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In triangle ABC<A + <B + <C = 18040 + <B + 90 = 180<B = 180 - (90 + 40)<B = 180 - 130<B = 50°

Now,In triangle EBD<E + <B + <D = 180100 + 50 + x = 180x = 180 - (100 + 50)x = 180 - 150x = 30°

Therefore, value of x = 30°

on reversing 43we get 34on dividing quotient is 3.9

(a) 11 it is yours answer

20asttashbdxbbdhgksjsnnsjdncj

on reversing 43we get 34on dividing quotient is 3.9

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(3+√3)(2+√2)= √3(√3+1)*√2(√2+1)= √6(√3+1)(√2+1)= √6*(√6+√3+√2+1)= 6+3√2+2√3 +√6

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6 is a even number and therefore all the multiples of 6 are even.

For example consider an even number like 2.

Multiples of 2 include 2, 4, 6, 8 etc which are even numbers.

Similarly multiples of 6 include 6, 12, 18.. which are even numbers.

Hope it helps u.............

6,12,18,24,30,36,42,48,54,60,66,72,etc are some multiple of 6 under 100

6, 12 ,18,24,30,36,42,48,54,60

0,6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96,… so that they form a simple pattern increasing by6at each step. Because6is an even number, all itsmultiplesare even.

10 multiples of 6 that are less than 100 = 6, 12, 18, 24, 30, 36, 42, 48,54,60, 66 .....

6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96 These all are the 10 multiple of 6 less than 100.

6,12,18,24,30,36,42,48,54 and 60

61218243036424869

6,12,18,24,30,35,42,48,54,60 is the answer of the question

any integer when divided by 4 gives a quotient q, and a reminder which is either 0, 1, or 2 or 3...

so N = 4q or 4 q +1 or 4 q+2 or 4 q+3 for a nonnegative integer q. 4 q and 4 q + 2 are even numbers. it is quite obvious.

hence any odd positive integer is of the form 4q +1 or 4 q +3

equivalently also we can say N is of the form: 4 q - 1 or 4q - 3

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0 is added or subtracted number remains unaffectedhence3+0=35+0=5

thanks

a:c-15:16 is the best answer

Columbus wanted to go to Japan, China and/or India. North, Central and South America proved to be a barrier Columbus could not get around. He did not recognize that he had discovered a New World as far as Europe was concerned, and he kept approaching the New World in the middle of this massive barrier to east-west sea travel.

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According to the problemlet the two numbers be "x" and "y"then x-y=72andx/y=4x=4ysubstitute it in first onethen x-y=724y-y=723y=72y=72/3=24from x-y =72x-24=72x=72-24x=48

hence x=48 and y=24

p:q=3:4q:r=6:5r:s=7:2so p:q:r:s=63:84:70:20total 12324 so amount of q=84/237 *12324=4368

Let the denominator be xthen, numerator = x-6

according to question ,

=> (x-6)+3/x = 2/3=> (x-6+3)/x = 2/3=> (x-3)/x = 2/3

=> 3(x-3) = 2x => 3x-9 = 2x => 3x-2x = 9=> x = 9. (denominator)

numerator = x-6 => 9-6 = 3

then , fraction = 3/9

2nd term=a+d=86th term=a+5d=20so 4d=12so d=3so a=5so 20th term=a+19d=5+19*3=57+5=62

i.) 2/16=1/8now, (1/8)÷2 = 1/(8×2) = 1/16ii.) (4/8)÷2= (1/2)÷2= 1/(2×2) = 1/4iii.) (4/22)÷2 = (2/11)÷2 = 2/(11×2) = 2/22 = 1/11iv.) (12/14)÷2 = (6/7)÷2 = 6/(7×2) = 6/14 = 3/7

5n-1= 95n= 9+1= 105n= 10n= 10/5= 2Answer

thanks....

LHS = ( 1 + sin∅ + cos∅)²

use formula , ( a + b + c)² = a² + b² + c² + 2( ab + bc + ca)

= 1 + sin²∅ + cos²∅ + 2( sin∅ × 1 + sin∅× cos∅ + cos∅ × 1 )

we know , sin²∅ + cos²∅= 1

so,

= 1 + 1 + 2sin∅ + 2cos∅ + 2sin∅.cos∅

= 2 + 2sin∅ + 2cos∅ ( 1 + sin∅)

= 2( 1 + sin∅) + 2cos∅( 1 + sin∅)

= 2( 1 + sin∅) ( 1 + cos∅) = RHS

you took some mistake in your question. question is ,proved that( 1 + sin∅ + cos∅)² = 2( 1 + sin∅ )( 1 + cos∅)

The Europeans for many years wanted to discover a sea route to India. India was a spice haven and was in great demand in Medieval Ages. Trade occurred through land mostly. Europeans had to pay money to the peopleof the region from where their trade goods were transported. This led to a very high prices of spice in Europe. So they desperately needed to find a new sea route to minimize this cost. Portuguese were the first to find a sea route to India.

n(n+1)(4n²+2n)(n+1) +3n= 2n(2n+1)n(n+1)(n+1)+3n= 2n²(n+1)²(2n+1) +3n=n(2n(n+1)²(2n+1)+3)

But it's wrong answer I had also done but it say wrong

By the way thanks

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We know that (a+b)^2= a^2+b^2+2abso

Using (a+b)^2 = a^2+b^2+2ab

= 16m^2 + 25n^2+ 40mn + 25m^2 + 16n^2 + 20mn

=41m^2 + 41n^2 + 60mn

Let the radius of the spherical steel ball be 'X'Then the volume of the spherical steel ball=4/3πr³=4/3π(X)³Let the radius of the small spherical balls be 'x'Then, Volume=4/3π(x)³According to question:-4/3π(X)³=8[4/3πx³]4/3(X)³=32/3x³(X)³=8x³X=2xTherefore ratio- 1:2

check kar Raha tha sahi hai yaa fake mast hai

angle BCD=30+30=60which is same as that of angle ABCthey are alternate anglesonly when AB parallel to CD can the alternate angles be equal.hence proved.

sum of the angles around apoint is 360°then 60+x+2x+2x=3605x=300x=60°

Given ratio of sum of n terms of two AP’s = (7n+1):(4n+27)Let’s consider the ratio these two AP’s mth terms as am : a’m →(2)Recall the nth term of AP formula, an = a + (n – 1)dHence equation (2) becomes,am : a’m = a + (m – 1)d : a’ + (m – 1)d’On multiplying by 2, we getam : a’m = [2a + 2(m – 1)d] : [2a’ + 2(m – 1)d’]= [2a + {(2m – 1) – 1}d] : [2a’ + {(2m – 1) – 1}d’]= S2m – 1 : S’2m – 1= [7(2m – 1) + 1] : [4(2m – 1) +27] [from (1)]= [14m – 7 +1] : [8m – 4 + 27]= [14m – 6] : [8m + 23]Thus the ratio of mth terms of two AP’s is [14m – 6] : [8m + 23].

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