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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Il. The length of each side of an equilateral triangle of area 18/3 cm 2is( 12 c |
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| 2. |
कम कमला/| dn n ome| 4dn ) ABC and - ADEE 5AB-OF andl /A= [D २८०1 = 2 By 5A%ax%am, curntFcond?f fon 9o pec 55 a4 10 ghow that : el| 4 ABC © 40€FVe I R LR S o |
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Answer» thnzzz Julie needs 1.75m of clothsf for her school dress Julie needs 1.75m of cloth for her school dress . How many dresses can be made for her in 10.5m of cloth? |
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| 3. |
In Fig. 642, if lines pQ and Rs intersect at point T. such thatPRT = 40°1 RPT> 95° |
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| 4. |
(\sqrt{5})^{4 x-4}-5^{2 x-3}=20 |
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| 5. |
Add1)5 4 2 |
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| 6. |
Add the diagonals2 71654 |
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Answer» Left diagonal = [2 5 8]Right diagonal = [ 4 5 6 ]Sum of diagonals = 2+5+8+4+5+6 = 30. |
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| 7. |
2.lf3°.. 1 = 9 and 4, + 2-64, find the value of r- |
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Answer» 3^(x-1) = 93^(x - 1) = 3^2Since they have the same bases, you can equate the exponents.x - 1 = 2x = 3 4^(y+2)= 644^(y + 2) = 4^3y + 2 = 3y = 1 y/x - x/y = 1/3 -3/1 = 1/3 - 3 = -8/3 |
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| 8. |
The perimeter of the ends of a frustum of a cone are 44 cm and 8.4 Π cm. If the depth is 14 cm, then find its volume. |
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Answer» Perimeter of upper end = 44 cm Perimeter of lower end = 8.4 Π cm Height of frustum cone =14 cm Now we have to find the volume of frustum cone Volume of the frustum cone = (1/3)Πh (R²+ r² + R r) 2Π R = 44 2x(22/7)xR = 44 R = 44x(1/2)x(7/22) R = 2x(1/2)x(7) R =7 2Π r =8.4 Π 2xΠxr =8.4 Π r =8.4 Πx(1/2Π) r = 4.2 Volume of the frustum cone = (1/3)x(22/7)x(14)(7²+ 4.2² + 7(4.2))= (44/3)(49+ 29.4+ 17.64) = (44/3)(96.04) = (44)(32.013) = 1408.57 cm³ Volume of the frustum cone = 1408.57 cm³ |
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| 9. |
In Figure 2, DE || BC. Find the length of side AD, given that AE = 18 cm,BD = 72 cm and CE = 5-4 cm.1.8 cmEDA7.2 cm5-4 cm |
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Answer» I don't know how to get free products from shop and I don't know how to get |
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| 10. |
Tick () the correct option.9. The cross-section of a canal is in the form of a trapezium. If the canal top is 10 m wide and theis 6 m wide and the area of cross-section is 72 m2, then the depth of the canal is(a) 10 m(b) 7 m(c) 6 m(d) 9 m |
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Answer» Area of trapezium=(1/2)(sum of parallel sides)*height72cm²=(1/2)*(10+6)*depth144=16*depth9m =depth Option d is correct |
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| 11. |
1. ABC and DEF are to similartriangle ZA= ZF, ZB = ZD,ZC = ZE and AB = 48 cm, AC=52 cm, DE= 45 cm, DF = 72 cm.Find BC + EF? |
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Answer» 108 is the correct answer of the given question |
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| 12. |
() the correct option.9./ Thecross-section of a canal is in the form of a trapezium. If the canal top is 10 m wide and the botomis 6 m wide and the area of cross-section is 72 m2, then the depth of the canal is(a) 10 m(b) 7 m(c) 6 m(d) 9 m |
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| 13. |
UQ. 16. The difference between the outside and insidesurface of a cylindrical metallic pipe 14 cm long is44 cm2. If the pipe is made of 99 cm2 of metal, find AAthe outer and inner radii of the pipe.[Board Term II, 2012 Set-12] |
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| 14. |
