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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Line segments AB and CD intersect at O such that AC | DB.If < CAB = 35° and < CDB = 55°, then < BOD-(d) 8 |
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| 2. |
4. In the adjoining figure, line segments AB and CD bisect eachother at O.Prove that:(i) AC DB and(ii) AD-CB. |
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Answer» Since,ACandBDbisecteachotheratO, thenOA=OBandOC=OD In∆AOCand∆BOD,OA=OB Given∠AOC=∠BOD VerticallyoppositeanglesOC=OD Given⇒∆AOC≅∆BODSAS ⇒AC=BDCPCT ∠CAO=∠OBDCPCT ⇒∠CAB=∠ABD In∆AODand∆BOC,OA=OB Given∠AOD=∠BOC VerticallyoppositeanglesOD=OC Given⇒∆AOD≅∆BOCSAS ⇒AD=CBCPCT ⇒∠OAD=∠OBCCPCT But∠OADand∠OBCarealternateinterioranglesmadebythetransversalABwithlinesADandBCandareequal. So,AD∥CB Thanks Can i have your fb account please |
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| 3. |
28. In a parallelogram ABCD, E and F are the midpoints of sides AB and CD 4respectively as shown in the figure below. Show that the line segments AFand EC trisect the diagonal BD |
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| 4. |
arrange the following in decending order 4/21, -6/7, 23/35 ,9/-14 |
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| 5. |
(ii) On his return journey after drinking water, he jumps 4 steps upand then jumps back 2 steps down in every move. In how manyjumps will he reach back the top step? |
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Answer» 1st jump = 9 - 4 + 2 = 72nd jump = 7 - 4 + 2 = 53rd jump = 5 - 4 + 2 = 34th jump = 3 - 4 + 2 = 1 |
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| 6. |
7. By what number (-9)- should be multiplied, so that the produthat the product may be equal to (-12)', |
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| 7. |
Direction for Q. 39-40: Read the following informationcarefully and answer the questions which follow:1.i.iii.iv."A × B, means "A is father of B'."A + B' means 'A is daughter of B'‘A ÷ B' means lis mother of B'.‘A-B' means ‘A s brother of B'.39-t-1f"P ÷ Q + R × T', how is T related to Q?しB. SisterA. AuntC. BrotherE. of theseD. Grandson40. ) If"R-P ÷ J × Q, how is J related to R?A Son/daughter B. NephewC. NieceE. of theseD. Grandson |
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Answer» 39 - option b is right T is the sister of Q40-nephew |
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| 8. |
25. Select that figure which may continue the series:चित्र का चयन करें जो श्रृंखला को पूरा कर सके?Question Figures :AnswerFigure |
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Answer» the answer of this figure is 1 ye clock yose ghum raha he,ghadiki kidisha me ghum raha he,isliya answer ho ga 'D' last bala figure right 3 is the correct answer to this yes as it move so first figure is the figure which may continue.the series. |
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| 9. |
4 Suppose line segments AB and CD intersect at O in such a way thatAO OD and OB OC. Prove that AC BD but AC may not be parallel toBD.Triangles Congruence of Triangles395 |
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Answer» thanks |
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| 10. |
6 Continue the pattern.7) 1421b 9 (18) 27Teacher's signature39 |
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Answer» a)7,14,21,28,35,42,49,56,63,70b)9,18,27,36,45,54,63,72,81,90c)8,16,24,32,40,48,56,64,72,80 |
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| 11. |
पी ि 800 A ८०0्च्ड Hoa. As |
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| 12. |
1. The rainfall ina city on three consecutive months was 30.56 cm, 23.20 cmnths ?.and 5.7 cm. How much total did it rain in these three mon |
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Answer» rains are in 3 months=30.56,23.20,5.7so total rain in 3 months=30.56+23.20+5.7 =59.46 cm |
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| 13. |
Q0\)[ 9]() |
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| 14. |
पे समीर १ के...s, *पु «मु s Az 9ही 5 x2-px+q=0; PL i +1=0R et R SR |
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| 15. |
tosuhneal ABc 0čžşructong4 wbing RHS Trnert That tuamgle ABÄ and Abc are |
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Answer» m f |
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| 16. |
6 (p)9 (0)s (q) |
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Answer» 30×25=75035×12=420750+420=11701170÷30= 39 दिन |
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| 17. |
the rainfall in a city on three consecutive months was 30.56cm, 23.20cm and 5.7cm. how much total did it rain in these three months? |
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Answer» rains are in 3 months=30.56,23.20,5.7so total rain in 3 months=30.56+23.20+5.7 =59.46 cm thank you |
