Solve : sina + sin 0 = 1 and find 0.

1.	Solve : sina + sin 0 = 1 and find 0.
Answer» maloom Nahi hai app hi log batao Nahi maloom hai to aaj me aapko all answer are Right Consider a right angled triangle with an internal angleθ: Then: sinθ=ac cosθ=bc So: sin2θ+cos2θ=a2c2+b2c2=a2+b2c2 By then sino =accoso =bcso:sin2∅+ cos2∅=a2c2+b2c2=a2+b2c2 sin2 0 + sin 0=0 iska answer hai sin–¹(-1±√5/2) is the answer to yeh formula hei answer your question sin2 +cos2=a2c2+b2c3=a2+b2c2 is right answer of this question sin1/2(-1+_√5/2) is correct answer of this question sin^2A+sinA+1=0as per shridhar acharya a=1,b=1,c=1x= -b+-√b^2-4ac/2a sinA= -1+-√(1)^2-4×1×1/2 = -1+-√-3/2 the following above is the right answer

Answer»

maloom Nahi hai app hi log batao

Nahi maloom hai to aaj me aapko

all answer are Right

Consider a right angled triangle with an internal angleθ:

Then:

sinθ=ac

cosθ=bc

So:

sin2θ+cos2θ=a2c2+b2c2=a2+b2c2

then sino =accoso =bcso:sin2∅+ cos2∅=a2c2+b2c2=a2+b2c2

sin2 0 + sin 0=0 iska answer hai

sin–¹(-1±√5/2) is the answer to

yeh formula hei answer your question

sin2 +cos2=a2c2+b2c3=a2+b2c2 is right answer of this question

sin1/2(-1+_√5/2) is correct answer of this question

sin^2A+sinA+1=0as per shridhar acharya a=1,b=1,c=1x= -b+-√b^2-4ac/2a sinA= -1+-√(1)^2-4×1×1/2 = -1+-√-3/2

the following above is the right answer

Discussion