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Quadrafie equafion firul fon velue of vहक... कु 1-28 कफ शी स्‍-

Answer»

For given equationx^2 - 2x (1 + 3k) + 7(3 + 2k) = 0Roots are equal

Then,b^2 - 4ac = 0a=1, b = - 2(1+3k)/1, c = 7(3 + 2k)

We get,4(1 + 3k)^2 - 4*1*(21 + 14k) = 01 + 9k^2 + 6k - 21 - 14k = 09k^2 - 8k - 20 = 09k^2 - 18k + 10k - 20 = 09k(k - 2) + 10(k - 2) = 0(9k + 10)(k-2) = 0k = - 10/9, 2


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