1.

(iii)、12 x2 +7x+5V2 =0

Answer»

√2x²+5x+2x+5√2=0X(√2x+5)+√2(√2x+5)=0(X+√2)(√2x+5)=0either (X+√2)=0 or (√2x+5)=0X=-√2,-5/√2



Discussion

No Comment Found