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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
2x+36=11 |
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Answer» 2x + 36 = 112x = 11-362x = -25x = -25/2= -12.5 hit like if you find it useful |
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| 2. |
simlpify6^(2x-1) = 36^(x-1) +1080 |
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| 3. |
Example 18: Rationalise the denominator of |
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Answer» Rationalising hence2-√5/(2+√5)*(2-√5)=2-√5/4-5=2-√5/-1=√5-2 |
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| 4. |
25-u= 2x+36- 2D |
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| 5. |
21-Ń Solve:< 05x-6-x2 |
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| 6. |
Solve : sina + sin 0 = 1 and find 0. |
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Answer» maloom Nahi hai app hi log batao Nahi maloom hai to aaj me aapko all answer are Right Consider a right angled triangle with an internal angleθ:  Then: sinθ=ac cosθ=bc So: sin2θ+cos2θ=a2c2+b2c2=a2+b2c2 By then sino =accoso =bcso:sin2∅+ cos2∅=a2c2+b2c2=a2+b2c2 sin2 0 + sin 0=0 iska answer hai sin–¹(-1±√5/2) is the answer to yeh formula hei answer your question sin2 +cos2=a2c2+b2c3=a2+b2c2 is right answer of this question sin1/2(-1+_√5/2) is correct answer of this question sin^2A+sinA+1=0as per shridhar acharya a=1,b=1,c=1x= -b+-√b^2-4ac/2a sinA= -1+-√(1)^2-4×1×1/2 = -1+-√-3/2 the following above is the right answer |
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| 7. |
0methodsolve this question by Gushlachio917-8-0. 2x-37-1=0 |
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| 8. |
u u o epRR & Yएव लत, पा लुक पाप न ug = Y दा? (6४ |
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Answer» Sn=5n^2 +11nS1=a1=5 (1×1)+11×1=5+11=16 S2=a1+a2=5(2×2)+11×2=42a2=42-16=26 d=a2-a1=26-16=10 Tn=a+(n-1)×dTn=16+(n-1)10Tn=16+10n-10Tn=6+10n |
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| 9. |
Find e v ug |
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| 10. |
factorise the following by splitting middle terms i.6x²+17x+5 |
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Answer» 6x^2 + 17x + 5 = 6x^2 + 15x + 2x + 5 = 3x(2x + 5) + 1(2x + 5) = (3x + 1)(2x + 5) -15 and -2 is right ans bcz dono ka sum 17x hoga and product 30 hoga |
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| 11. |
(2, -12)RELATIONSHIP BETWEEN ZEROES AND COEFFICIENTS OF A POL, we shall establish the relationship between the zeroes and coefficients of a polynomConsider a Quadratic Polynomial p(x) = 2x2 - 8x + 6.w splitting the middle term, we have: |
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Answer» 2x^2 - 8x + 6 = 02x^2 - 6x - 2x + 6 = 02x(x - 3) - 2(x - 3) = 0(2x - 2)(x - 3) = 0x = 1, 3 Sum of zeroes= - coefficient of x/ coefficient of x^2= - (-8)/2 = 4 Product of zeroes= constant / coefficient of x^2= 6/2 = 3 |
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| 12. |
factories the following using middle terms splitting x^2 -10x -24 |
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Answer» x²-10x-24x²+2x-12x-24x(x+2)-12(x+2)(x+2)(x-12) |
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| 13. |
3x +20+4x _ 36 =180 |
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Answer» 3x + 20 + 4x - 36 = 1807x - 16 = 1807x = 180 + 167x = 196x = 196/7 = 28 Therefore, value of x is 28 |
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| 14. |
3x+2y=362x+3y=14 |
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Answer» 2x + 3y = 14...(i)3x+2y = 36...(ii)2(ii) - 3(i):=> -5y = 30=> y = -6. Putting this value in (i),2x +3(-6) = 14=> 2x = 14+18=> X = 16. Please hit the like button if this helped you. nice |
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| 15. |
3 (3 2)Step 3 Putting (a) and (b) together- 2y (3x -2)-3 (3x 2- (3r - 2) (2y - 3)The factors of (6xy-4y + 6-9 x) are (3x -2) and (2y-EXERCISE 14.1I.Find the common factors of the given terms.(i)12x, 36(i) 2y. 2 |
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| 16. |
23B. If θ is the angle between the diagonals of a parallelogram ABCD whosevertices are A(0, 2), B(2,-1), C(4, 0) and D(2, 3). Show that tan 0 2 |
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Answer» In the parallelogram ABCD, Slope of the diagonalAC (m1) = (0-2)/ (4-0) = -1/2 Slope of the diagonal BD (m2) = (3 - (-1))/ (2 - 2 ) = ∞ That means diagonal BD is parallel to the y axis. Now, m1x m2= -1 (-1/2) x tanθ = -1 So, tan θ = 2 |
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| 17. |
Example 8: Solve 0.1 of Exercise 3.1 by the method of substitution |
