC = 11CMIF points X,Y,Z are the midpoints of side AB, side BC and side AC of ΔABC.then,AX = BX = 5/2 = 2.5CM BY = CY = 11/2 = 5.5 CMAZ = CZ = 9/2 = 4.5 CMFrom the property, we can say that XY is parallel to AC. Similarly, YZ is parallel to AB and XZ is parallel to BC.then ,BY = XZ = 5.5CMYZ = XB = 2.5CMXY = CZ = 4.5CM

Hence , (XY, YZ, XZ.) = ( 4.5cm , 2.5cm , 5.5cm)

She earns 7500 in 16 daysso in one day she will earn 7500/16nowin 30days

= 7500*16/30750*16/3

4000

lets take unit digit of each number so they are 5,6,7 so multiplication of it 5*6*7=210 so 0 will be at unit place in 25^2*16^3*7^2

72 +36+v =180 v =72

72°+36°+v°=180°108°+v°. =180° v°=180°-108° v°=72°

using a_square+2ab+b_square

√8.356/√2.635 = 1.8796787...

this question is solve logarthoms mathod

y = √8.356/√2.635

logy = log(√8356/2635) = 1/2*[log(8356)-log(2635)] = 1/2*(3.92-3.42) = 1/2*(0.5) = 0.25so, y = 10^0.25 = 1.7782

approximate Value.. is this, you can follow the steps on your own

DIAMETER OF METALLIC SPHERE = OUTER DIAMETER OF HOLLOW SPHERE = 1 cm THEREFORE OUTER RADII = 0.5 cm = 5mm

THICKNESS = 1mm

THEREFORE INNER RADII = OUTER RADII - THICKNESS

= 5 mm - 1mm

= 4mm

Total no. of students= 300.Let total no. of news papers = n.Given every student reads 5 news papers and every newspaper is read by 60 students.Total no. of newspaper reading by every student = 300*5 = 1500 .Total no. of newspaper reading which each paper will get = 60*n .which implies that, 60*n = 300 *5 => 60 *n =1500=> n = 25

Total no. of newspapers is 25

(c) is correct option

Ans =total no.of newspapers is 25 correct ans is option (c)

Given newspaper read by 1 student = 5

so total newspaper read by 300 students = 300X 5 = 1500

Single newspaper is read by 60 studentso total different newspaper read = 1500/60= 25

tanks sir

y= x^sinx + (sinx)^cosx​let x^sinx = u and (sinx)^cosx= vdy/dx = du/dx + dv/dxu= x^sinx+++Taking log on both sideslog u = log(x^sinx) = sinx log xDifferntiating both sides1/u du/dx= cosx logx + sinx/x (product rule)du/dx= u {cosxlogx+sinx/x}du/dx= x^sinx(cosxlogx+sinx/x)

Now, v = (sinx)^cosxTaking log on both sideslog v = log {(sinx)^cosx} = cosxlog sinxDifferentiating1/v. dv/dx = (-sinx)log sinx+ cos x (cos x/ sin x)dv/dx = v { cos x cot x - sinx log sinx}​dv/dx = (sinx)^cos x (cos x cot x - sinx log sinx)=> dy/dx = {x^sinx(cosxlogx+sinx/x)} + {​(sinx)^cosx (cosx cot x -sinxlogsinx)}Therefore, dy/dx = x^sinx (cosxlog x + sinx/x) + sinx^cosx (cosx cotx - sinx log sinx)

thanks

y = f(sinx) dy/dx = f'(sinx)*cosx

y=sin^3xdy/dx=3sin^2x [d (sinx)/dx]dy/dx=3sin^2xcosx

Ans :- Steps: Draw a line across thecircleto make a "chord" Construct the perpendicular bisector of that chord to make a diameter of thecircle. Construct the perpendicular bisector of that diameter togetthecenterof thecircle.

(3x+5y)(3x+2y)=9x^2+6xy+15xy+10y^29x^2+21xy+10y^2

length of the hypotenuse is 15

May i know why it has been marked as spam?

y = (e^x)^xTaking log on both sides, log y = x*log(e^x)Differentiating both sides with respect to x,(1/y)(dy/dx) = {x/(e^x)}*(e^x) + log(e^x)=> dy/dx = xy + y*log(e^x)

dy/dx (sinx)= cosxthanks

cos X is the correct answer

y=sinxdy/dx=d/dx(sinx) =cosx

dy/dx=cosx is the right answer

Y=sinced(y)/dx=d(sinx)/dx=cosx Answer

dy/dx= cos x is the answer

dy/de(since)=coaxanswer.

Please hit the like button if this helped you

2a³/(s²+a²)² is the correct answer of the given question

Given - 2x+3y = sinx

Differentiating both sides with respect to x , we get

d/dx ( 2x+3y) = d/dx (sinx)

2.d/dx(x) + x.d/dx(2) + 3.d/dx(y) + y.d/dx(3) = cosx . d/dx(x) [ using product rule ]

2(1) + x(0) + 3.(dy/dx) + y(0) = cosx (1)

2 + 3(dy/dx) = cos x

dy/dx = ( cosx - 2) / 3

thank you

If you find this solution helpful, Please give it a 👍

Let 82:72::72:x=>82x=72×72=>x=63

Option 1 is correct.

I cannot understand

Let the missing number here(?) be x.

When 4 numbers are in continued proportion,a:b::c:d=>ad=bc

ans

3+0=3

1+14=15

7+6=6+7

0+18=18+0

3+0=3

1+14=15

7+6=6+7

0+18=18+0

3+0=31+14=157+6=6+70+18=18+0

3+0=31+14=157+6=6+70+18=18+0

18 2/11

18×2÷11 is the correct answer

18×2÷11 is right answer of that question

Given:d1=10; d2=6

Area of Rhombus= (d1 ×d2)/2=(10×6)/2=60/2=30 sq units

area of rhombus is half the product of diagnols=1/2×(d1 × d2)=1/2×10×6=60/2 =30 sq units

it is given, lenght of diagonals is 10 and 6 area=half of product of diagonals = 30

1/2 ×d1×d2 =1/2×6×10=30