is 1 cm, find the whole surface of the prpe.27. The difference between outside and inside surfaces of a cylindrical metallic pipe 14 cmlong is 44 em2. If the pipe is made of 99 cubic metres of metal, find the outer and innerraili of 'he pp |
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Answer» thanks |
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| 15. |
Fon and BPC are semieircies.Firluof the shaded region in Fig. 12.22, whend thn with vertex O of an equilateral triangle Carea of the6 cmAB |
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Answer» please like my answer if you find it useful |
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| 16. |
mean ě 10 obser valeonS is 20 and surn ofns omonj the 10iS 50, then ind meonaf xem ainingnex |
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Answer» the mean of next five observations is 30 |
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| 17. |
\frac{\sin 26^{\circ}}{\sec 64^{\circ}}+\frac{\cos 26^{\circ}}{\csc 64^{\circ}}=1 |
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| 18. |
. fon2.3 |
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| 19. |
Find:(i) 64^1/21, |
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| 20. |
The solution of $x \frac{d y}{d x}+2 y=x^{2} \log x$ is |
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| 21. |
64^(1/2) |
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Answer» its very simple it's answer is 8 |
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| 22. |
Find the unknown variable i(i:5 44 20 |
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| 23. |
1) Add42,,2 |
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Answer» thankyou so much |
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| 24. |
instalments the iHlerel uIn an A.P the first term is 2 and the sum of the first five terms is one fourth of the sum of the nexterms. Show that the 20th term is-112. |
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| 25. |
(9*(64^(1/3) %2B 125^(1/3))^3)^(1/4) |
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Answer» 9 is the correct answer 9 is the correct answer of the given question |
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| 26. |
( 64 ) ^ { 1 / 2 } \times ( 125 ) ^ { 1 / 3 } |
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Answer» squareroot(8×8)×cuberoot(5×5×5)=8×5=40 |
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| 27. |
8^(x %2B 1)=64 |
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| 28. |
Quadrafie equafion firul fon velue of vहक... कु 1-28 कफ शी स्- |
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Answer» For given equationx^2 - 2x (1 + 3k) + 7(3 + 2k) = 0Roots are equal Then,b^2 - 4ac = 0a=1, b = - 2(1+3k)/1, c = 7(3 + 2k) We get,4(1 + 3k)^2 - 4*1*(21 + 14k) = 01 + 9k^2 + 6k - 21 - 14k = 09k^2 - 8k - 20 = 09k^2 - 18k + 10k - 20 = 09k(k - 2) + 10(k - 2) = 0(9k + 10)(k-2) = 0k = - 10/9, 2 |
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| 29. |
-1/64 %2B 2*6 |
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Answer» 12-1/64 is the correct answer of the given question 11.984375 is correct answer 11.984375 is the correct answer |
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| 30. |
a4 =+ ’\"Qn o 3Fon T T TR | —jen R TNटेक: थे ज रे ७8 : |
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| 31. |
-3*x^2 %2B x^4 %2B x^3 %2B 2/x - 1 |
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Answer» f(x)=x^4+x³-3x²+2g(x)=x-1Here x-1=0x=1Thus f(1)=(1)^4+(1)³-3(1)²+2=1+1-3+2=1Thus remainder=1 |
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| 32. |
3*x %2B x^2 %2B x^5 - 4*x^3 %2B 1 |
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Answer» When p(x) = x^5 - 4x^3 + x^2 + 3x + 1 divided by g(x) = x^3 - 3x + 1 We get, quotient = x^2 - 1 and remainder = 2. Therefore, g(x) is not a factor of p(x) |
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| 33. |
(a) Construct 3 equations starting with.x 2b) Construct 3 equations starting withx-2 |
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| 34. |
