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Put X=-1 in the equationhence3(-1)^3-1-1-3-1-1=-5

9x+3y=-12....3x+y=-418x+6y=-24....3x+y=-4subtract both the equations0 hence no solution possible.

The general term in expansion of (1 - y)^-n

tr+1= [n(n+1)(n+2)...(n+r-1)/r!].y^r

In the expansion of (1 - 2x)^-5/2, we havetr+1 = [(5/2)(5/2+1).....(5/2+r-1)/r!].(2x)^r

= [5*7*9...........(3+2r)/2^r*r!].2^r.x^r

Putting r = 6, we gett7 = [5*7*9*11*13*15/ 2^6*6!].2^6.x^6

= [15015/16]x^6

Therefore, Coefficient of x^6 in expansion of (1 - 2x)^-5/2 is15015/16

Given: Let PQ and RS be two equal chords of a given circle and they are intersecting each other at point T.

To prove: PT= RT and ST = QT

Construction:Draw OV⊥PQand OU⊥SR. Join OT.

Proof: In ΔOVT and ΔOUT,OV = OU (Equal chords of a circle are equidistant from the centre)OT = OT (Common )∴ ΔOVT≅ΔOUT ( R.H.S.)

⇒VT= UT (By CPCT )

⇒ PV + VT = RU + UT (∵AV = RU = ( ½ )PQ = (½) RS

PT = RT⇒PQ–PT = SR–RT (Given PQ = RS )⇒ QT= ST.Hence proved

Because it is given that = 2 equal chords of a circleIf think about diameter is equal in circle so, when they intersect the corresponding segment are equal

thanks bhaiji

2^2001+1999/2^2000-1998= 2^4000/2^2=2^4000_/2=2^2000

The least prime number less than 100 is 2 and greatest prime number less than 100 is97.

Therefore,Difference between greatest and least prime number is(97 - 2) = 95

(a) is correct option

Least prime nmbr=2Greatest prime nmbr =97Diffrence=97-2=9t

(a) is right answer because when we subtract the number 97- 2 is equal to 95

Option (a) is the right answer

9x/8 + 1 = 10

9x/8 = 10 - 1

9x/8 = 9

x = (9 × 8)/9

x = 8

9x^2y^2(3z - 24)/27xy(z - 8)

= 9x^2y^2* 3(z - 8)/ 27xy(z - 8)

= 27x^2y^2(z - 8)/ 27xy(z - 8)

= xy ans.

D is the correct answer.

3q^2-2q-8= 0Roots will be 2 and -4/3please like the solution 👍 ✔️

odd =500,even =500=0 is the correct answer

odd=500,even=500=0 is the right answer

Odd=500,even=500 =0 is the correct answer

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1. Dr. rajendra prasad2. pt. jawahar Lal Nehru3. sardar Patel

1) Dr. Rajendra prasad2) Pandit Jawaharlal Nehru3)

1. Dr. Rajendra Prasad2. Pt. Jawahar Lal Nehru3. Sardaar Ballabh Bhai Patel

Least prime factor of a is 3 so a = 3k Least prime factor of b is 7 so b = 7k a + b = 3k + 7k = 10k = 2*5k so least prime factor of a + b is 2.

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x - 1 + 1/x = 6 x + 1/x = 6 + 1 = 7 x*x + 1 = 7x x*x - 7x + 1 = 0 x = (7+√(49-4))/2 or (7-√(49-4))/2 x = 7/2 + √45 /2 or 7/2 - √45 / 2 x = 7/2 + 3√5 /2 or 7/2 - 3√5 /2

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x²+6x+5=0

x=[-6±√(6²-4(1)(5)]/2(1)x=[-6±√(36-20)]/2x=[-6±√16]/2x=[-6±4]/2

x=(-6-4)/2=-10/2=-5 orx=(-6+4)/2=-2/2=-1

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x^2+9^2 = 15^2x^2 = 225-81x= 12

a= 5b = 13c= 8x= -b+-√D/2a= -13+-√49/10= -13+-7/10roots will be -13+7/10-13-7/10

a=5,b=-13,c=8D=b^2-4ac =(-13*-13)-4(5)(8) =169-160 =9x=-b+or-rootD/2a =-(-13)+or-root9/2*5 =13+or-3/10x=13+3/10 or x=13-3/10x=8/5 or x=1

5x^2+13x+8=0; 5x^2+5x + 8x +8=0; 5x( x +1)+8( x + 1)=0; (5x+8)( x+1), 5x =-8; x= -8/5; x= -1

correct answer is x = -1, -8/5

x=8/5 & x=1 are the correct answer of given question.

4x^2 - 4ax + (a^2 - b^2) = 0

=> (4x^2 - 4ax + a^2) - b^2 = 0

=>(2x-a)^2-b^2=0

=>{2x - a - b}{2x - a + b} = 0

=> x = (a+b)/2 , (a-b)/2

ii) is the right answer of the following

ii) is the correct answer

1

2

3

Initial selling price is 18000 and loss % is 20%.

so, selling price = 80% of C.p => C.P = sp/0.8 = 18000/0.8 = 22500.

now actual cost price per show is. 22500/20 = 1125 rs.

again for selling price to be 16200. and having profit of 20%.

the total cost price should be (100+20) % C.P = 16200 => CP = 16200/1.2 =13500

so no. of shows = 13500/1125 =12 pair of shoes.

Let cp of article be 100100(CP)----85(SP) as 15% loss85 units---1701 unit is 170/85=2100 units is 100*2=200CP is 200Gain at 20%200*120/100=240hence new price will be 240

In 1907 the helicopter was invented

the helicopter was invented in 1885+22 ie in 1907

cost of fencing = perimeter of field × cost per meter perimeter =2 (pi)rr is the radius of field 2×(22/7)×r×50=220r=220×7/(2×22×50)r=0.7

(cos A- sin A + 1)/(cos A + sin A - 1). Divide both numerator and the denominator by sinA.the sum becomes

(cot A - 1 + cosec A)/(cot A + 1 -cosec A)

=(cosec A + cot A - 1)/(cotA - cosec A +1)

={cosecA+cotA-(cosec^2 A- cot^2 A)}/Dr where Dr=cotA-cosecA+1

={(cosecA+cotA)-(cosecA+cotA)(cosecA-cotA)}/ Dr.

=[(cosecA+cotA){1-(cosecA-cotA)}]/Dr

={(cosecA+cotA)(1-cosecA+cotA)}/Dr

=(cosecA+cotA)(cotA-cosecA+1)/Dr

=(cosecA+cotA).Dr/Dr

=cosecA+cotA.