Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

11. If the radius of the circle is 6 cm and the length of an arc is 12 cm. Find the area of the seciot12. The data tera rrling mas obtai

Answer»
2.

की है || \> WO adjoaond — \”é\ ८ g- Crn. N 6Cm (M

Answer»
3.

A shopkeeper allows his customers 10% off on the marked price of goods and still getsa profit of 25%. what is the actual cost to him of an article marked Rs 250?

Answer»
4.

Ashopkeeper allows his customers 10% off on the marked price of goods and still getsa profit of 25%. What is the actual cost to him of an article marked Rs 250?

Answer»
5.

Find the ratio of volumes of cylinder and cone having same base radu and sameheights.

Answer»
6.

(a) 150 crn to 8 m

Answer»
7.

Write the division facts:12 x 5 60

Answer»

here 12 times 5 gives 60that 12 and 5 factor of 60 and 60 is multiple of 12 and 5

8.

Write the tera division facts for .889=72

Answer»

36×2=72, 24×3; 18 x 4; 12x6

12×6=72, 36×2=72,18×3

8*9iysgshzjzjsjxhxhdhhshdhdhdhshshhdhshshs9*8

36×2=72,24×3=72,18×4

36×2=72,24×3=72,18×4

8×9,24×3,12×6 is the factors

9.

8. For a set of 5 true/false questions, no studenthas written all correct answers and no twostudents have given the same sequence ofanswers. What is the maximum number ofstudents in the class for this to be possible?

Answer»

We have formula for nCr = n!/(n-r)!r!

By applying the formula we can deduce the solution like this

5C4+5C3+5C2+5C1+5C0

5!/(5-4)!4! +5!/(5-3)!3! +5!/(5-2)!2! +5!/(5-1)!1! +5!/(5-0)!0!

5 + 10 + 10 + 5 + 1 = 31

tysm

without formula i want

10.

Now I know -all can be filled in each bag.To find the HCF of given numbers, we make a list of the factors of the numbersand find the greatest of the common factors.Practice Set 24Find the HCF of the following numbers.1) 45, 30(2) 16, 48 (3) 39, 25 (4) 49, 56 (5) 120, 1445) 81, 99 (7) 24, 36 (8) 25,75 (9) 48, 54 (10) 150, 225large square beds of equal size are to be made for planting vegetables on a plot of landmetres long and 15 metres wide, what is the maximum possible length of each bed?wo ropes, one 8 metres long and the other 12 metres long are to be cut into piecethe same length. What will the maximum possible length of each piece be ?e number of students of Std 6th and Std 7th who went to visit the Tadoba Tigject at Chandrapur was 140 and 196 respectively. The students of each class aredivided into groups of the same number of students. Each group can have a pnumber of students there can be in each group? V

Answer»

10150,225150]225[1 150 —— 75]150[2 150 —— 00the last divisor is 75. therefore HCF=75

method of listing factors4.49,56the factors of 49 are 1,7 and 49the factors of 56 are 1,2,4,7,8,14 and 56Here the factors which are common are1,7 but the greatest is 7 so HCF=7

1. hcf of 45, 30= 152. hcf of 16 ,48 = 63.hcf of 25,39= 14.hcf of 49,56=75.hcf of 120,144=246. hcf of 81,99=97.hcf of 24,36=128.hcf of 25,75 = 3

1. hcf of 45, 30= 152. hcf of 16 ,48 = 63.hcf of 25,39= 14.hcf of 49,56=75.hcf of 120,144=246. hcf of 81,99=97.hcf of 24,36=128.hcf of 25,75 = 39. hcf of48,54= 610. hcf of 150, 225 = 75

Baby seats in my opinion on on my way home now available on request

45,30-1516,48-1624,36-1281,99-9

11.

4. Sudhir bought an almirah for13600 and spent 400 on its transportation. He sold tt for6800. Find his gain per cent.

Answer»
12.

Thas a01

Answer»
13.

340 for its transportation. Then, he sola4. Manjit bought an iron safe for 12160 and paidit for 12875. Find his gain per cent.

Answer»

375 rs is his profit

total cp=12160+340=rs 12500sp=12875profit=12875-12500=rs375profit%=375*100/12500=3%

profit = 375 rsprofit % = 30 % is the best answer

your gain 375 but in percentage is 3..

