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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
An electric pole is 10 m high. A steel wire tied to top of the pole is affixed at a point in groundto keep the pole up right. If the wire makes an angle of 45° with thendthrough the foot of the pole, find the length of the wire. |
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| 2. |
An electric pole is 10 m high. A steel wire tied to top of the pole is affixed at a point on theground to keep the pole up right. If the wire makes an angle of 45e with the horizonitalthrough the foot of the pole, find the length of the wire. |
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| 3. |
5)State and prove "Pythagoras theorem". |
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| 4. |
tIf . lof an estate be worthvalue of half of the estate.1680, find the |
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| 5. |
Divide 880 between Rajan and Kamal in the ratio 1/5:1/6Divide 5600 between A, B and C in the ratio 1:3:4.8.16 to mak |
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Answer» Rajan:Kamal=1/5:1/6=6:5Rajan=6*880/11=480Kamal=5*880/11=400 A:B:C=1:3:4A=1*5600/8=700B=3*5600/8=2100C=4*5600/8=2800 |
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| 6. |
q 1.50页爫1witapCHH弗 Fy 2西.君Tǐ fe灰ㄒ-h嗬ft aR0浒四ere |
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| 7. |
If $x \in N,$ then solve following equations:\frac{1}{6 !}+\frac{1}{7 !}=\frac{x}{8 !} |
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Answer» 1/6! + 1/(7×6!) = x/(8×7×6!) 1/6! (1+1/7)= x/(8×7×6!) 8/7 = x/56 so x=(56×8)/7 = 64 |
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| 8. |
If 2 tan A+cot A = tan B then cot A+2tan(A- B) =A)-1B) 0C) 1D) 1/2 |
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Answer» 2TanA+CotA=TanBwe will substitute this value of TanB while solving the answer.CotA + 2Tan(A-B)= CotA + 2 [ (TanA-TanB)/ (1+TanATanB)]= CotA+ 2 [(TanA-2TanA-CotA)/ (1+TanA(2Tan+CotA))]= CotA + 2 [(-TanA-CotA)/(1+2Tan2A+1)]= CotA + 2 [(-TanA-CotA)/(2+2Tan2A)]=CotA+ [(-TanA-CotA)/(1+Tan2A)]= CotA+ [(-TanA-CotA)/(Sec2A)]= CotA - TanA/Sec2A - CotA/Sec2A = CotA - SinACosA - CotACos2A= CotA(1-Cos2A) - SinACosA= CotA(Sin2A) - SinACosA= SinACosA - SinACosA= 0therefore CotA + 2Tan(A-B) = 0 |
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| 9. |
sino-19, If eos0-, find the value of mytang2tan 0 |
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| 10. |
(11) 2tan 2 45cos230°-sin60°200 |
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Answer» Like if you find it useful |
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| 11. |
The Sum a two number is 60 andotheir emotions 7:5, Find the number |
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| 12. |
/23sinÂŽ + 4 cos 0i Evaluate _â0 sin 6 + cos O |
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Answer» Thanks😊 |
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| 13. |
43If sin 0 = and cos 0 = then tan =5543(A)(B)3412(C)CS Scanne25ith CamScanner(D) can not be calculated |
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Answer» D. can not be calculated 4/3. answerbzbzbzzbzbb the right answer is 4/3 12 /25 bsshxjxucb right answer option . A tan ¤ = 4/3 the answer is 4/3of this question the right option is {A} if sin 12_ 25 hai option a is correct i.e. 4/3 option a is correct i.e 4/3 4/3 is correct answer in this question 4/5 is the right answer d ddddddddddddddddddddddd c....12/25 is my answers 4/3 is the right answer then tan Q=4/3 ans the right answer in question c correct answer 5 guna5 =25../4guna 3 =12 b 3/4 hai utar ayega iska tan=sin/costan=4/5/3/5 =4/3 A. 4/3 is a correct answer tan=4/3 right option A as tan=sin/cos.........so the answer will be sin/cos, i.e., 4/3 the correct option is A tan..=sin.. /cos.. (tan.. =4/5/3/5 =4/5x5/3 =20/15 =4/3 right answer the right answer is (C) (A). 4/3 is the answer because tan thita= sin thita/cos thita this question ans is 4/3 (A) is the answer of your question this question answer of 4/3 Options (A) 4/3 is correct answer 4/3 is right answer 💯👈💯 if sinx equal to 4/5 and cosx equal to 3/5 then tanx equal to 4/3 tan=4/3 is correct answer in this question tan°=sin°\cos°tan°=4/5/3/5tan°=4/3 4/5/3/5=4/3. answer is 4/3 option a is correct because tan0=sin0/cos0 the answer is A this question c answer dhik hai dost (A)4/3= sin/cos=tan, 4/3...A is the correct answer 4/3 that is opposite side to teta in sin teta and adjacent side to teta in cos teta tanA=4\3 is that trru correct answer b hai (a) answer is right 4/5 answer sahi hai iska your questions answer is 4/3 aapka answer hona chhahiye option no. A b part is the right answer The correct ans. is option A The correct answer would be tan∅=. 4/3 ans is A is the right answer it is wrong please comment and right please like 4/3 is the answer of this question A Is a wright answer p=4b=3h=5tanQ=p/b=4/3 and(A) the right answer is B 3/4 c tan®=sin®\cos®tan®=(4/5)/(3/5)tan®=(4×5)\(3×5)tan®=4/3 answer (A) 4/3 is the correct answer answer should be 4 by 3 answer: This answer is (a) |
