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8 less from 22 is 1422-8=14

14 is the answer of your question

Here, AB is the flag staff, C is the end point of the shadow when the angle of elevation is 60°, andθis the angle at which we need to find.

Let AB =x, BC =y

By given condition, BD = 3y

In rightΔABC,ABBC= tan 60⁰xy=3x = √3 yIn right ΔABD,ABBD=tanθx3y=tanθ3y3y=tanθ1/√3=tanθθ = 30° [tan 30° =1/√3]Thus, the required angle is 30°.

x²+7x+10=0=> x² +5x+2x+10=0=> X(X+5)+2(X+5)=0=> (X+5)(X+2)=0=> X = -2, -5.

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X²+7x+10=0

x²+2x+5x+10=0

x(x+2)+5(x+2)=0

(x+2)(x+5) = 0

x+2 = 0 ; x = -2

x+5 = 0 ; x = -5

Relationship between the zeroes and coefficients :-

Sum of zeroes = -2+(-5) = -2-5 = -7/1 = -x coefficient /x² coefficient

Product of zeroes = (-2)(-5) = 10/1 = constant/x² coefficient

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2x² - 7x - 15

2x² - 10x + 3x - 15

2x ( x - 5) + 3 ( x - 5)

(2x + 3) ( x - 5)

Both sides of this equation is same

7x+8-7=107x+1=107x=9X=9/7

3x + 7x =10 10x=10 x=10/10 x=1your answer is 1

3x+7x=1010x=10x=10/10=1

x=1 is your right answer.

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x + 4y = 14 7x - 3y = 5 3x + 12y + 28x - 12y = 42 + 20 31x = 62 x = 2 2 + 4y = 14 4y = 12 y = 3

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4x + 3y = 10 ....(1)

7x + 2y = 11 ....(2)

2× Eq(1) - 3 × Eq(2)

8x + 6y = 20

21x + 6y = 33

8x - 21x = 20 - 33

- 13x = -13

x = 1

So, 3y = 10 - 4x = 10 - 4

3y = 6

y = 2

Given, A is a single digit number. if A = 1 then, A³ = 1³ = 1 , here you can see unit digit of A and A³ are same. if we take A = 2 then, A³ = 2³ = 8 , unit digits are not same.if we take A = 3 => A³ = 27 ( × )if we take A = 4 => A³ = 64 ( ✓ )if we take A = 5 => A³ = 125 (✓)if we take A = 6 => A³ = 216 (✓) if we take A = 7 => A³ = 343 ( × )if we take A = 8 => A³ = 512 ( × )if we take A = 9 => A³ = 729( ✓)

hence, there are five possible solution where unit digits of A and A³ are same. so, x = 5

again, if we take A = 1 => A² = 1 and A³ = 1 (✓)if we take A = 2 => A² = 4 and A³ = 8 ( × )if we take A = 3 => A² = 9 and A³ = 27 ( × )if we take A = 4 => A² = 16 and A³ = 64 ( × )if we take A = 5 => A² = 25 and A³ = 125( ✓ )if we take A = 6 => A² = 36 and A³ = 216 ( ✓)if we take A = 7 => A² = 49 and A³ = 343 ( × )if we take A = 8 => A² = 64 and A³ = 512 ( × )if we take A = 9 => A² = 81 and A³ = 729 ( × )here we can see , there are three possible solution where unit digits of A² and A³ are same. so, y = 3

hence, x - y = 5 - 3 = 2

let x=2ay=3a 2a+3a=180(linear pair)5a=180a=180/5=36x=2a=2*36=72y=3a=3*36=108

Solution:-It is given that PS/SQ = PT/TRSo, ST II QR (According to B.P.T)Therefore,∠ PST =∠ PQR (Corresponding angles)Also it isgiven that ∠PST = ∠PRQSo,∠ PRQ = ∠PQRTherefore, PQ = PR ( sides opposite the equal angles)So,Δ PQR is an isosceles triangle.Hence proved.

eethna late

The answer of this question is XYZ.As per my information

PR=24cm tanQ=24/7tanR=7/2424/7-7/24527/168

2x² - 7x = 0

x ( 2x - 7) = 0

So, x = 0 and 7/2

X²+7x+10=0

x²+2x+5x+10=0

x(x+2)+5(x+2)=0

(x+2)(x+5) = 0

x+2 = 0 ; x = -2

x+5 = 0 ; x = -5

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i) 3x-4y+7=0, kx+3y-5=0; 3(3x-4y+7)=9x-12y+21; 4(kx+3y-5)=4kx+12y-20; 9x+4kx=20+21; 9x(1+4k)=41;