Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

11. Prove the identity:1+sin Acos A1 +sin A=2sec Acos A

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2.

Q.7. Explain the concept of online transaction.

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Online transactionis a payment method in which the transfer of fund or money happensonlineover electronic fund transfer.Online transactionprocess (OLTP) is secure and password protected. Three steps involved in theonline transactionare Registration, Placing an order, and, Payment.

It is a method in which the transfer of fund or money happens online over electronic fund transfer

It is a payment method in which the transfer of fund or money happens online over electronic fund transfer

Online transactionis apaymentmethod in which thetransferof fund or money happensonlineover electronic fundtransfer.Online transactionprocess (OLTP) is secure and password protected. Three steps involved in theonline transactionare Registration, Placing an order, and,Payment.

Online transactionis apaymentmethod in which thetransferof fund or money happensonlineover electronic fundtransfer.Online transactionprocess (OLTP) is secure and password protected. Three steps involved in theonline transactionare Registration, Placing an order, and,Payment.

Online transactionis apaymentmethod in which thetransferof fund or money happensonlineover electronic fundtransfer.Online transactionprocess (OLTP) is secure and password protected. Three steps involved in theonline transactionare Registration, Placing an order, and,Payment.

Online transactionis apaymentmethod in which thetransferof fund or money happensonlineover electronic fundtransfer.Online transactionprocess (OLTP) is secure and password protected. Three steps involved in theonline transactionare Registration, Placing an order, and,Payment.

Online transactionis apaymentmethod in which thetransferof fund or money happensonlineover electronic fundtransfer.Online transactionprocess (OLTP) is secure and password protected. Three steps involved in theonline transactionare Registration, Placing an order, and,Payment.

InOnline transaction processing(OLTP),information systemstypically facilitate and manage transaction-oriented applications.

The term "transaction" can have two different meanings, both of which might apply: in the realm of computers ordatabase transactionsit denotes an atomic change of state, whereas in the realm of business or finance, the term typically denotes an exchange of economic entities (as used by, e.g.,Transaction Processing Performance Councilorcommercial transactions.[1]):50OLTP may use transactions of the first type to record transactions of the second.

OLTP has also been used to refer to processing in which the system responds immediately to user requests. Anautomated teller machine(ATM) for a bank is an example of a commercial transaction processing application. Online transaction processing applications have high throughput and are insert- or update-intensive in database management. These applications are used concurrently by hundreds of users. The key goals of OLTP applications are availability, speed, concurrency and recoverability.[2]Reduced paper trails and the faster, more accurate forecast for revenues and expenses are both examples of how OLTP makes things simpler for businesses. However, like many modern online information technology solutions, some systems require offline maintenance, which further affects the cost-benefit analysis of an online transaction processing system.

OLTP is typically contrasted toOLAP(online analytical processing), which is generally characterized by much more complex queries, in a smaller volume, for the purpose of business intelligence or reporting rather than to process transactions. Whereas OLTP systems process all kinds of queries (read, insert, update and delete), OLAP is generally optimized for read only and might not even support other kinds of queries. OLTP also operates differently frombatch processingandgrid computing.[1]:15

OLTP is contrasted to OLEP (online event processing), which is based on distributedevent logsto offer strong consistency in large-scale heterogeneous systems.[3]Whereas OLTP is associated with short atomic transactions, OLEP allows for more flexible distribution patterns and higher scalability, but with increased latency and without guaranteed upper bound to the processing time.

Online Transaction. What it is: Anonline transaction, also known as a PIN-debittransaction, is a password-protected payment method that authorizes a transfer of funds over an electronic funds transfer (EFT)

3.

Find the unknown angle.

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4.

. Find the measure of the unknownangle57°42

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5.

2. Find the unknown lettered angle.ii) A65 6550°70°

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we know that sum of all angles of triangle is 180so, angle x=180-50+70 angle x= 180-120 60so angle x = 60

in any triangle sum is always 180 degreeso 65+65+a= 180 ,a= 50 degree2)x+50+70= 180x= 180-120x=60 degree

6.

find the value of unknown x in triangle ABC if Angel c is 60degree and angle b is 50degree find value of x in angle a

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Sum of angles of a triangle = 180 degreesa+b+c=180==> a=180-(50+60)=> a= 180-110=> a= 70 degrees

7.

SOME NCERI IDFind the value of the unknown interior angle r in the following figures:70115100

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good jop

8.

2. if A+B =90°, then prove thattanA.tanattanA.cotB _ sin2 B = tanAsinA.secBcosž-

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9.

sin A, ssin2 63 + sin2 27°cos 17° + cos 73°sin 25° cos 65° +cos 2(B

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10.

Finding Unknown Angle MaQuiz ActiveWhat is the measure of RMpriedawn to scale

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answer is 27 degrees

11.

Olf cos2 A + cos2 C(A) equilateralsin2 B , then ЛАВС is:(B) right angled(C) isosceles(D) none of these

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Ans: (B) right angled

12.

6. A circle has its centre atZAOB -60°. Find the len7. In each of the followingunknown (lettered) angle24°25°

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13.

