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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Two equai circles intersect in P andQ. A straight line through P meetsthe circles in A and B. Prove thatQA = QB. |
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| 2. |
A circular flower bed is surrounded by a path of 4m wide. The diameter of thflower bed is 66m. Find the area of the path. Show your work with a figure.. |
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Answer» thankssss |
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| 3. |
eb)x + (am Sab 1२०९) eD |
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Answer» Answer. Consider, 9x²-9(a+b)x+(2a²+5ab+2b2)=09x²- 9(a + b)x + (2a²+ 4ab + ab + 2b2) = 09x²- 9(a + b)x + [2a(a + 2b) + b(a + 2b)] = 09x²- 9(a + b)x + [(a + 2b)(2a + b)] = 09x²– 3[(a + 2b) + (2a + b)]x + [(a + 2b)(2a + b)] = 09x²– 3(a + 2b)x - 3(2a + b)x + [(a + 2b)(2a + b)] = 03x[3x – (a + 2b)] - (2a + b)[3x + (a – 2b)] = 0[3x – (a + 2b)][3x - (2a + b)] = 0[3x – (a + 2b)] = 0 or [3x - (2a + b)] = 03x = (a + 2b) or 3x = (2a + b)x = (a + 2b)/3 or x = (2a + b)/3 |
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| 4. |
R T ममD= (०१४) =3 MQ«Q }sab -l-’lbm) |
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| 5. |
3. Find two consecutive odd numbers whose sum is 136thoco sum is 502 |
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| 6. |
#. 4a* = Sab |
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| 7. |
Subtract the sum of 2a+Sab-band-J-ab +2b froma +4ab+ b |
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| 8. |
Subtract the sum of 2a. Sab-b2 and-3d-ab + 2b: fread + 4ab + ba. |
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| 9. |
49*p^2 - 16 |
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Answer» 49p^2-16p^2=16/49p=4/7 |
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| 10. |
Identify the terms and their factors in the following expressionsby tree diagrams.3x 5ii. 4a -Sab |
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Answer» 3x-5terms=3x,-5factor=3x-5,1 4a²-5abterms=4a²,-5abfactors4a²-5ab=a(4a-5b) by tree diagram 9nly answer ok thanks friends |
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| 11. |
Convert the given fractional numbers toper cents3440 |
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| 12. |
If 600 men dig a 5.5 m wide, 4 m deep and 405 m long canal in half an hour, then howlong a canal will 2500 men, working for 6 hrs, dig if it is 10 m wide and 8 m deep? |
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| 13. |
13. Two equai circles intersect in P andQ. A straight line through P meetsthe circles in A and B. Prove thatQA QB |
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| 14. |
EXERCISE 8.2Convert the given fractional numbers to per cents.401.4 |
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| 15. |
ERCISE 8.2Conert the given fractional numbers to per cents.,a)1/8b)5/4c)3/40d)2/7 |
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| 16. |
How to convert fractional numbers to per cent |
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Answer» To convert fraction into percent we multiply the given fraction by 100. |
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| 17. |
6. Write two fractional numbers whose sum is 1and difference is 0 |
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| 18. |
8) A park is 4.6 miles long and 2.7 miles wide.a. What is the total distance around the park?b. If a racecar drove 50 times around the park, how far will it have90? |
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Answer» a. Total distance= perimeter of the park = 2 (4.6 + 2.7 ) = 2 * 7.3 = 14.6 miles. b. If racer takes 50 rounds he would have traveled = 14.6*50 =730 miles. |
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| 19. |
9. Parul runs twice around a square park with side 50m, whereas Hiten runs thrice arounda rectangular park with length 100 m and breadth 75 m. Who covers less distance? |
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Answer» To find this we need to compare perimetersHenceFor Parulperimeter =4*side=4*50=200mHence in 2 rounds it will be 2*200=400mFor Hiten,perimeter will be 2(l+b)=2(100+75)=2(175)=350mHence for 3 rounds350*3=1050mHence Parul runs less |
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| 20. |
yin an = 4, d=237RS--I4fZT-nat a孤朮 |
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Answer» 4=a+(n-1)d-14=(n/2)(a+4).......(1)4=a+(n-1)2....... (2)on solving eq. 1 and 2a=-8n=7 |
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| 21. |
5. The length and breadth of a rectangular park are in the ratio 5:2. A2.5 m wide path runningaaround the outside the park has an area 305 m2. Find the dimensions of the park. |
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| 22. |
lowing per cents to decim(ii) 12% |
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Answer» 0.12 is the correct answer of ur question 12/100= 6/50= 3/25= 0.12 0.12 is the best answer. o.12 is the best correct answer 0.1 2 is the correct answer of the given question 0.12 is correct answer. 0.12 is the correct answer 0.2 is the correct answer dear friend, percent =12%decimal form = 12 / 100 = .12 or 0 . 12 |
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| 23. |
Convert the following to per cents:12/16(b) 3.5c) 49/50d)2/2(e) 0.05 |
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| 24. |
Write the base and the exponent in each case. Also, write the term in the expanded form(i)3^4(ii) (7x)^2(iii) (5ab)^3(iv) (4y)^5 |
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Answer» Mark the question which we have to answer as we will not able to provide multiple answers. |
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| 25. |
27) A square lawn has a 4m wide path surrounding it. If the area of the path is 236m2, find tluearea of the lawn. |
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| 26. |
10. Prove that AAOD ABOC| Hint. First prove ΔΑ DBΔΙ3CA then AAOD&BOCI3530° |
