Given, total value of Rs = Rs 300Total number of coins = 160Coins of denomination = Re 1, Rs 2 and Rs 5Number of Rs 2 coins = 3 x number Rs 5 coins

Let the number of coins of Rs 5 = mSince, the number coins of Rs 2 is 3 times of the number of coins of Rs 5Therefore, number of coins of Rs 2=m×3=3mNow, Number of coins of Re 1 = Total number of coins – (Number of Rs 5 coins + Number of Rs 2 coins)Therefore,Number of coins of Re 1=160–(m+3m)=160–4mTotal Rs = (Re 1 x Number of Re 1 coins) + (Rs 2 x Number of Rs 2 coins) + (Rs 5 x Number of Rs 5 coins)⇒300=[1×(160–4m)]+(2×3m)+(5×m)⇒300=(160–4m)+6m+5m⇒300=160–4m+6m+5m⇒300=160–4m+11m⇒300=160+7m

After transposing 160 to LHS, we get300–160=7m⇒140=7m

After dividing both sides by 7, we get

140/7=7m/7

Or,m=20Thus, number of coins of Rs 5 = 20Now, since, number of coins of Re 1=160–4mThus, by substituting the value of m, we getNumber of coins of Re 1=160–(4×20)=160–80=80Now, number coins of Rs 2 = 3m

Thus, by substituting the value of m, we getNumber of coins of Rs 2=3m=3×20=60Therefore,Number of coins of Re 1 = 80Number of coins of Rs 2 = 60Number of coins of Rs 5 = 20

any other short method plzz..