1.Find the value of the unknown interior angle x in the following figuresnreIn the2·The1i5min3. If

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14.

3*8/2+9/3*3

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3*4+1=12+1=13 by basic calculation.

15.

tan 20° 43'cot 69° 17

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tanA = cot(90-A). So, tan (20degrees 43') = cot(69degrees 17'). Hence, tan(20degrees 43') / cot(69degrees 17') = cot(69degrees 17') / cot(69degrees 17')= 1.

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16.

150010+ 17509\frac{15 \cot \theta+17 \sin \theta}{8 \tan \theta+16 \sec \theta}uate शक

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cos theta = √ ( 1 - sin^2 theta) =

√ ( 1 - (15/17)^2 )

√ (289 - 225) / 17 =

√64 / 17 =

8/17

cottheta=cos/sin=8/15tan=sin/cos=15/8sec=1/cos=17/8hence in given equation15*8/15+17*15/17/8*15/8+16*17/8=8+15/15+17/2=23/30+17/246/30+17=46/47

17.

The areas of three adjacent faces of a cuboid are a, y and z. Its volume is V, prove that Vxyz.

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18.

24. The areas of three adjacent faces of a cuboidare x, y and z. If the volume is V, prove that

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19.

aied lo he oiginal surtace area.s. The areas of three adjacent faces of a cuboid are x, y and z. Its volume is V, prove that V-

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20.

If the area of three adjacent faces of a cuboidal box are 120sq cm,72 sq cm and 60 sq cm respectively,f Ind the volume of the box?

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Area of 3 faces = (lb + bh + lh)

so, 120 = lb 72 = bh 60 = lh

l²b²h² = 518400so, lbh =√518400 = 720 cm³

Thanks a lot.

21.

(1-cosa)(1+cosa)(1+cot²a)=1

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(

22.

0 (+-2x-3)in)-2X+1)-(-1X+3)(v) (2r-1Xr-3)-(r+5Xx-1)(Vİİ) (x+2),-2x (x2-1)x-312r +1)-+5)(i) r+3r+1-(r-2)

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23.

41. If theareas of three adjacent faces of a cuboid are x, y, z respectivelythen the volume of the cuboid is(a) xyz(b) 2xyz(c) xyz (d) 3/xyz

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24.

the area of three adjacent faces of a cuboid are in the ratio 2 ratio 3 ratio 4 and its volume is 9000 cm cube the smallest size has a length of

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25.

The coordinates of a point are (0, 1) and the ordinate ofanother point is - 3. If the distance between the two points is5, then the abscissa of ancther point.

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26.

Show thatsin2 A cos? B -sin2 A sin2 B sin2 A - cos B.

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sin^(2)Acos^(2)B-cos^(2)Asin^(2)B= sin ^2 A(1- sin ^2 B) - cos^(2)Asin^(2)B= sin ^2 A - sin ^2 A sin ^2 B - cos^(2)Asin^(2)B= sin ^2 A - sin ^2 B(sin ^2 A + cos ^2 A)= sin ^2 A - sin ^2 B

27.

Example 3 The value of sin2 5° +sin2 10°sin290° is+sin2 15° +... +sin2 85(a) 7(b) 822(c) 10(d) 922

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from LHS

sin²5° +sin²10° + sin²15° +.........sin²90°

= (sin²5° + sin²85° )+(sin²10°+sin²80°) +....+(sin²40° +sin²50° )+sin²45° +sin²90°

= [sin²5° +sin²(90°-5°)] +[sin²10°+sin²(90°-10°)]+....+[sin²40° +sin²(90°-40°)] +sin245° +sin²90°

= (sin²5° +cos²5° ) +(sin²10°+cos²10°)+....+(sin²40° +cos²40°)+sin²45°+sin²90°

=1+1+1+1+1+1+1+1+(1/√2)²+1

=9+1/2

=] 9+1/2 =19/2 Answer ...

28.

What is the resistance of ideal voltmeter ? How much work is done in moving a charge of 4 C from a point of220 V to another point of 230 V?

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The internal resistance of an ideal voltmeter is infinity and the internal resistance of an ideal ammeter is zero.Ammeter is connected in series and voltmeter is connected in parallel with the electric appliance.

here we have Q(charge) = 4 coulomb

V(potential difference)= 230V - 220V = 10V

we want work done so by using

W = VQ

W= 4 into 10

W = 40 j

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29.

6. Show that Pt3.-3), 9(-3,-3) and O(O, O) are the vertices of an isoseerangled triangle.

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30.

12. If tan | π + Y | = tan" | 4 + 2 | , thensin x3+ sin2 x1+ 3 sin2 x2+sin x(D) 1+ 2 sin2 x(A) 1(cy

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B

31.

Show that point (- 1 , -2 ) is equidistance from ( 4, -3 ) & ( 6 , -3)

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32.

sin2 55+ sin2 35 is equal to:

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sin^2 55° + sin^2 35°=sin^2 55° + sin^2 (90°-55°)=sin^2 55° + cos^2 55°=1

33.