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Answer» Ao=BO........................(given)angle AOC =angle BOD ........(vertically opposite angle )THUS1) Δ AOC congruent to Δ BOD........... (by SAS congruence test) 2) AC =Bd ............C. P. C. T3) angle OAC =Angle OBD........ C. P. C. T |
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| 27. |
2lawn has a 5 m wide path surrounding it. If the area of the path is 1900 m , find the area of the la |
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| 28. |
14) A plot is som long bom wide. A pathsm wide is to be constructed aroundthe plot. Find the area of the path(OR) |
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Answer» L=50mB=30m the smaller plot l=40mb=20ml*b=area of rectanglearea of path =(L*B)-(l*b)=>(50*30)-(40*20)=>(1500)-(800)m^2=>700m^2 700m 2 is the answer to the question |
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| 29. |
a=5d=3an=50n=? Sn=? |
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| 30. |
LagadCircles44113. In the given figure, AB is a diameter of a circlewith centre O and DOl CB.If ZBCD-1209 calculate(i) ZBAD(ii) ZCBDAlso, show that AAOD is an equilateraltriangle.(ii) LABD(iv) ZADC0120 |
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Answer» thanku so much |
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| 31. |
A square lawn has a 2 m wide path surrounding it. If the area ofthe path is 136 sq.mts. then find the area of the lawn. |
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| 32. |
convert the given fractional number to percents 1/8 |
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Answer» thankyou 😊📝 |
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| 33. |
24, sn484 a tr-3 |
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| 34. |
a=3,d=4,n=10,Sn= |
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Answer» a = 3 d = 4 n = 10 Sn = S10 = 10/2*(2×3+9×4) = 5*(6+36) = 5*42 = 210 |
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| 35. |
L i n+ , T " , T. SN —+o08 «व. =6 3 4 |
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| 36. |
3. In an AP, Sn-n-, what is tn ? |
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| 37. |
In an AP, Sn=n2-3, what is t?. |
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| 38. |
AB and CD are two chords of the circle such that AB=10cm and CD=24cm AB॥CD. The distance between AB and CD is 17cm find the radius of the circle |
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| 39. |
In Fig. PR> Pe ag. PR PQ and PS bisects /QPR. Prove that PSR > APSQ |
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| 40. |
the given figure, PQRS is a quadrilateral with diagonals PR and QS.w that PQ+QR+RS+PS> PR+ Qs. |
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Answer» IPQRS is a quadrilateral in which diagonalPR and QS intersect at aO .to prove - PQ +QR +RS+SP < 2 ( PR + QS )proof - we know that sum of any two side of a triangle is greater than the third side ..'. inΔ PQO , PO+QO>PQ , .......................(i) inΔ SOP SO + PO >PS , .........................(ii) inΔ SOR SO + OR > RS ...........................(iii) inΔ QOR , QO + OR > QR ...........................(iv)on adding eqn. i , ii , iii & iv we get ,PO+QO+SO+PO+SO+OR+QO+OR>PQ+PS+SR+QRalso⇒ 2 ( PO + QO + SO + OR ) > PQ+PS+SR + QR = 2( PR + QS ) >PQ+PS+RS + QR ( proved) .... |
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| 41. |
2. Divide 42 into two parts in such a way thatO Olt poon3. Sum of the digits of a two digit number is 9 and the number itself is equal to twice the sum ofitsdigit. Find the number.ARATION ZONE |
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| 42. |
Find the product of the largest 4-digit number and the smallest 4-digit number. Writethe product in expanded form also. |
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Answer» Largest 4 digit number = 9999Smallest 4 digit number = 1000 Product = 9999 x 1000=> 9999000=> 9000000 + 900000 + 90000 + 9000 |
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| 43. |
lIn the figure, ABCD is a trapezium in which AB DC and its diagonals AC and BD intersectat O. Prove thatArea (AAOD)- Area (ABOC). |
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| 44. |
What per cent of 3.6 kg is 72 g? |
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Answer» 3.6kg=3.6*1000=360gmHencex%of 360gm=72gmx/100*360=72x=72*100/360=20% |
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| 45. |
8. जे5 डीवाबमां 2 भीटर Gous w3 1 भी,udlous euRg] Aaidy 8. Aaad dous 4‘.122 21 yglous 3.6 भीटर 8. A daadalaail Wi g2 प्रति भीडैना ₹ 20 डोव, तोदीवालने धोणवानों णर्य शोधो,. |
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Answer» I don't understand can you translate please |
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| 46. |
1 + 6 + 11 + 16 + \ldots + x = 148 |
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Answer» a=1d=6-1=5n=?Sn=148Sn=n/2[2a+(n-1)d]Sn=n/2[2*1+(n-1)*5]148*2=2n+5n^2-5n5n^2-3n-296=0n=3+-√9+5920/10n=3+-77/10n=3+77/10=80/10=8other value neglected as n cannot be negative |
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| 47. |
EXAMPLE Rasheed got a playing top (lattu as his birthday present, which surprisinglyhad no colour on it. He wanted to cosurmounted by a hemisphere. The entire topcm. Find the area he has to colour. (Take π-22/7)lour it with his crayons. The top is shaped like a coneINCERT] |
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| 48. |
1. A room 9.5 m long and 6 m wic'e is surrounded by 1.23 m wide varandah. calculate thethe cost of cementing the floor of this varandan at rs. 80 per m². |
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| 49. |
and height of a room are Sm, 4ms and 3ms respectively. Find the area ofthe lour waills of the room. |
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Answer» area of 4 wall =2h(l+b) =2(3)(5+4)m^2 = 6×9=54m^2 |
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| 50. |
25-paisa coins is lour timles ulallUl JuDelsed tuly, md20. Five times the price of a pen is R 17 more than three times its price. Find the prlin 231 more than the number of girls. If the total strethe pen. |
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