1.

3. Evaluatesin2 63째+ sin2 27째cos 17째cos 73째

Answer»

sin^2(90°-63°)+sin^2 27°/cos^2(90°-17°)+cos^2 73°cos^2 27°+sin^2 27°/sin^2 73°+cos^2 73°1/1=1

thanks actually I m new here so I can only try this that all

[sin^2(90-63)+sin^2(27)]/[cos^2(90-17)+cos^2(73)]=cos^2(27)+sin^2(27)]/[sin^2(73)+cos^2(73)]=1/1=1 answer

ritu Mohit thakur u r in a Facebook



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