dyFind in the following:dlx1, 2x + 3y sin x4, xy + y2 tan x + y

1.	dyFind in the following:dlx1, 2x + 3y sin x4, xy + y2 tan x + y
Answer» Given - 2x+3y = sinx Differentiating both sides with respect to x , we get d/dx ( 2x+3y) = d/dx (sinx) 2.d/dx(x) + x.d/dx(2) + 3.d/dx(y) + y.d/dx(3) = cosx . d/dx(x) [ using product rule ] 2(1) + x(0) + 3.(dy/dx) + y(0) = cosx (1) 2 + 3(dy/dx) = cos x dy/dx = ( cosx - 2) / 3 thank you

Answer»

Given - 2x+3y = sinx

Differentiating both sides with respect to x , we get

d/dx ( 2x+3y) = d/dx (sinx)

2.d/dx(x) + x.d/dx(2) + 3.d/dx(y) + y.d/dx(3) = cosx . d/dx(x) [ using product rule ]

2(1) + x(0) + 3.(dy/dx) + y(0) = cosx (1)

2 + 3(dy/dx) = cos x

dy/dx = ( cosx - 2) / 3

thank you

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