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Since the axis of parabola isyaxisSo, let the equation of parabola bex2= 4ayalso R is the mid point of PQRQ=PQ/2 =6m =600 cmand OR = 3 cm∴ Coordinates of Q are (600, 3)⇒ (600)2= 4a× 3⇒a= 30000⇒x2= 4 × 30000y= 120000yLet the deflection is 1 cm of a distancexcm from the vertex i.e. origin (0, 0)∴ BC = AC – AB = 3 – 1 = 2 cmNow B (x, 2) lies on the parabola⇒x2= 120000 × 2 = 240000x= 200 root 6 cm = 2 root 6 cmHence, the deflection is 1cm at a distance of 2 root 6 m from the centre

For this first find distanceHenceDistance=speed*timeDistance=80/60*45=60km..as 1hr=60minshenceIf speed increased by 10km/hr that is 90km/hrHence,Time=Distance /speed=60/90=0.66hr

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Meaning of grade

(I) 9 (iii) 0(v) -3(vii) 15

(i) 9(iii) 0(v) -3(vii) 15(ix) -11

(i)9(iii)0(v)-3(vii)15(ix)-11

1= 92=03=-34=155=-11

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the solubility is simple as -6 is greater so solution will be negative which is -3

(1) 9(3) 0(5) -3(7) 15(9) -11is a correct answer

sir answer the first question I have posted

Given: The largest sphere is curved out of a cube of 7cm.

∴The length of the side of square= diameter of square ∴d=7cm =>r=7/2cmWe know that, volume of sphere= 4/3r³ = 4/3 x 22/7 x (7/2)³ = 4/3 x 22/7 x 7/2 x 7/2 x 7/2 = 4/3 x 22 x 1/2 x 7/2 x 7/2 = 2/3 x 22 x 7 x 7/2 = 2/3 x 22 x 7 x 7 = 2/3 x 22 x 49 = 2/3 x1078 = 2156/3 = 718.66cm^3 ∴ Volume of sphere = 718.67cm³

3:12:34

6y^2+17y+12=6y^2+9y+8y+12=3y(2y+3)+4(2y+3)=(2y+3)(3y+4); y=4/3, -3/2

Perimeter of square=4*side

Side=(1/2)*3=3/2m

Perimeter=4*(3/2)=6m

Given there are 9 suare slabs each with side of 1/2 m. The arrangement so formed is a square.Now side of a square = 3*side of square slab.So perimeter of the arrangement (square) = 4*(3*side of square slab) = 4*3*1/2 = 12/2 =6m

let total Distance = x km.3/5 distance still remains to cover =3x/5 kmhe covers the distance = x-3x/5 = 2x/5 km

A/Q2x/5 = 252x = 25*5 =125x = 125/2

Hence, the total Distance = 125/2 km ANS..



1

Secondary SchoolMath5 points

Rajesh can walk at 5 M per second on cycle at 20 metre per second. it takes 45 second to cover a distance of 600 M using a combination of two Modes of transport. how long did Rajesh cycle

Ask for detailsFollowReportbyDivyansh199919.06.2018

Answers



shivamdalmiaAmbitious

Speed he has of walking = 5 m/s

Let time taken on walking be pSpeed she has on cycle = 20 m/s

Let time taken on cycle be qSo, we have following equations

5p + 20q = 600p + q = 45So, p = 45 - qPutting this in 1st equation, we get5(45 - q) + 20q = 600225 - 5q + 20q = 60015q = 600 - 225q = 375/15q = 25Andp = 20Therefore, he cycled for 25 secs, and walked for 20 secs.

Total surface area=6(side)^2 =6×(64)^2 cm^2 =24576 cm^2

inverse=determinant of matrix × adjoint of matrix

determinant=2(12-1)-(-1)(4-1)+3(1-3)=2(11)+1(3)+3(-2)=22+3-6=19adj=11. 3. -2 -7. 5. 3 -10. -1. 7

inverse=19(adj) =209. 57. -38 -133. 95. 57 -190. -19. 133

changed row to column.

In telecommunications, trunking is a method for a system to provide network access to many clients by sharing a set of lines or frequencies instead of providing them individually. This is analogous to the structure of a tree with one trunk and many branches.

a' + a'b = a'( 1+ b) ..... Taking a' common= a'(1) ......... [1+ b = 1]= a'

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2

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Hence, the mean heart beats per minute for women is 75.9.

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The first law is product rule: logₐ xy = logₐ x + logₐ y

Step 1:

Let m = logaₐ x and n = logₐ y

Step 2: Write in exponent form

x = a^m and y = a^n

Step 3: Multiply x and y

x • y = a^m • a^n = a^(m+n)

Step 4: Take log a of both sides and evaluate

logₐ xy = logₐ am+nlogₐ xy = (m + n) logₐ alogₐ xy = m + nlogₐ xy = logₐ x + logₐ y

Tan q

(1).log21 = 0(2).log22 = 1(3).log24 = 2(4).log28 = 3

log2 1=0log2 2= 1log2 4=2log2 8 =3

log2 1=0log2 2=1log2 4=2log2 8=3

The first law is product rule: logₐ xy = logₐ x + logₐ y

Step 1:

Let m = logaₐ x and n = logₐ y

Step 2: Write in exponent form

x = a^m and y = a^n

Step 3: Multiply x and y

x • y = a^m • a^n = a^(m+n)

Step 4: Take log a of both sides and evaluate

logₐ xy = logₐ am+nlogₐ xy = (m + n) logₐ alogₐ xy = m + nlogₐ xy = logₐ x + logₐ y

y = x^4

dy/dx = 4x^3

d^2y/dx^2 = 12 x^2

d^3/ dx^3 = 24x

187500 is the right answer

3x-y=3 -----(1)

9x-3y=9------(2)

x= 3+y / 3

9 ( 3+y / 3) = 9

27+9y /3 = 9

27 +9y = 9*3

9y = 27-27

9y =0

y=0/9

y=0

(put value of y in 1st equation)

3x-y=3

3x-0=3

3x=3

x=3/3

x = 1

(1,0)

therefore, value of x and y by substitution method is 1 and 0

3x-y=3; 9x-3y=9; 3(3x-y=3) 9x-3y=9, 9x-3y=9/3y+3y=18, 6y=18; y=18/6=9/3 =3; 3x-y=3; 3x=3+3=6; x=6/3=2

X= 1 ,Y= 0 is the correct answer of the given question

x=1 AND y=0 hope you like it