4.(a) Construct 3 equations starting with r -2(b) Construct 3 equations starting withx--2 |
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Answer» 4. (a) x - 2 = 0 2x = 4 2x + 1 = 5 2x + 5 = 9 (b) x + 2 = 0 2x + 4 = 0 2x + 1 = -3 2x + 6 = -2 |
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| 35. |
construct three equation starting with x=-3 |
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| 36. |
Construct two equations having solution |
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Answer» 1) 7x+14=02) 11x+22=0 |
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| 37. |
Construct two equations having solution x=-2. |
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Answer» equations having - 2 as solution are x*x+4x+4 = 0 x*x+2x = 0 |
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| 38. |
1. Construct two equations having solution x =-2. |
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Answer» 1) x+2=02) x + 12 = 103) 5x+10= 0 |
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| 39. |
n and solve them to find unknown number in the following:4 to 8 times a number, you get 60(b)When is subtracted 11 from twice a number, the result is 15 |
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| 40. |
One and a half times a number is 1i of a number is 49x of a number is 18.Solve for the unknown.16 15x 10142x 2xion and solve. |
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Answer» 1/10 of no. is 49x/10=49x=490 1/3 of no is 18x/3=18x=54 16/5x=1/1016/x=1/2x=16x2=32 (y+3)/5=14y+3=70y=67 3/2x + 7/2x=510/2x=5x=1 (x+4)/6=3x+4=18x=14 |
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| 41. |
t up equations and solve them to find the unknownAdd 4 to eight times a number, you get 60 |
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Answer» 8x+4= 60 8x= 60-4 8x = 56 x = 56/8 x= 7 |
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| 42. |
(9*1/sqrt(64))*(64^(1/2) %2B 64^(3/2)) |
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Answer» 585 is correct answer of following question |
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| 43. |
-16 %2B 64^(-1/3)*64^(1/3) |
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| 44. |
-12*x*y %2B x^3 %2B y^3 %2B 64 |
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Answer» ex³ + y³ - 12xy + 64x³ + y³ + 4³-3(4xy) (64 = 4³)(x + y + 4)(x² + y² + 4²- xy - 4y - 4x)x + y = - 4(- 4 + 4) *(x² + y² + 4²- xy - 4y - 4x)0 *(x² + y² + 4²- xy - 4y - 4x) |
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| 45. |
(I) ćżf(x)=8x3 (and) 721 g(x)7x3 finda gof |
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| 46. |
-12*x*y %2B x**3 %2B y**3 %2B 64 |
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Answer» what to do please specify |
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| 47. |
(-7)^0 %2B 32^(1/5) %2B 64^(1/2) |
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Answer» 2+1+811 answer is correct ones |
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| 48. |
721*704213 |
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| 49. |
5.draw a parallelogram,HEAR.HE=5cm and EA = 6 cm <R = 60 |
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Answer» Replace Angle R as 60 |
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| 50. |
p isht triangle, the square of the hotethe sum of the squares of the other two sidesす721+sin2 θ = 3 sin θ cos θORtan θ =-,28,atfe る秫玑倆tan θ e: 13If 1+sin2 θ = 3 sin θ cos θ, then prove that tan θ = 1 or tan θ =-.2 |
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Answer» 1+ + sin²x = 3 sinx cosx(1 + sin²x)² = 9 sin²x cos²x1 + sin⁴x + 2 sin²x = 9 sin²x (1 - sin²x)1 + sin⁴x + 2 sin²x = 9sin²x - 9sin⁴x10sin⁴x - 7sin²x + 1 = 0 sin²x = [ -(-7) ± √((-7)² - 4(10)(1))] / 2(10)sin²x = [ 7 ± √(49 - 40)] / 20sin²x = [ 7 ± 3] / 20sin²x = 1/2 or 1/5 sinx = ±1/√2 or ±1/√5 tanx= sinx/cosx= sinx/√(1 - sin²x) = (±1/√2)/√(1 - 1/2) OR (±1/√5)/√(1 - 1/5)= ±1 OR (±1/√5)/√(4/5)= ±1 OR ±1/2 |
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