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suppose four terms a b c & d are in proportion so bc=adnow a=12 c=8 and d=14so b*8=12*14so b=21so second term is 21

so late but thanks

in a proportion second term*third term=first term*fourth term so third term = 32*217/112 = 2*117/7 = 234/7

thank you..

yesNegative numberscan berational numbers.Rational numbersare thenumberswhich can be expressed in the form P/Q, where P & Q are integers & Q is Not zero. ... 3/2 , 1/7, 22/7, 3.142, -2.3 are allrational numbers

Total cost = Rs. 176Rate of charge = 25 paise per sq.cm = Rs. 0.25 per sq.cm

Total cost of painting cone = Total surface area of cone * Rate of charge=> Total surface area of cone = Total cost of painting cone / Rate of charge= 176/0.25= 704 sq.cm

Let radius of cone be r cmslant height (l) = 25 cm

Total surface area of cone = πr(r+l)=> 704 = πr(r+l)=> 704 = 22r(r+25)/7=> 704*7/22 = r^2+25r=> 224 = r^2+25r=> 0 = r^2+25r-224=> 0 = r^2+32r-7r-224=> 0 = r(r+32)-7(r+32)=> 0 = (r-7)(r+32)=> 0 = r-7 or 0 = r+32=> r = 7 or -32

Discarding negative value as radius cannot be negativeTherefore, radius of cone = 7 cm

By Pythagoras Theorem, height of cone = (l^2-r^2)^1/2= (25^2-7^2)^1/2= (625-49)^1/2= (576)^1/2= 24 cm

Therefore, volume of cone = πr^2h/3= 22*7*7*24/3*7= 1232 cu. cm

R = 10 cmh = 14 cminner area = inner curved surface area + base area = 2πrh +πr² = 2×(22/7)×14×10 + (22/7)×10² = 880 + 314.28 = 1194.285 cm²rate = 5p per cm²cost = 1194.285×5 = 5971.4285 p

= 59.714 rupees

Total cost = Rs. 176Rate of charge = 25 paise per sq.cm = Rs. 0.25 per sq.cm

Total cost of painting cone = Total surface area of cone * Rate of charge=> Total surface area of cone = Total cost of painting cone / Rate of charge= 176/0.25= 704 sq.cm

Let radius of cone be r cmslant height (l) = 25 cm

Total surface area of cone = πr(r+l)=> 704 = πr(r+l)=> 704 = 22r(r+25)/7=> 704*7/22 = r^2+25r=> 224 = r^2+25r=> 0 = r^2+25r-224=> 0 = r^2+32r-7r-224=> 0 = r(r+32)-7(r+32)=> 0 = (r-7)(r+32)=> 0 = r-7 or 0 = r+32=> r = 7 or -32

Discarding negative value as radius cannot be negativeTherefore, radius of cone = 7 cm

By Pythagoras Theorem, height of cone = (l^2-r^2)^1/2= (25^2-7^2)^1/2= (625-49)^1/2= (576)^1/2= 24 cm

Therefore, volume of cone = πr^2h/3= 22*7*7*24/3*7= 1232 cu. cm

hilta dulta question

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S6=3(2a+5d)=992a+5d=336th term=a+5d=392a+5d-a-5d=33-39a=-6-12+5d=33 so d=93rd term+4th term=a+2d+a+3d=-12+45=333rd term=a+2d=-6+18=12sequence=-6,3,12,21,30,39,...

If four terms are in propotion product of mean terms = product of extreme terms

Let third term be n

Then,6*25 = 15*nn = 6*25/15 = 2*5 = 10

Hence,Third term is 10

nth term = a + (n-1)d where a is a first term and d is a common difference 3rd term is 6 so a + 2d = 6 7th term is 22 so a + 6d = 22 a + 6d - a - 2d = 22 - 6 4d = 16 d = 4 a + 8 = 6 a = -2 Sn = n/2(2a+(n-1)d) S45 = 45/2 * (2*(-2) + 44*4) = 45/2 * (-4+176) = 45/2 * 172 = 45*86 = 3870

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168 is correct answer.

a=253, , d=8-3=5; n=18, a+( n-1)d=253++17(5)=253-85=168

wrong

but answer given is 158

Given series is 3, 8, 13, ...... 253 here, first term , a = 3 common difference , d = 5 Let us find total number of terms at first.use Tn = a+(n-1)d=> 253 = 3 + (n - 1)5 => 250 = 5(n - 1) => n - 1 = 50 => n = 51 so, there are 51 terms in given series.now we know, mth term from last =last term - mth term + 1 so, 20th term from last = 51 - 20 + 1 = 32 hence, 20th from last = 32th term from first

use , T32 = a + (32-1)d= 3 + 31 × 5 = 3 + 155 = 158

hence , 20th term from last = 158

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Given:first term(a)= 121common difference (d)= 117- 121 = -4∵ n th term of an AP

an= a + (n – 1)d⇒121+(n-1)×(-4)⇒121-4n+4⇒12+4-4n⇒125 -4nan= 125 -4n

For first negative term , an <0⇒ 125-4n<0⇒125<4n⇒4n>125⇒n>125/4⇒n> 31 1/4

least integral value of n= 32

Hence, 32nd term of the given AP is the first negative term.

write a.p.in reverse order 253.....,13,8,3.here a=253,d=-8 and n=20so a20= a+(n-1)d a20=253+19×-5 a20=253-95 a20=158so,the 20th term from last term is 158

Straw

Bagpipes

battery

thread

Let the 1st paycheck be x (integer).

Mrs. Rodger got a weekly raise of $ 145.

So after completing the 1st week she will get $ (x+145).

Similarly after completing the 2nd week she will get $ (x + 145) + $ 145.

= $ (x + 145 + 145)

= $ (x + 290)

So in this way end of every week her salary will increase by $ 145.

x*2+2x-x+3x(x+2)-1(x+2)(x-1)(x+2)x=1/x=-2

{2,3}will be the roaster form

Hi Sunil,

Here is the answer to your question.

we know that (-4)^2=4^2=16

so A={-4, -3, -2, -1, 0, 1, 2, 3, 4}

A={-4,-3,-2,-1,0,1,2,3,4}

the answer to this question is A= {-4,-3,-2,-1,0,1,2,3,4}

{ -4,-3,-2,-1,0,1,2,3,4} is the correct answer of the given question is

set A = {-2,-1,0,1,2,3,4,5,6,}

8 - 1 + 1 × 36 ÷ 5 × 3 = 8 - 1 + 36 ÷ 5 × 3 = 8 - 1 + 7.2 × 3 = 7 + 21.6 = 28.6

For AP 3, 6, 9...a1 = 3, d = 6 - 3 = 3

nth term of AP an = a1 + (n-1)d

Therefore, 15th term of APa15 = a1 + 14d = 3 + 14*3 = 3 + 42 = 45

a=3,d=a2-a1=6-3=3n=15an=a+(n-1)dan=3+(15-1)3an=3+(14)3an=3+42an=45

a = 3, d = 5

Now, 253 = a + (n + 1) d

⇒ 253 = 3 + (n -1) x 5

⇒ 253 = 3 + 5n – 5 = – 2

⇒ 5n = 253 + 2 = 255

⇒ n = 255/5 = 51

Therefore, 20th term from the last term = 51 – 19 = 32

a32= a + 31d

= 3 + 31 x 5

= 3 + 155 = 158

Thus, required term is 158

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