Explore topic-wise InterviewSolutions in Current Affairs.

But mam answer is 120960

number of members = amount they paid

number of members = (2916)^1/2 = 54 (ANS)

let no of member = xcontribute = xx.x= 2916x^2= 2916x= √2916= 54 so no of member = 54

number of members = amount they paidnumber of. members =(2916) ^1/3 = 54(ans)

number of members =amount they paid number of members =(2916)^1/2=54(ANS)

The H.C.F. of 96and 404is

CP = 400 GAIN = 20% SP = 400*1.2 = 480

The first ten natural number are 1,2,3,4,5,6,7,8,9,10.

thank you

Sn = n/2(2a+(n+1)d)

Now an= a+(n-1)d4= a+(n-1)a+n = 5

An=a+(n-1)d=4a+(n-1)2=4 (substitute d=2)a+2n-2=4a+2n=6a=6-2n

Sn=n/2(2a+(n-1)d)-14=n/2(2(6-2n)+(n-1)2) (substitute a=6-2n,d=2)-14=n/2(12-4n+2n-2)-14=n/2(10-2n)-14=n(5-n)5n-n^2=-14n^2-5n-14=0n^2-7n+2n-14=06-2n(n-7)+2(n-7)=0(n-7)(n+2)=0n=7,-2

n can't be negativetherefore n=7

a=6-2n (substitute n=7)a=6-2(7)=6-14=-8

thanks bro

(8*3)-(7.5*2)=9. Done

L cm 72, 126,156,; 72=2×2×2×3×3; 156=2×3×3×7; 156=2×2×3×13; L cm =2×2×2×3×3×7×13=8×9×91=6056; Hcf=2×3=6; L cm x Hcf=6057 x 6=36+0+30×42=45036

(x+4) (x+10)

x^2+10x+4x+40=x^2+14x+40

6x is the right answer

(x+4) (x+10)xdhdjzbsjxhakbxjejzbejwhsjsjjdbd

please like my answer if you find it useful

Thankyou so much

Given, total value of Rs = Rs 300Total number of coins = 160Coins of denomination = Re 1, Rs 2 and Rs 5Number of Rs 2 coins = 3 x number Rs 5 coinsLet the number of coins of Rs 5 = mSince, the number coins of Rs 2 is 3 times of the number of coins of Rs 5Therefore, number of coins of Rs 2=m×3=3mNow, Number of coins of Re 1 = Total number of coins – (Number of Rs 5 coins + Number of Rs 2 coins)Therefore,Number of coins of Re 1= 160 – (m+3m) = 160 – 4mTotal Rs = (Re 1 x Number of Re 1 coins) + (Rs 2 x Number of Rs 2 coins) + (Rs 5 x Number of Rs 5 coins)⇒ 300 = [1×(160–4m)] + (2×3m) + (5×m)⇒ 300 = (160–4m) + 6m + 5m⇒ 300 = 160 – 4m + 6m + 5m⇒ 300 = 160 – 4m + 11m⇒ 300 = 160 + 7mAfter transposing 160 to LHS, we get300 – 160 = 7m⇒ 140 = 7mAfter dividing both sides by 7, we get 1407 = 7m7Or, m = 20Thus, number of coins of Rs 5 = 20Now, since, number of coins of Re 1=160–4mThus, by substituting the value of m, we getNumber of coins of Re 1= 160 – (4×20) = 160 – 80 = 80Now, number coins of Rs 2 = 3mThus, by substituting the value of m, we getNumber of coins of Rs 2= 3m = 3×20 = 60Therefore,Number of coins of Re 1 = 80Number of coins of Rs 2 = 60Number of coins of Rs 5 = 20

any short method

310000 is a correct answer

Given, total value of Rs = Rs 300Total number of coins = 160Coins of denomination = Re 1, Rs 2 and Rs 5Number of Rs 2 coins = 3 x number Rs 5 coins