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Answer» 42-7(y)=-42; -7y=-42-42; -7y=-84, y=-84/-7=12,; 42-7(y)=-42; 42-7(12)=-42; 42-84=-42 |
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| 18. |
r1 3Example 18: Solve2x +3 8 |
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Answer» (x+1)/(2x+3) = 3/88(x+1) = 3(2x+ 3)8x + 8 = 6x + 98x - 6x = 9-82x = 1x = 1/2 ans |
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| 19. |
2323. If θ is the angle between the diagonals of a parallelogram ABCD whosevertices are A (0, 2), B(2,-1), C(40 and D(2, 3). Show that tan e 24 Cha thot th |
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Answer» In the parallelogram ABCD, Slope of the diagonalAC (m1) = (0-2)/ (4-0) = -1/2 Slope of the diagonal BD (m2) = (3 - (-1))/ (2 - 2 ) = ∞ That means diagonal BD is parallel to the y axis. Now, m1x m2= -1 (-1/2) x tanθ = -1 So, tan θ = 2 |
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| 20. |
lim 5-3*-21xâ0Example 39: Evaluate |
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| 21. |
5.Vikash is more competent than Keshav, Shiv is less competent than Aashu but more competentthan Keshav. Vikash is less competent than Shiv. Who is the most competent in the group ?(1) Aashu(2) Keshav(3) Vikash(4) Shiv |
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| 22. |
3060. what washisAmit uas given an increment of 20% on his salary. If his new salary issalary before the increment?12, |
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Answer» thanw thanq The old salary of Amit is Rs. 12,750 |
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| 23. |
12. Amit was given an increment of 20% on his salary. If his new salary is 15300, what was hissalary before the increment? |
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Answer» let his initial salary = X rs.A/QX + X ✖ 20/100 = 15300120X/100 = 15300X = (15300 ✖ 100)/120X = 12750 rs. ( ANS ) |
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| 24. |
tusperiileleris24m,hnditsaltitude.1. AX and CY are heights of the parallelogram ABCD whose area is 9- cm2. What are the lengths ofX4 and CY?D X4 cm |
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| 25. |
धान की समझ का विकास कर सके।लखिए -(ब)7 3 82 1 3 5।। 3 17++44नखिए -| 7 584+26 || 938 |
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Answer» 7 3 2 8+2 135+4 3 1 7 =14080 |
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| 26. |
,592 , ,500 , ,508 , i586 、 ,584The value of-592+/580 +戸78 +戸76 + i574(A)1(B)-2(C) 3 |
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Answer» option B is correct -2 is the answer but how please explain iota raised to the power in multiples of 4 has value = 1 and the values raised to power of 2 have value -1. hence n the numerator +1-1+1-1+1 = 1 and in denominator -1+1-1+1-1 = -1 hence the fraction = 1/(-1) = -1 hence -1 -1 = -1 answer is -2 because -1-1=-2 so the answer is -2 |
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| 27. |
i592 + i590 +i588 + i586 + i584592590588586 5848. Thevalueof582580578576574(b) -2(a) -1(c) -3 |
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| 28. |
140MATHEMATICSExample 5 Evaluate (i) 5 !(ii)6120 |
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Answer» 5! = 5*4*3*2*1 = 1207! = 7*6*5! = 5040 7!-5! = 5040-120 = 4920 |
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| 29. |
Example 5. Prove that:1+ cos A 1- cos A1- cos A V1+ cos A- 2 cosec A |
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| 30. |
Example 6 Prove that2.7"+ 3.5" -5 is divisible by 24, for all n EN |
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| 31. |
Example 13: BL and CM are medians of atriangle ABC right angled at A. Prove that4 (BL' + CMP) = 5 BC2. |
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| 32. |
The monthly salary of a teacher issalary after an year.1.12,800. If his annual increment is 300, find his new |
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Answer» monthly salary=12800 annual salary= 12800*12 =153600 so salary after increment per annum=153600+153600*3% =153600+4608 =158208 hence salary of a month = 158208/12 = 13184 |
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| 33. |
2. The monthly salary of a teacher is 12,800. If his annual increment is 3%, find his newsalary after an year.1. |
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Answer» after an year salary=12,800×103/100 =128×103=₹13,1 84 ₹13184 is the correct answer After a year salary =12800×103/100=128×103=$13184is the right answer for this questions 12,800×103/100128×10313184 is the best answer |
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| 34. |
