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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
693x 693×693-383×383×383-2693 × 693 + 693 × 383 + 383 × 383 |
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Answer» solution (×) = (55701638) necha 593 |
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| 2. |
to. If cose. Bethen find the valueatt14142410419 |
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Answer» cosx=p-1/p+1; Tanx=4p/ p+1x Tanx cosx=p-1\+1; tanx=4p/ p+1 cosx=p-1/p+1;Tanx=4p/p+1x tanx |
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| 3. |
Find the values of x, y and z from400110Two adjacent angles of a paralleloIn parallelogram PQRS, find x, y, |
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Answer» since ABCD is a ||gm so x=110°.... (opp. angles of ||gm are equal) in triangle ADC x+y+40°=180° 110°+y+40°=180° y+150°=180° y=30° z=y.... (becoz AB||CD) z=30° |
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| 4. |
) (30 2 gBp+q +p+ ŕ¤ŕ¤Ş p |
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| 5. |
3. What is rotational symmetry? |
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Answer» A shape has rotational symmetry when it still looks the same after some rotation. |
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| 6. |
3. What number comes inside the blank circle?ATT |
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Answer» 250 answer. the correct answer is 250... the answer is 250.... the correct answer is 250 923=14 right answer 250 is the right answet 250right answer good 250 is the answer of question 250 is the answer ...... 250 is the right answer .... 250 is the right answer ..... 250 is the right answer ..... 250 is the right answer...... answer is................................ 9 |
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| 7. |
693 x693x693 - 383x383x383/693 ×693 + 693 ×383 + 383×383 |
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| 8. |
Find the Lem of 693 and 1078 |
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Answer» 77 and 9702 77 and 9702 |
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| 9. |
PUU999 692X 99 is equal to693(a) 99800 (b) 99900 (c) 1(d) 99000 |
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Answer» (1/7) + (692999/693) × 99 = (1/7) + 98999.8515 = 98999.985 =98999.985 CORRECT ANSWER LIKE ME LIKE LIKE LIKE your answer is 98999.985= approximately 99800 so option number a=99800 is the right answer please like the answer of this question is option (d) ...99000 |
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| 10. |
and Anglesfivo adjacent angles on a straight hof both the angles.djacent angles on a straiyght line ave (3given figure it cSh and ah, fvd the values of a and by snd 76 sthe adjoining fiue, POO is a straight e Finl m and n wKii) m7:5Find the value of x if AOB is a straight lineIfa : b : c = 2 : 3 : 4, find a, band c.Find the value of xShow that the bisectors of two adjacent supplemeFind the measure of an angle if five times of its coFind the complement of the angle (150-a+ b)In the given figure, find the measures of ZAOC |
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Answer» Please post a clear image with proper lighting. We cannot provide a solution without a clear image of question. ok |
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| 11. |
(g) 42 ÷(T) 125÷ 25(T) 130 ÷ 13 = |
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Answer» 1)72)53)10is the answer |
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| 12. |
Find the value of x.12513545 |
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Answer» Sum of all the angles inside a quadrilateral is equal to 180 125+135+45+x=360305+x=360x=360-305x=55 |
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| 13. |
Sequence and Series20124. If first, second and n th terms of an AP are a, b and I respecitvely, then show(al) (2and S 2a-b)Lathat n =a-b |
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Answer» where is the answer |
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| 14. |
Ifa parallcio5. In the figure, 'O' is the centre of the circle.OM 3cm and AB 8cm. Find the radius ofthe circle'Q' is the centre of the circle |
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Answer» Answer is 5 . Hit the like if you satisfied with my answer |
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| 15. |
725 \div 7 |
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Answer» 725/7 = 103.57 is the answer |
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| 16. |
बटन ककिभत हि नी49८ दो संख्याओं का म0 स0 145 तथा ल0 स0 2175 है| यदि इनमें से एक संख्या 725 हैकि जलकर 2 T = |
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Answer» म.स. × ल.स. = पेहली सन्ख्या × दूसरी संख्या 145 × 2175 = 725 × x x = 145 × 2175 / 725 = 435 If you find this answer helpful then like it. |
