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as given 6 to power 3x is 221 but 221 = 13×17 so there is no integer solution for x ,but real exist taking log base 6 on both sides gives3x = log base 6 (221)x = { log base 6 (221)}/3

c number answer hoga

answer D, if the lines intersect at -4,4 then use the slope to continue the pattern the same distance between x and y across the point of intersection

A= (5,-1)

Reflection in x-axis changes the y coordinate →A'= (5,1)

Reflection in y-axis changes the x coordinate →A"= (-5,-1) since A and A" has same y coordinatethe distance between them is the absolute value of difference between their x coordinates =5-(-5)= 10 units

√x-[x] = {x} and fractional part has period of 1

so, period of √{x} is = 1

It's a 0/0 form we will use l' hopital rule here and we will diffrentiate it till it's not a 0/0 formso we will differentiate numerator and denominator both irrespective of one another .. we will differentiate both taking them to be two different terms so d/DX( x+4)^1/31/3(x+4)^(1/3-1)1/3(x+4)^-2/3d/DX of denominator (x) will be 1now we will put limit

so after putting limits x tends to 0= 1/3(0+4)^-2/3= 1/3(4)^2/3= please like the solution 👍 ✔️👍

3/(x + 1) - 1/2 = 2/(3x - 1)[6 - (x + 1)](3x - 1) = 4(x + 1)[18x - 6 - (3x^2 - x + 3x - 1)] = 4x + 4-3x^2 + 16x - 5 = 4x + 43x^2 - 12x + 9 = 0x^2 - 4x + 3 = 0x^2 - 3x - x + 3 = 0x(x - 3) - 1(x - 3) = 0(x - 1)(x - 3) = 0x = 1, 3

The function inside the root should be positive,So (x-1)>0 x>1 x€(1, infinity)

Area of triangle=420 cm²base=20 cmArea =(1/2)*b*h(1/2)*20*h=420h=(420*2)/(20)h=42 cm

Given, Area of triangle = 420cm sq. And, Base of triangle = 20cm

Let h be the altitude of the triangle.

Now, Area of triangle=1/2×base×altitude 420=1/2×20×h 420=10h h=420/10 h=42

Therefore, the altitude of the triangle is 42cm....ans.....

thanks

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Where is the figure?

what is the ans. I think y=30, and X=180

first part

second part

Ratio of Ares=3^2/5^2=9/25

According to Euclid's Division Lemma,a = bq + r, Let 'a' be any positive integer , then it is of the form 3q , 3q + 1, 3q +2

Here are the following cases ----

CASE I ---> When a = 3q=>a = 3q=> a^3 = (3q)^3=> a^3 = 27q^3=> a^3 = 9(3q^3) = 9m, where m = 3q^3

CASE II ---> When a = 3q + 1=> a = 3q + 1=> a^3 = (3q + 1)^3=> a^3 = 27q^3 + 27q^2 + 9q + 1=> a^3 = 9m + 1 , where m = q(3q^2 + 3q + 1)

CASE III ---> When a = 3q + 2=> a = 3q + 2=> a^3 = (3q + 2)^3=> a^3 = 27q^3 + 54q^2 + 36q + 8=> a^3 = 9m + 8 , where m = q(3q^2 + 6q + 4)

Therefore, a^3 is either of the form 9m, 9m + 1 or 9m + 8.

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option 3 is correct answer

B is the correct ans

option D is the correct answer

b is the correct ans pls like my ans

3/4 is the correct answer

8 power (-1) = 1/85³ = 1252 power (-4) = 2⁴ = 16So, we get(16×125)/82 × 125250

So take x ^2 comman from denominator and numeratornow1+b/x+4/x^2/(1+a/x+5/x^2)now as x tends to infinity1/x will tend to 0soanswer will be1+0+0/1+0+0= 1

The value of given limit is 1.

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x=3,y=6,z=9,t=6 answer

(P + a/V2) (V - b) = RTP is pressure, V is volume and T is temperature.[P] = [F/A] = [MLT−2/L2] = [ML−1T−2][V] = [L3]We cannot add or subtract quantities of different dimensions. Therefore[P] = [a/V2] ⇒ [a] = [PV2] = [ML−1T−2L6] = [M L5T−2]∴ [a] = [M L5T−2]Similarly,[b] = [V] = [L3]

PTQ= 180 - POQ = 180 - 105 = 75Hence, (a) 75 is the answer

PTQ= 180 - POQ = 180 - 105 = 75Hence, (a) 75 is the answer

sum of angles of triangle is = 180°

here third angle +30+45 = 180°

=> Third angle = 180-75= 105°

option D

The sum of the angles inside a triangle is 180 degrees.

30+45+x=180

85+x=180

x=180–085

x=95

The last angle in the triangle is 95 degrees.

The 7:30 shows the hour hand between 7&8 exactly at (1/2) way and minute hand on6.So the angle between the minute hand and hour hand will be the (1.5) times the angle traversed between any two digits ie 1 out of 12 gaps on a clock =360°/12=30°. So the angle=1.5×30°=45°

dispersion is the splitting of white light

dispersion is right for your given question

The separation of visiblelight into itsdifferentcolors is knownas dispersion.Dispersion

dispersion is the correct answer of the given question

5x=2-(7/9)5x=(18-7)/95x=11/9x=11/45

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Given that 4/5 children in a school are boys. Therefore, the number of girls is 1/5.Let total number of students be x

1/5x = 200 x = 200 x 5 x = 1000 students

Number of boys is 4/5x

= 4/5 x 1000= 800 boys

suppose the number is xso