1.

RUSHE _ (quey— goas) e} y2 Bquis—

Answer»

1-sinA)/(1+sinA)=(1-sinA)(1-sinA)/(1+sinA)(1-sinA)=(1-sinA)^2/(1-sin^2A)=(1-sinA)^2/cos^2A={(1-sinA)/cosA}^2={(1/cosA)-(sinA/cosA)}^2={secA-tanA}^2



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