Prove that:sin Asin AcosecA +cot AcosecA-cot17. The below for

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34.

sin2 63° sin2 27°cos2 17° cos2 73

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35.

se wbe more electronegative? Why?How does the electrontc configuPeriodic Table?ration of an atom relate toits position in the Modern

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It's helpful thank you.... 🤗🙂

36.

3. Evaluatesin2 63째+ sin2 27째cos 17째cos 73째

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sin^2(90°-63°)+sin^2 27°/cos^2(90°-17°)+cos^2 73°cos^2 27°+sin^2 27°/sin^2 73°+cos^2 73°1/1=1

thanks actually I m new here so I can only try this that all

[sin^2(90-63)+sin^2(27)]/[cos^2(90-17)+cos^2(73)]=cos^2(27)+sin^2(27)]/[sin^2(73)+cos^2(73)]=1/1=1 answer

ritu Mohit thakur u r in a Facebook

37.

in its aees.etest side of A ABC?G-(b) 6entao the sho4 35, the ratio ot AD to DC iw 3 te2. he atea okarea of Δ BDC?(4) 19ABC woANSWE(b) 24 em(a) 16 cmi20%ONS (MCOs)Fig. 17.35then its area, isth nf a median of an equilateral triangle is x cm,

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38.

(CosA - SinA + 1)/(CosA + SinA - 1) = CosecA + CotA

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39.

Prove that cosA-sinA+1/cosA+sinA-1=cosecA+cotA

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40.

1Show that 5 €06 = tan 6.sin 6cos

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LHS1/cosA - cosA=(1 - cos^2 A)/cosA= sin^2 A/cosA=(sinA/cosA)sinA=tanA sinA=RHS

41.

ORThe angle of elevation of the top of a vertical tower from a point on the ground is 60°. Fromanother point 10 m vertically above the first, its angle of elevation is 45°. Find the height of thetower.

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42.

The angle of elevation of the top of a vertical tower from a point on the ground is 60. From anotherpoint 10 m vertically above the first, its angle of elevation is 30. Find the height of the tower.

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43.

hodgn te poniThe angle of elevation of the top of a vertical tower from a point on the groundis 609. From another point 10 m vertically above the first, its angle of elevationis 30°. Find the. height of the tower.

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44.

ii π < 28.5. then y2+V2+2cos 40equal:3) 22)-2 sintů1)-2 cosThe value of cos10° cos30, cos50 oos70 is2)3)

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cos10.cos30.cos50.cos70 = 3/16 = cos30.cos10.cos50.cos70 = root(3)/2 × cos10.cos50.cos70 = root(3)/4 × (cos60 + cos40)cos70 = root(3)/8 × 2cos60.cos70 + 2cos40.cos70 = root(3)/8 × (cos70 + cos110 + cos30) = root(3)/8 × (cos70 - cos70 + root(3)/2) = [root(3) × root(3)] / (8×2) = 3/16

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45.

3 6Show thatA=\left( \begin{array}{ll}{3} & {6} \\ {1} & {2}\end{array}\right)is a singular

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when Matrix is singular then determinant is 0here determinant is 3×2 -6×1 = 0

46.

5.A fox and an eagle lived at the top of a cliff of height 6m, whose base was at adistance of 10m from a point A on the ground. The fox descends the cliff and wentstraight to the point A. The eagle flew vertically up to a height x metres and thenflew in a straight line to a point A, the distance taled by each being the same.

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Distance traveled by the fox = distance traveled by the eagle(6+x)^2+ (10)^2= (16 – x)^2on solving we getx = 2.72m.

slove

47.

= 2 cosecA.

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48.

What is the value of (cos267° sin223o)?

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cos²67° - sin²23°

cos²67° - sin²(90° - 67°)

cos²(67°) - cos²(67°)

0

49.

19.If tan A = 2, evaluate : sec A sin A + tanA_ cosecA:

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tanA=2, cotA=1/21+(cotA)^2=(cosecA)^21+1/4=(cosecA)^2(5/4)^(1/2)=cosecAcosecA=√5/2tanA+(tanA)^2-cosecA2+4-√5/26-√5/2

50.

४ 4 सिद्ध करें कि : 2 011 = cosecA + cot A.! & COSA +sinA —1

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(cosA-sinA+1)/(cosA+sinA-1) = cosecA+cotA

L. H. S =

Diving by sinA in numerator, we get

(cotA-1+cosecA)/(cotA+1-cosecA)

cotA+cosecA-1 / (cotA-cosecA+1)

cotA+cosecA-(cosec²A-cot²A)/(cotA-cosecA+1)

cotA+cosecA-[(cosecA+cotA)(cosecA-cotA)] / (cotA-cosecA+1)

Taking common cosecA+cotA in numerator, we get

cosecA+cotA [(1-cosecA +cotA)] /(cotA-cosecA+1)

cosecA+cotA [(1-cosecA+cotA)] /(1-cosecA+cotA)

Hence, (1-cosecA+cotA) will be canceled in numerator and denomination and Answer will be cosecA +cotA.