&. Which of the linesy 3 0 and x - 4y-7- 0 is farther from the origin. |
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| 35. |
a pie-diagram of the areas of continents of the world given in the followingAsia U.S.S.R Africa Europe America America26.9 20.5 30.3 4.9 24.3 17.9ivee ContinentsNorth SouthAustraliaAreain million sqkm)the following data gives the amount spent on the construction of a house. Draw a pi8.5w: lagram |
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| 36. |
A lcal bus is, cayng 10 pascengersome with 35 bckets and yemainingith 21.50 iktthal edeiatsreceiptstrom these passengers is 330, ind'ot parengers uh 5unbertickets |
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Answer» 5 rs passengers are x and 7.5 rs passengers are yso x+y=405x+7.5y=230x+1.5y=46x+1.5y-x-y=46-40=60.5y=6so y=12so x=28so 5 rs passengers are 28. |
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| 37. |
Who is the poet of the poema The Road not taken |
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Answer» the poet of the poem is "Robert Frost". The name of poet is Robert Frost. the pier of poem is Robert Frost Robot Frost is the poet The poet of this poem is ((((####ROBERT FROST####)))).... |
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| 38. |
9. A line intersects the y-axis and x-axis at the points P and O respectively If (2, -5) is the mid-point of PO,then find the coordinates of P and Q |
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Answer» i also posted another question.plz answer |
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| 39. |
13.If a,b,c EQ, then roots of the equation (b+c - 2a)x2 + (c+a-2b)x +(a+b-2c) = 0 are(A) Rational(B) Non-real (C) Irrational (D) Equal |
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Answer» May be Rational number. A rational right ans hai |
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| 40. |
A line intersects the y-axis and x-axis at the points P and Q respectivelyIf(2,-5) is the mid-point of PQ, then find the coordinates of P and Q. |
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| 41. |
6.A line intersects the y-axis and x-axis at the points P and Q respectively. If (2, 5) is the mid-point of PQ, then find the coordinates of P and Q. |
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| 42. |
2+If x= 7+52 , then find1Teacher's Signature: |
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Answer» 178 is the correct answer |
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| 43. |
\begin { equation } \int e^{x} \sin 2 x d x \end { equation } |
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| 44. |
Hiralal gave 1/9th of his money to his eldest son, 2/9th to hisdaughter and 5/9th to his wife. He donated the rest. If he hadRs. 10,00,008/- with him, what amount did he donate? |
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Answer» 1/9th to eldest son 2/9th to daughter 5/9th to wife so remaining are 1 - 1/9 - 2/9 - 5/9 = 1/9 so donated amount = 1000008/9 = 111112 |
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| 45. |
How will you describe the position of a table lamp on your stperson?(Street Plan) : A city has two main roads which cross each other at thecity. These two roads are along the North-South direction and East-West recudy table to anotherthe centre of the |
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| 46. |
Show that the line passes through the points (a, -1,2)and (3, 4,-2)is perpendicular to the line passesthrough the points (0, 3, 2) and (3, 5, 6). |
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| 47. |
Henna first originated in Egypt |
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Answer» Henna is actually a powder derived from crushing the leaves of the henna plant. The earliest use of this plant dates back to the Pharaohs in Egypt, some 9,000 years ago. Cleopatra, the last reigning queen of the ancient Egyptian civilisation is said to have used henna to adorn her body and beautify herself. |
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| 48. |
Find the equation of the circle whichpasses through the origin and cuts offchords of length 4 and 6 on the positiveside of the x- axis and y-axis respectively2. |
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Answer» can you give me digram |
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| 49. |
Equation of the line which passes through the origin and is parallel to the line having intercepts - 5 and 10 on x and y axis respectively |
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| 50. |
Line passes through: (3,-1), has slope-1 |
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