3% is the correct answer of the given question

14.

15. Water in a canal, 5.4 m wide and 1.8 m deep, is flowing with a speed of 25 km/hour. How much areacan it irrigale in 10 minutes, if 10 cm of standing water is required for irrigation?ncentric circles with centre O have radu 21 crn and 42 cm. If / AOB = 6(P,

Answer»

B= 5.4 mh=1.8m

v= 25 km/htherefore, l=25km per hourtherefore water that would be flowing in 40 minutes=40*25/60=50/3km=50000/3m

area of irrigation= area water flowing in 40minutesvolume of water which irrigates the land= volume water flowing from canal in 40 minutes

and 10 cm or 1/10 m of standing water is required for irrigationtherefore,l*b*h=L*B*Hl*b*1/10=50000/3*5.4*1.8l*b=300000*5.4l*b=16200000sq. mtherefore, area to be irrigated when 10 cm of standing water is required=16200000sq. m

15.

Eg9114S i Lessthas Lto

Answer»

15 percent of 240=15*240/100=36So, 240-36=204

16.

50०... #पुध-6500 का तQUIS+]| QUIS+ S0+

Answer»

please share your valuable feedbackby liking it

17.

४४० + ।| ४४(poutb)- 368 ५।8)

Answer»

its component will be 9×9 OR 3×3×3×3

convert into minute /second. 58km/hr

correct answer is 9x9=81

18.

9500. 6 पा&QuIs— §s0d® 9

Answer»
19.

RUSHE _ (quey— goas) e} y2 Bquis—

Answer»

1-sinA)/(1+sinA)=(1-sinA)(1-sinA)/(1+sinA)(1-sinA)=(1-sinA)^2/(1-sin^2A)=(1-sinA)^2/cos^2A={(1-sinA)/cosA}^2={(1/cosA)-(sinA/cosA)}^2={secA-tanA}^2

20.

{8503QUIS+T )guey - en‘oas"7 6 पथ + 9295

Answer»
21.

8 What is meant by bond order? How is it related to stability of a molecule?

Answer»

The half difference between the no.of electrons present in bonding molecular and anti-bonding molecular orbital is called bond order

22.

Exercise-9.1t Divike the given shapss as instructed(0) into 3 rectangles(i) into 3 rectangles

Answer»
23.

Convert the following as instructed:(3)42 minutes into seconds

Answer»

1 minute = 60 secondstherefore 42 minutes = 60 x 42 seconds42 minutes = 2520 seconds

24.

Example 17 If the coefficients of (r-5) and (27 - 1) terms in the expansion of(1 + x)" are equal, find r.

Answer»
25.

3. Determine by substitution, itf(a) 5 is the root of x-3-6.

Answer»

Put x = 5

So, LHS = 5 - 3 = 2

RHS = 6

LHS ≠ RHS

So, x = 5 is not a root

26.

- asose quis QuoteTharosa Quist Quotpoup oroidpoutand

Answer»

sir the image is inverted I could not understand please put this question again

I can't understand please put this question again

27.

135 WAP to monitor P215 and mov the valves

Answer»

find the volume of the cube whose side is 4.5 cm

28.

1. Find area of largesttriangle that can beinscribed in a semicircleof radius r unit.Al

Answer»
29.

,U) and radius rExample 1 Find an equation of the circle with centre at (U0)

Answer»
30.

four jacks are missing in a well shuffled pack of 52 cards.a child could find only 2 jacks and reshuffled it back. What is a probability of getting a face card

Answer»

Total outcomes= 50Favourable outcomes = 4Probability of getting a face card = 4/50 = 2/25

31.

A particle is moving with a uniform speedin a circular orbit of radius R in a centralforce inversely proportional to the nthpower of R. If the period of rotation of theparticle is T, then:(1) T R3/2 for any n.(2) T R?+1(3) T R(n+1)/2(4) T Rn/2

Answer»
32.

It is given that < XYZ = 64° and XY is producedto point P. Draw a figure from the giveninformation. If ray YQbisects ZYP, find Z XYQand reflex 2

Answer»
33.

