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ive positive integin4-p The Summiddle 3 texms is 24 and psoduct of f+the teim |
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Answer» Let AP= a, a+d, a+2d, a+3d, a+4d. By given 3a+6d=24 a+2d=4 d=(4-a)/2 ….(1) a(a+4d)=48 a²+4ad=48 …..(2) (1) and (2) a²+2(8a-a²)=48 a²+16a-2a²-48=0 -a²+16–48=0 a= 4 or 12 a=12(impossible) So a=4, d=2. This AP = 4, 6, 8, 10, 12. |
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