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| 17. |
The HCF of two numbers is 145 and their LCM is 2175. If one number is 725, findthe other number. |
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| 18. |
18. In figure, the value of y and y are50> p/2(a) 130" (b) 150 (c) 160 (d) 135 |
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Answer» x =130°( linear pair of angles )Y=130°( vertically opposite angles or alternate interior angles ) |
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| 19. |
Exercise 1.11. Fill in the blanks using properties of rational numbers.+NI-1000§ 33ūnouviu |
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| 20. |
L~7 o,N No | ol M\f)-~ हितल. ४१८ i कि9 तक S 0 §; | 8 4> A5 । &s LAL= " “ |
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Answer» (0.03125)^-2/5 = (3125/100000)^-2/5 = (100000/3125)^2/5 = [(100000/3125)^1/5]^2 = (10/5)^2 = 2^2 = 4 |
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| 21. |
Find the perimeter of a triangle with sides measuring 10 cm, 14 cm and 15 cm. |
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Answer» The perimeter of a triangle is =10+14+15=39cm |
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| 22. |
\begin{array}{l}{\text { 1. Add the following rational numbers: }} \\ {\text { (i) } \frac{3}{7} \text { and } \frac{-6}{7}} \\ {\text { (iii) } \frac{-8}{13} \text { and } \frac{-4}{13} \text { and } \frac{-6}{11}}\end{array}. |
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| 23. |
If the mean of 6, 8, 9, x and 13 is 10, then the value of x is-(A) 12(Cy 14(B).13(D) 15 |
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| 24. |
If Δ ABC ~ Δ RQP, LA80, L B = 60, then find the value ofP. |
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Answer» As both the Triangles are similar angle C is equals to angle P so angle c=180°-(angle A+angleB)=(180-140)°=40°Therefore angle P is equals to 40° |
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| 25. |
1. () Find the sum to n terms of the sequence la,) where a, 5-6n, n eN. |
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| 26. |
Quadrilateral PLAN \left. \begin{array} { l } { PL = 4 cm } \\ { LA = 6.5 cm } \\ { \angle P = 90 ^ { \circ } } \\ { \angle A = 110 ^ { \circ } } \\ { \angle N = 85 ^ { \circ } } \end{array} \right. |
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| 27. |
AABC is an isosceles triangle in which AB ACSide BA is produced to D such that AD AB(see Fig. 7.34). Show that BCD is a right angle.uio h ZA 90°nlein whic |
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| 28. |
In the adjoining figure, a circle is inscribed in a quadrilateral ABCD inwhich LB = 90°. If AD = 23 cm, AB = 29 cm and DS-5cm, find theradius (r) of the circle.ら |
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| 29. |
1 A quadrilateral has three acute angles eachmeasuring 75 the measure of fourthangle is(a) 145 (b) 135 () 125()130 |
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| 30. |
If cp of an article is 540 rs.and spis 480. Then td loss%or profit |
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Answer» loss % =540-480/480 = 60/480 = 1/8 = 0.125% loss |
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| 31. |
.10 In the given figure ifa -b700 Find the value of a and b:5TD |
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Answer» Given : a - b = 70 ....(2) a and b linear pair a + b = 180 .... (2) Adding (1) and (2), thereby eliminating b 2a = 250 a = 125° b = 180° - 125° = 55° |
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| 32. |
25. From a window 60 m high above the ground of a house in a street, the angleion and depression of the top and the foot of another house on the oppositside of the strect are 60° and 45° respectively. Show that the height of opposithouse is 60(1+ v3) metres. |
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| 33. |
the middle lingre mutually perpendicular lnger points in the direction of magnetthe direction of magneticger points in the direction ofad middle finger pol mbe thumb will point in the direction of 1a fonce acting on the conductors tie finge). theof thee net| ILLUSTRATIVEandFad the magnitude of magnetic induction at aof4cm due to a long straight wire carryingaument of 104. (Ho= 4mx 10" Wb/Am)Data : a = 4cm = 4 ×102 m, 22013-6I = 10A,Ho = 4π × 10-7 Wb/Amlution : B = Hol- |
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Answer» Please hit the like button if this helped you |
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| 34. |
3n a rectangle be called a parallelog.alIn the adjoining figure, I Ilm l nFind La, Zb, 4c and Ld.125 |
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| 35. |
Nitin walks around a circular track of radius 14m with a speed of4 km/hr. if he takes 20 round of the track for how long does he walk? |
