f*((2^2001 %2B 2^1999)/(-287032673818563631058208300294420496005579425 – InterviewSolution

1.	f*((2^2001 %2B 2^1999)/(-28703267381856363105820830029442049600557942552217380011941068420644156534809257846416487157912656747961149115974686569336177974021576383285648283904166329634782497286328070000172194787060011217857231747515871561195403865911597090986829256510116588492726249139540599702236157401405827912384041055492583170336042227246114626400594871201978514725233694125107250679176656457630502033059070322940316970829301649748849104531755444964601010539963295812885222358475522980138739445897418009790020489304157645688845106395931503882087196604858013627228818945970656293858882200205710692704491363440546212787257344 %2B 2^2000))
Answer» 2^2001+1999/2^2000-1998= 2^4000/2^2=2^4000_/2=2^2000

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