1.

Find the value of ‘k’ for which the following pair of equations has no solution: (𝑖) 3𝑥 − 4𝑦 + 7 = 0; 𝑘𝑥 + 3𝑦 − 5 = 0 (ii)(3𝑘 + 1)𝑥 + 3𝑦 − 2 = 0; (𝑘2 + 1)𝑥 + (𝑘 − 2)𝑦 − 5 = 0 [ans: k=-9/4, k≠10,k=-1]

Answer»

i) 3x-4y+7=0, kx+3y-5=0; 3(3x-4y+7)=9x-12y+21; 4(kx+3y-5)=4kx+12y-20; 9x+4kx=20+21; 9x(1+4k)=41;



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