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| 18. |
write the next three natural naumber after 1099 |
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Answer» 1100,1101,1102. these are the numbers |
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| 19. |
:. 5 2थी हे...” जा . 55४] - tang sn-cos |
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| 20. |
Find Five rational number between_5and _37. 8 |
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| 21. |
Find five rational number between 2\3 and 4\5 |
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Answer» First we must equate the denominators.Let's do LCM of 3 and 5.It is 15.2/3 and 4/5.By multiplying by 5/5 and 3/3 to 2/3 and 4/5 respectively,we get10/15 and 12/15Since there is only one number available between 10/15 and 12/15,we should multiply both by 5/5..Now we get50/75 and 60/75Now five rational numbers between 2/3(50/75) and 4/5(60/75) are61/75,62/75,63/75,64/75 and 65/75 |
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| 22. |
ateulatèralAABC,ANisperpendiculartoBC.ProvethatAN3BN9. Prove by Pythagoras' theorem that the diagonals of a rectangle are equal in length. |
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Answer» Forthe asked question, we need to draw a rectangle, that is, Consider a rectangle ABCD, Join B and D, similarly join A and C, therefore by joining this Diagonals AC and BD are formed. Now in triangle BAD,BD2= AB2+AD2( by pythagorus theorm.) Similarly in triangle BAC,AC2=BC2+AB2(same reason.) Therefore BC=AD and AB is the commom in both,so AC2=BD2. Which implies that AC =BD. Hence,Proved. |
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| 23. |
14. If A(-5,7,B(-4,-5),C(-1,-6) and D(4,5) are the vertices of a quadrilateABCD.ral, find the area of the quadrilateral |
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| 24. |
Find the LCM.24 x^{2} y z \text { and } 27 x^{4} y^{2} z^{2} |
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| 25. |
Find area of the triangle if its base is 7cm and perpes icular on the base is 5cm.d cello tang Find the length of cello tape |
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| 26. |
24 ( x ^ { 2 } y z + x y ^ { 2 } z + x y z ^ { 2 } ) b y |
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Answer» 24(x^2yz+xy^2z+xyz^2)/8xyz3(x+y+z) |
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| 27. |
If secθ + tangp , then find the value of cosecθ |
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Answer» Given: sec θ + tan θ = p ----- (i) We know that sec²θ - tan²θ = 1 ⇒ (secθ + tanθ)(secθ - tanθ) = 1 ⇒ (p)(secθ - tanθ) = 1 ⇒ secθ - tanθ = (1/p) ----- (ii) On solving (i) & (ii), we get ⇒ secθ + tanθ + secθ - tanθ = p + 1/p ⇒ 2secθ = p² + 1/p ⇒ secθ = (p² + 1)/2p ⇒ cosθ = (1/secθ) = 2p/p² + 1 Sin²θ = 1 - cos²θ = 1 - (2p/p² + 1)² = 1 - (4p²)/p⁴ + 1 + 2p² = (p⁴ + 1 + 2p² - 4p²)/p⁴ + 1 + 2p = (p⁴ + 1 - 2p²)/p⁴ + 1 + 2p = (p² - 1)²/(p² + 1)² sin θ= p² - 1/p² + 1. Now, We know that cosecθ = (1/sinθ) ⇒ (p² + 1)/p² - 1. |
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| 28. |
00Excelience in Mathematics- vilBC and AC are respectively 15e perimeter of Î ABC is 50 cm. Its sides AB,10 em and (r+ 4) em. Find the value of x ?Ie km 72 m long wire is required s |
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| 29. |
4x-16.x +16 |
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Answer» 4x^2 - 16x + 16 = 04x^2 - 8x - 8x + 16 = 04x(x - 2) -8(x - 2) =0(4x - 8)(x - 2) = 04(x - 2)(x - 2) = 0x = 2 |
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| 30. |
d the value of x, if x =16+16-6+oo , where x is a natural |
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Answer» PLEASE HIT THE LIKE BUTTON |
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| 31. |
9 x ^ { 2 } + 16 y ^ { 2 } + 4 z ^ { 2 } - 24 x y + 16 y z - 12 x z |
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Answer» (-3x)^2+(4y)^2+(2z)^2+2(-3x)(4y)+2(4y)(2z)+2(-3x)(2z) = (-3x+4y+2z)^2 |
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| 32. |
9 x ^ { 2 } + 4 y ^ { 2 } + 16 z ^ { 2 } + 12 x y - 16 y z - 24 x z |
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| 33. |
7. Prove that :+ aBEw |
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Answer» please like me and accept as best 😍😍😍 |
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| 34. |
find a andywand provePQ 11004** Toys |
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Answer» hear Y=110°andX=70° because vertically opposite angles are equal pq//xy because when the corsponding angles are equal on the intersecting line than the intersected lines are parallel to each other y=110x=70 opposite angle are equal |
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| 35. |
In the figure, ifxiy w+z,then prove that AOB is a line. |
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| 36. |