. Navin cycles to his school at an average speed of 12 km/hr. It takes him 20 minuschool. Ifhe wants to reach his school in 15 minutes, what should be his average speed

Answer»

20 min for 12 km/hr15 min for x km/hr20/15×12=xx=16 km/hr

thank u

34.

15.In a race of 600m, A can beat B by 60m and in a race of 500m. B can beat C by 25m by how many metres willA beat C in a 400m race?

Answer»

In the race of 400meters A can beat C by 60 meters.

35.

There are 845 students in a school. On a day of strike, only 169 students were present inthe school. Find the per cent decrease in the students attending in the school due to strike.

Answer»

845-169/845 * 100

= 676/845 * 100

= 0.8*100

= 80%

36.

Itf one zero of thethe value of k14. Iero of thee polynomial 3x -8x-(2k+1) is seven times the other, find both zeroes of the polynomial and

Answer»

hit like if you find it useful

37.

LICसेमी-3.5 सेमी वाला एक घनाभ बनाने के लिए 1-15 सेमी व्यास और05-5 सेमी-10 सेमीके सिक्कों को पिघलाना पड़ेगा

Answer»

hskanavu joqg iwiqvw nwlq kqlqbq qkqk. lqlqbqnqma

38.

long form of lic

Answer»

LIC - Life Insurance corporation.

39.

400 Tet.How thuch mon.11: At a car park, 50% of the vehicles parked were cars, 30% were motorcycles and the rest of the40 vehicles were vans.(0) Calculate the number of motorcycles parked there.(i) If 40 cars left the car park, what percentage of the vehicies parked there were cars.There are 120 boys and 57 girls in a school. If 5% of the boys leave and nowhat percentane of the uhol42nou

Answer»
40.

0 21(on 2092 Find the volume of the culbe, itf one face of the cube has an area of 121 sq, m

Answer»
41.

6) 21ii) 2092. Find the volume of the cube, if one face of the cube has an area of 121 ssq m.

Answer»

One face of cube is sqaure. So area of sqaure is a² where a is sidetherefore a² = 121which gives a = 11therefore area of cube is a³ = 11³= 1331m³

42.

|||८||-37.यदियदि NOTES को STONE कोडित किया जाता है तो STEAL काकोड क्या होगा:(A) SLATE (B) TEALS (C) LETSA (D) LATESRY

Answer»

steal=letsa is the correct answer

steal = letsa is a correct answer

steal - lesta is a correct answer

43.

A cube has a surface area of 600 m. What is the area of one face?

Answer»
44.

What decimal of an hour is a second ?

Answer»

To 6 decimal places:

0.000278

You could do this yourself.

There are 60 seconds in a minute, and 60 minutes in an hour. Therefore 60x60=3600 seconds in an hour.

Then 1 / 3600 = 0.000278.

45.

Q.13Find the zeores of the polynomial 2x2-8x + 6·

Answer»
46.

For the polynomial 2x2-5x + 1-0 find the value of α + β-2αβ

Answer»

Sum of roots=-b/a=-(-5)/2=5/2Product of roots=c/a=1/2Hencea+b-2ab=5/2-2*1/2=5/2-1=3/2

47.

ज्ञात 5त1४०2 "91८ 3DU ,.....

Answer»

Zorn's lemma, also known as the Kuratowski–Zorn lemma, after mathematicians Max Zorn and Kazimierz Kuratowski, is a proposition of set theory that states that a partially ordered set containing upper bounds for every chain (that is, every totally ordered subset) necessarily contains at least one maximal element.

48.

If a and B are the zeroes of the polynomial 2x2 + 3x + 5, then the va+

Answer»

check out mysolution

=3/5 is the correct answer

49.

S farmer per day 6 hour work and in 15 days work finishbut how much hour more Labour he finish work in 10 days ?

Answer»

Farmer finish work in 15 days if work for 6 hoursTotal amount of work done = 15*6

If farmer finish work in 10 days number of hours farmer should work= 15*6/10= 3*3 = 9 hours *

50.

Q2) What is the standard form of 22-81

Answer»

72/-81 here both are multiple of 9...9(8)=72....9(9)=81....so standard form is - 8/9