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| 14. |
- 4 sin2 (A+B4. Prove the following(i) cos 35°+cos 85° +cos 155° 0 |
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Answer» Cos 35°+cos85°+cos155°= 2cos{(35°+85°)/2} cos{(35°-85°)/2}+cos(180°-25°)[cosC+cosD=2cos{(C+D)/2}cos{(C-D)/2}]=2cos(120°/2)cos(50°/2)+cos{(90°×2)-25°}=2cos60°cos25°+(-cos25°)=2×(1/2)cos25°-cos25°=0 (Proved) |
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| 15. |
The initial solution of a transportation problemcan be obtained by applying any known method.However, the only condition is that- |
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Answer» The only condition is that the rim conditions are satisfied. |
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| 16. |
If x E N, then solve following equations:\frac{(2 x+3) !(x-1) !}{(x+1) !(2 x+1) !}=7 |
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| 17. |
शा हि o farto of %OL.{;‘Od&naffl/\&&o कसa8 किट, उम्र: ८ हि 2? |
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Answer» x-2 is a factor of the polynomial, which means that X = 2.3x³ - 2x² +Kx -6 = 0=> 3(2³)-2(2²)+k(2)-6 = 0=> 3(8)-2(4)+2k-6=0=> 24-8-6+2k = 0=> 2k = -10=> k = -5 Please hit the like button |
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| 18. |
EXERCISE 10-1Find the perimeter of each |
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Answer» perimeter of triangle =side+side+side perimeter of triangle=10cm+10cm+9cmperimeter of triangle=29cm |
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| 19. |
EXERCISE 10 AFind the perimeter of the following figures.3.2 mĺ¤çŽ24m2.4 m8 m |
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| 20. |
EXERCIsE 4.3e te Rollow ing equations7() + 28 10(b) 5t + 281010 |
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| 21. |
0. Divide (at-b) by a - b and find the quotdient andremainder |
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| 22. |
IV. Solve the following problems and express the ansuin their simplest form.1) The total population of Bandipur village is 5,400.out of them 900 are illiterate. Then find outi)ŃĐ°the ratio of the total population to the numberilliterates.i) the ratio of the number of literates to number dilliterates. |
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Answer» Total population of village = 5400Total number of illiterates = 900Total number of literates = 5400 - 900 = 4500 1) ratio of total population to the number of illiterates = 5400/900 = 6/1 or 6:1 2) ratio of number of literates to number of illiterates = 4500/900 = 5/1 or 5:1 |
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| 23. |
Long Answer Type Questions. A cylindrical jar of radius 6 cm contains oil. Iron spheres each of radius 1.5 cm are immersed ine oil. How many spheres are necessary to raise the level of the oil by two cm2.dinmerer, has the same volume as a sphere of radius 4 cm |
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Answer» thanks |
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| 24. |
of the total population of a village arechildren. - of the remaining are women andthe rest are men. If there are 90 men in thevillage, calculate(i) total population(ii) number of children(iii) number of women |
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Answer» 1.total population. answer |
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| 25. |
0] | hisjie BUS Elle 1 (40TX20T) DS टेकपुन 12 [nilbla G + X (4 +B) + X = ( + X)(8 + X) QT kSl |
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| 26. |
If 27x+1 = 9x+3-31 , then find ě¤ . |
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| 27. |
In a city, there are 296726 men: 177569men and 371050 children, Find the totalpopulation of the city. |
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Answer» total population=men+women+children =296726+177569+371050 =845,345 |
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| 28. |
\int \frac { 4 + 5 \sin x } { \cos ^ { 2 } x } d x |
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| 29. |
37. Product of the roots of 7x2-9x +33A)B)C)D)1 |
