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eb)x + (am Sab 1२०९) eD |
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Answer» Answer. Consider, 9x²-9(a+b)x+(2a²+5ab+2b2)=09x²- 9(a + b)x + (2a²+ 4ab + ab + 2b2) = 09x²- 9(a + b)x + [2a(a + 2b) + b(a + 2b)] = 09x²- 9(a + b)x + [(a + 2b)(2a + b)] = 09x²– 3[(a + 2b) + (2a + b)]x + [(a + 2b)(2a + b)] = 09x²– 3(a + 2b)x - 3(2a + b)x + [(a + 2b)(2a + b)] = 03x[3x – (a + 2b)] - (2a + b)[3x + (a – 2b)] = 0[3x – (a + 2b)][3x - (2a + b)] = 0[3x – (a + 2b)] = 0 or [3x - (2a + b)] = 03x = (a + 2b) or 3x = (2a + b)x = (a + 2b)/3 or x = (2a + b)/3 |
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