33. In Fig. 6.57,x y and w . Prove that I1 In.Fig. 6.57 |
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Answer» If you like the solution, Please give it a 👍 |
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| 37. |
3.Rationalise the denominators of the following:as WF-5(iv)J7-22V2+3/36.If both aandANSWERSHey Aman RajAnswer question and earn 150 pointWin points each time your answer gets a lik-answer. Be careful, posting irrelevant ansresult in account termination.oType your answer here..... |
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Answer» bhai 4th no mjhe v ni aaya😜 |
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| 38. |
Question 5. Answer in exponent form(i) 45 42(iii) (3), (3)45)11 +(4)6(iv) (-5 |
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Answer» i) (4×4×4×4×4)÷(4×4) = 4×4×4 = 64 ii) (-5)(-5)(-5)(-5)(-5)(-5)(-5)/(-5)(-5)(-5)(-5) = (-5)(-5)(-5) = -125 iii) (2/3)(2/3)(2/3)(2/3)(2/3)÷(2/3)(2/3)(2/3)(2/3) = 2/3 iv) (-1/5)(-1/5)(-1/5)(-1/5)(-1/5)(-1/5)(-1/5)(-1/5)(-1/5)(-1/5)(-1/5) ÷ (-1/5)(-1/5)(-1/5)(-1/5)(-1/5)(-1/5) = (-1/5)(-1/5)(-1/5)(-1/5)(-1/5) = -1/3125 |
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| 39. |
33. In Fig. 6.57, x -and wz. Prove that I1 In.P7mFig. 6.57 |
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Answer» If you like the solution, Please give it a 👍 |
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| 40. |
42.In the following figure, find the ZCBE:70°50° |
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Answer» 60° is the correct answer of the given question 60 degree is right answer 50+70+CBE=180CBE=180-120CBE=60 |
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| 41. |
1. Perpendicular height of a cone is 12 cm and its slant height is 13 cm. Find the radius ofthe base of the cone, |
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Answer» 24cm is the length or radius of base of the cone We know that l² = h² + r² so, r² = 13² -12² = 169 - 144 r² = 25so, Radius, r = 5 cm Solve by phythgoras theormanswer 5cm we know that, (slant height)^2=(perpendicular height )^2+( radius)^2(13)^2=(12)^2+(r)^2169=144+r^225=r^2r=√25=5cm ans hiiiiiii🖐️🖐️🖐️🖐️🖐️🖐️🖐️😊😊😊😊😊😊😊😁😁😉 radius = 5 cm is the correct and best 5 cm is the correct answer radius=5 cm it is right answer r = 5 is the best answer. 5cm is the correct answer radius = 5 is the best answer. r = 5 is the best answer. radius of the base of the cone 5 5 cm is the correct answer of this question 5cm is correct answer |
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| 42. |
In Fig. 6.16, if x+y = w+ z, then prove that AOBis a line. |
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| 43. |
Perpendicular height of a cone is 12 cm and its slant height is 13 cm. Find the radius ofthe base of the cone. |
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Answer» We know that l² = h² + r² so, r² = 13² -12² = 169 - 144 r² = 25so, Radius, r = 5 cm |
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| 44. |
or the coneA right triangle ABC with sides 5 cm, 12 cm and 13 cm is revolved about the side 12cm.7./// Find the volume of the solid so obtained. |
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Answer» If you like the solution, Please give it a 👍 |
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| 45. |
PART- AMarks: 5 x 2swer any 5 questions: (Each qFind 'x" if \left| \begin{array}{ll}{x} & {3} \\ {1} & {2}\end{array}\right|=0 |
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Answer» 3\2 answer hoga bhai |
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| 46. |
The 1st term of an ininite G.P. is unity, and any term is equal to the sum of all terms thatfollow it. Find the series, |
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| 47. |
222. Mention type of number? |
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Answer» rational is the correct answer of the given question it is a rational number pie value is 22/7 ,so the answer is zero The answer is... Pie is Irrational number. 22/7 is an approximatame value of pie. Hope you understand |
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| 48. |
A child is chosen at random from a groupcontaining of 4 girls and 6 boys. What isthe probability of the child being a girl?2(A)a234 |
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Answer» total child=10 probability of child being girl=4/10=2/5 Total child= 4girls +6 boys=10 childrenProbability of being a girl=4/10=2/5 |
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| 49. |
Asobie w plis lacatProve that the sum of the angles of a triangle is 180. |
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| 50. |
(vil) (-27) x (-16) + (-27) > (-14) |
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Answer» (-27) × (-16) + (-27) × (-14) = (-27)(-16 - 14) = (-27) × (-30) = 810 |
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