17. Find the 20th term from the last term of the arithmeticprogression

1.	17. Find the 20th term from the last term of the arithmeticprogression 3, 8, 13,.... 253.
Answer» a = 3, d = 5 Now, 253 = a + (n + 1) d ⇒ 253 = 3 + (n -1) x 5 ⇒ 253 = 3 + 5n – 5 = – 2 ⇒ 5n = 253 + 2 = 255 ⇒ n = 255/5 = 51 Therefore, 20th term from the last term = 51 – 19 = 32 a32= a + 31d = 3 + 31 x 5 = 3 + 155 = 158 Thus, required term is 158 Hit like if you find it useful!

17. Find the 20th term from the last term of the arithmeticprogression 3, 8, 13,.... 253.

Answer»

a = 3, d = 5

Now, 253 = a + (n + 1) d

⇒ 253 = 3 + (n -1) x 5

⇒ 253 = 3 + 5n – 5 = – 2

⇒ 5n = 253 + 2 = 255

⇒ n = 255/5 = 51

Therefore, 20th term from the last term = 51 – 19 = 32

a32= a + 31d

= 3 + 31 x 5

= 3 + 155 = 158

Thus, required term is 158

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