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| 30. |
3. If 36 men can do a piece of work in 25 days, in how many days will 15 men do theme work? |
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| 31. |
SOLVED EXAMPLESE11. 36 men can finish a piece of work in 25 days, how many days will 15 men tto do it? |
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| 32. |
In the given figure, a circle is inscribed in a quadrilateral ABCD in which 4B 90° If ADDS 5 cm. find the radius (r) of the circle.23 cm.AB29 cm and |
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Answer» thanks buddy |
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| 33. |
1. Divide0) 3x3 by 2 |
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Answer» Please hit the like button if this helped you |
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| 34. |
Exercise 10.41. Divide:(0) -39pg25 by -24p(i)-S4213 by 24 |
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Answer» 1) - 39pq^2r^5/-24p^3q^3r = 3/8 p^(1-3)q^(2-3)r^(5-1) = 3/8p^-2q^-1r^4 2) - 3/4a^2b^3/ 6/7a^3b^2 = - 7/8a^(2-3)b^(3-2) = - 7/8a^-1b |
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| 35. |
Divide:(0) - bycoln |
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Answer» 5/6 is right bro 5/6 is the correct answer of the given question |
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| 36. |
In figure, a circle is inscribed in a quadrilateralABCD in which < B = 90°. If AD = 23 cm,AB 29 cm and DS 5 cm, find the radiusr' of the circle.12, |
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| 37. |
ON-CIn figure, a circle is inscribed in a quadrilateralABCD in which ZB 90°. If AD 23 cm, AB= 29 cm and DS = 5 cm, find the radius ‘r' ofthe circle.23.2 |
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| 38. |
â ot STo e oy9 âŹ08 o - LOS |
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| 39. |
ds4 5 sin x |
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Answer» thanks |
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| 40. |
ठ1. (3x-7)(2x-7) |
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Answer» If you find this solution helpful, Please give it a 👍 |
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| 41. |
(2x + 7)²-56x = (2x-7)² |
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| 42. |
9x-(3 + 4x) 62x (7-5x) 7 |
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Answer» (9x-3-4x)/(2x-7+5x)=6/7(5x-3)/(7x-7)=6/77(5x-3)=6(7x-7)35x-21=42x-4221=7xx=3The value of x is 3. |
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| 43. |
If 10 men can finish a work in 30 days, in how many days 15 men can finishthe same work ? |
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Answer» 10 men can finish a work in 30 days so 15 men can finish a work in (10*30)/15=20 days |
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| 44. |
25. In a lown, there are 3450 men and 3020 women. The deorease in the number of men is 10%, whilethe increase in the number of women is 5%. What is the total population of the town? [ Ans: 62761 |
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| 45. |
2. 15 men do a work in 25 days. In how many days the 20 men will complete thesame work.(a) 18(b)18(c) 15(d) 164 |
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Answer» 15 men can do a work in 25 daystotal men x work= 25*15= 375 now suppose they will complete in x daysso x*20= 375x= 18.75 days |
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| 46. |
2. If 15 men can complete a piece of work in 30days, in how many days will 18 men completeit ? |
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Answer» 15 men take 30 days to complete a piece of work. 1 man takes (15 x 30) days = 450 days. 18 men take (450 / 18) = 25 days to complete the same piece of work. 18 men take 26 days to complete work |
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| 47. |
60. IfA1 0(al + ßA)2, then the values of αand β are given by-1(a) α75 ,β42(b) α42,p-42 |
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Answer» Answer will be C |
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| 48. |
P 42+42+ /42+v42+....o, then P- |
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| 49. |
कस न जद) जा (व — 42)° + (42 — उप्पकी |
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Answer» Here, (2x - 3y) + (3y - 4z) + ( 4z - 2x) = 0 If a + b + c = 0, then a³ + b³ + c³ = 3abc (2x - 3y)³ + (3y - 4z)³ + ( 4z - 2x)³ = 3(2x - 3y)(3y - 4z)( 4z - 2x) |
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| 50. |
1 a b+c|=011 b c+a1 ¢ ath |
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