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10 and 90 is the answer of your question

13 nearest ten is = 1086 nearest ten is =80.

2/5=4/10=6/15=8/20=10/25....

9/11 is equivalent to

9/11 × 2/2 = 18/22

9/11 × 3/3 = 27/33

Let the number be xyx+y=9...............(1)(10x+y)+27=10y+x10x-x+y-10y=-279x-9y=-27x-y=-3................(2)add equation 1 and 2we getx=3substitute it in eq 1y=6so the number is 36

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When Iron nail (Fe) kept in Copper sulphate (CuSO4) there takes reaction between them. As Iron is more reactive than Copper it can replace Copper from CuSO4.Fe + CuSO4 → FeSO4 + CuCuSO4 is in blue Colour and FeSO4 is in light green colour.So, there will be change in the composition and colour of the solution (from blue to light green). And decomposition of Copper layer on surface of nail.

-15 11 6 0 27

1/12= 2/24= 3/36=10/120=4/48=5/60=6/72

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thank you!!

9/11 is equivalent to

9/11 × 2/2 = 18/22

9/11 × 3/3 = 27/33

54/78 is the correct answer of the given question

9/13×6/6=54/78 is the right answer of this question

54/78 is the correct answer

54/78 is correct answer.

Here a = c = e = g and b = d = f = h

As a = 80,

a = c = e = g = 80°

b = d = f = h = 180-80

= 100°

First, a fraction is made up of two integers—one on the top, and one on the bottom. The top one is called thenumerator, the bottom one is called thedenominator, and these two numbers are separated by a line.

eg:2/5 where two is numerator and 5 is denominator

3/5/20= 3/100thanks

3/5/30= 3/150= 1/50thanks

Suppose x should be addedso4/9+x= 2/3x= 2/3-4/9= 24-16/36= 8/36

7th term = (a+6d) 11th term = (a+10d)(a+6d)7 since 7th term of the ap is 7 times and the same for 11th term(a+6d)7=(A+10d)11 (given)7a + 42d =11a +110d (on solving)7a - 11a = 110d - 42d-4a = -68da= -17d

we know 18th term = (a+17d)................................. (i)now we substitute the value of a in (i)which emplies, -17d + 17d = 0Hence proved

4/7 is the fraction with numerator 4 and denominator 7

4/7 is the required fraction

4/7isrequired fraction

4/7 is required answer.

the required fraction is =4/7

numerator 4 and denominator 7 with fraction 4/7

find the fraction is the write answer is 4/7 is the fraction , numerator is 4 and denominator is 7

4/7 is the required fraction

numerator 4 and denominator 7 convert into fraction is 4/7

4/7 is the required fraction answer.

4/7 is the required fraction of this question

The electrical resistance of an object is a measure of its opposition to the flow of electric current. The inverse quantity is electrical conductance, and is the ease with which an electric current passes. Electrical resistance shares some conceptual parallels with the notion of mechanical friction.

A barrier in the natural flow of current is known as resistance.

4x²+12x²+9x²adding the three given points25x²

Sum of angles of a hexagon = 720.=> 6x+4x+5x+6x+7x+8x = 720=> 36x = 720=> X = 20. Please hit the like button if this helped you

Let AP= a, a+d, a+2d, a+3d, a+4d.

By given

3a+6d=24

a+2d=4

d=(4-a)/2 ….(1)

a(a+4d)=48

a²+4ad=48 …..(2)

(1) and (2)

a²+2(8a-a²)=48

a²+16a-2a²-48=0

-a²+16–48=0

a= 4 or 12

a=12(impossible)

So a=4, d=2.

This AP = 4, 6, 8, 10, 12.

sin P = QR/PQcos Q = PR/PQtan P = QR/PRtan Q = PR/ QR

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Thanks g😊

(i)

(ii)

good 😶👏👍😎👍

(iv)

a+d=8a+4d=17

8-d+4d=178+3d=173d=9d=3a=5

19th term=a+18d=5+18*3=59

36/48 = (9x4)/(12x4) cancelling 4 from numerator and denominator, we get9/12. hence numerator comes out to be 9 in here

Given pth term = 1/qThat isap = a + (p - 1)d = 1/qaq + (pq - q)d = 1 --- (1)Similarly, we get ap + (pq - p)d = 1 --- (2)From (1) and (2), we getaq + (pq - q)d = ap + (pq - p)d aq - ap = d[pq - p - pq + q]a(q - p) = d(q - p)Therefore, a = dEquation (1) becomes,dq + pqd - dq = 1 d = 1/pqHence a = 1/pq

Consider, Spq = (pq/2)[2a + (pq - 1)d] = (pq/2)[2(1/pq) + (pq - 1)(1/pq)] = (1/2)[2 + pq - 1] = (1/2)[pq + 1]

thnx

To get 4 in numerator, divide numerator and denominator by 936÷9/63÷9=4/7

No, the ratios 1:2 and 2:3 are not equivalent. Reason: 1/2 ≠ 2/3

43 / (2⁴. 5³) = (43*5)/(2⁴.5⁴) = 215/10⁴So, the decimal expansion terminates after 4 decimal places as 10 has power 4

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Let a is the first term of AP and d is the common difference of APnow ,according to question ,(m+1) th term =2 (n+1) th term a+(m+1-1) d =2 {a+(n+1-1) d }a+md=2a+2nd(m-2n)d=a ------------(1)now,LHS =(3m+1) th term =a+(3m+1-1) d=(m-2n) d+3md =2 (2m-n) d

RHS =2 (m+n+1) th term =2 {a+(m+n+1-1) d}=2 {a+(m+n) d}=2 {(m-2n)d +(m+n) d}=2 (2m-n) d

hence LHS =RHS