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1 2 :न नए कस को कीजिए! ए।2 3x-1 » A#६........ हे :/.. . .. 12 - N IR e S |
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Answer» 3/(x + 1) - 1/2 = 2/(3x - 1)[6 - (x + 1)](3x - 1) = 4(x + 1)[18x - 6 - (3x^2 - x + 3x - 1)] = 4x + 4-3x^2 + 16x - 5 = 4x + 43x^2 - 12x + 9 = 0x^2 - 4x + 3 = 0x^2 - 3x - x + 3 = 0x(x - 3) - 1(x - 3) = 0(x - 1)(x - 3) = 0x = 1, 3 |
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