Let the number of coins of Rs 5 = mSince, the number coins of Rs 2 is 3 times of the number of coins of Rs 5Therefore, number of coins of Rs 2=m×3=3mNow, Number of coins of Re 1 = Total number of coins – (Number of Rs 5 coins + Number of Rs 2 coins)Therefore,Number of coins of Re 1=160–(m+3m)=160–4mTotal Rs = (Re 1 x Number of Re 1 coins) + (Rs 2 x Number of Rs 2 coins) + (Rs 5 x Number of Rs 5 coins)⇒300=[1×(160–4m)]+(2×3m)+(5×m)⇒300=(160–4m)+6m+5m⇒300=160–4m+6m+5m⇒300=160–4m+11m⇒300=160+7m

After transposing 160 to LHS, we get300–160=7m⇒140=7m

After dividing both sides by 7, we get

140/7=7m/7

Or,m=20Thus, number of coins of Rs 5 = 20Now, since, number of coins of Re 1=160–4mThus, by substituting the value of m, we getNumber of coins of Re 1=160–(4×20)=160–80=80Now, number coins of Rs 2 = 3m

Thus, by substituting the value of m, we getNumber of coins of Rs 2=3m=3×20=60Therefore,Number of coins of Re 1 = 80Number of coins of Rs 2 = 60Number of coins of Rs 5 = 20

any other short method plzz..

Like my answer if you find it useful!

x² - y² - 9z² + 6yz

x² - ( y² + 9z² - 6yz)

x² - ( y - 3z)²

( x - ( y - 3z)) ( x + ( y - 3z))

( x - y + 3z) ( x + y - 3z)

92 - x =63.58x=92-63.58x=28.42

28.42 is to be added to get 92

28.42 the correct answer of the given question

92-63.58=28.42so 28.42 will be added in 63.48 to get 92.

63. 58 + x = 92; X = 92 - 63. 58 = 28. 42

28.42 is correct answer

28.42 us correct anseer

28.42 is the correct answer

hit like if you find it useful

q(2) = 2 + 2 - 2^2 = 4 - 4 = 0

x+4=66x=66-4x=62 is the answer

men and women ratio=4:7total ratio=4+7=11such 7women in 11passengerso 1women 11/7so 147 women. 11*147/7=231ans

hit like if you find it useful

27 is the correct answer of this question

the right Ans is 9/16.

3*3,6x+1-5*5y9-1+6x10y8+6x10y

9x^2, 6 x+1-25y; 9x^2-6x+1-24y

If you find this solution helpful, Please like it.

67 * 99 = 6633 is the answer

thanks for the answer.I was just checking this app how it works.thanks

67*99 =6633 is the product

x +29 =411411-29=xx=411-29=382 and.

x+29=411x=411-29x=382

382 is right answer hi

X + 29 = 411 x=411-29x=382

x+29=411x = 411-29x = 382 is write answer

x+29=411x=411-29x=382

x+29=411x=411-29x=411

x+29=411x=411-29x=382 this is correct answer

x +29= 411; x=411-29= 382

x + 29 = 411x = 411 - 29x = 382Thus,the value of x in the given equation is 382.

in given equation x is equal to 382

x + 29 = 411

x = 411 - 29

x = 382.

X = 382.

382 this is a answer of these question

382 is the answer of your given question

382 is right answers

x+29=411

x=411-29 x=382 in right answer

x=411-29 X=382 in the right answer

the right answer is 382

x + 29 = 411x = 411 - 29x = 382Therefore, the value of x in the given equation is 382.

x+29=411x=411-29x=382.is right answer please like

x = 382 is right answer

thanks

Like my answer if you find it useful

6×5×90 at ones digit

0 at its ones place is the right answer

6x5x90 at one digit

25⁴ × 5⁵ = (5²)⁴ × 5⁵ = 5⁸ × 5⁵ = 5¹³ (∵ a^m a^n = a^(m + n))

Given question is -48*x^2*y^5/250y^4=24x^2*y/125

Hence answer is 24x^2y/125

-3v-3x = 15 => -3(v+x) = 15 => (v+x) = 15/-3 = -5 => v+x = -5

now, 5v+x = -29 => 4v+(v+x) = -29.... ( now, put x +v = -5)=> 4v+(-5) = -29=> 4v = -29+5 = -24=> v = -24/4 = -6

now, x = -5-v = -5-(-6) = 1

2×4×a^2×a^22×a^26=8a^2+22+26=8a^50

8a⁵⁰ is the solution

8a^50 is the correct answer

x+2=15x=15-2=13x=13