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Answer» Circumference of circle = 2*(22/7)*14= 88m. Total distance hr walks = 88*20= 1760m. Time = Distance / Speed = 1760/(4*(18/5))= 1760/ (72/5)= (1760*5)/72= 122.222 seconds PLEASE HIF THE LIKE BUTTON thanku |
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| 36. |
Can a relin the adjoining figure, ! l mI n.ind La, Lb, c and Ld.70259 |
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| 37. |
in uht(A 8 CDdre mid Point of dht sidus A8,GC,LD nAcs a diagonal. Shau ha0,13) POlIS |
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Answer» Given:In quadrilateral ABCD P,Q,R,S are mid point of sides AB,BC,CD and DA respectively T.P: 1 2 3 In triangle ADC, SR is a line segment joining the mid point of DA and DC respectively :. SR||AC ( mid point therom) In triangle BAC PQ is a line segment joining the mid point of BA and BC respectively. PQ||AC (mid point therom) pQ = half of AC From 1 &2 SR=PQ SR ||PQ :. PQRS is a ||gram. Iska answer option 2hoga |
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| 38. |
6813 |
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| 39. |
\begin{array} { c } { \text { Use Mathematical Induction to show that } } \\ { 1 + 2 + 4 + \ldots .2 ^ { n } = 2 ^ { n + 1 } - 1 } \end{array} |
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| 40. |
Similarly, LD> 2B.In theand LD of quadrilateralPLE 7adjoining figure, the bisectors ofa guadrilateral ABCD meet CDand AB produced at P and Q respectivelyProve that2 |
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Answer» InΔPBC we have,angle p +pbc+c=180p+1/2 B+C=180⇒eq 1 InΔqad we have Q+A+ADQ=180Q+A+1/2 D=180⇒eq 2 Adding 1 and 2P+Q+A+C+1/2 B+1/2 A=360 But,A+B+C+D=360P+Q+A+C+1/2(B +D)=A+B+C+D P+Q=1/2 (B+D)P+Q=1/2(ABC+ADC) |
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| 41. |
TD 13 lialotial.s. Find the 20th term from the last term of the AP 3, 8, 13,..3 |
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Answer» Please like the solution 👍 ✔️👍 wrong answe |
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| 42. |
14y-8=13 |
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Answer» 14y - 8 = 1314y = 13 + 814y = 21y = 21/14y = 3/2 thankes 14y -8 = 1314y=13+8=2114y=21 y =21/14= 3/2 |
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| 43. |
Johnny is travelling to a meeting that is 28 miles away. He needs to be there in 30 minutesfast does he need to go to make it to the meeting on time ?(A) 25 mph(B) 37 mph(C) 56 mph(D) 49 mph. |
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Answer» time = 30 minutes = 1/2 hrdistance = 28 milesspeed = distance / time = 28/(1/2) = 28*2 = 56 mph the correct answer is 56mph 56mph is the answer of the given question 56mph is the answer of the given question. the correct answer is 56 mph time=30 minutes =1/2hourdistance=25 milesspeed= distance/time=28/(1/2)=28×2=56 mph the correct answer is 56 mph Speed=56mph is the right answer |
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| 44. |
A helicopter is flying at a height of 500 m. If all ofsudden its engines stops working, the helicopterwill fall on the earth in |
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Answer» So t=√1000/ 10 = 10 secs. |
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| 45. |
Find the area of a square whose diagonal is 542 cmunits |
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| 46. |
(iii)ă12 x2 +7x+5V2 =0 |
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Answer» √2x²+5x+2x+5√2=0X(√2x+5)+√2(√2x+5)=0(X+√2)(√2x+5)=0either (X+√2)=0 or (√2x+5)=0X=-√2,-5/√2 |
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| 47. |
Find the area of a square whose diagonal is 5/2 cm |
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| 48. |
15. Find the area of a square whose diagonal is 52 cm.Hint. Area - Exidiagonal) sq units. |
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Answer» Diagnol of square with side a = a (root2) Side of square = a = ?a(root2)=5(root2)a = 5cm Area of square = a2= (5)square= 25 Area of square = 25 sq cm. |
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| 49. |
| Find the value ofk, for which one root of the quadratic equation kx-14x+8 = 0 is 2.nd the value of k, for which one root of the quadrati2. |
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| 50. |
Show using the principle of mathematical induction that n(n+1)(n+5) is a multiple of 3 . |
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Answer» p(n)=n(n+1)(n+5) p(1)=1(1+1)(1+5)=1x2x6=12 let p(k) b true p(k)=k(k+1)(k+5) on solving =k^3+6k^2+5k=3y( as itsamultiple of 3) k^3=3y-6k^2-5k ------(1) p(k+1)= k+1( k+1+1) k+1+5) =k+1(k+2)k+6) on solving =k^3+9k^2+20k +12 putting value of k^3from (1) =3y-6k^2-5k+9k^2+20k +12 =3y+3k^2+15k +12 3(y+k^25k +4) therefore we can say p(k+1) is a multiple of 3 p(k) is true so p(n) is also true and its a multiple of 3 |
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