1.

ive positive integin4-p The Summiddle 3 texms is 24 and psoduct of f+the teim

Answer»

Let AP= a, a+d, a+2d, a+3d, a+4d.

By given

3a+6d=24

a+2d=4

d=(4-a)/2 ….(1)

a(a+4d)=48

a²+4ad=48 …..(2)

(1) and (2)

a²+2(8a-a²)=48

a²+16a-2a²-48=0

-a²+16–48=0

a= 4 or 12

a=12(impossible)

So a=4, d=2.

This AP = 4, 6, 8, 10, 12.



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