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3 cos 68. cosec 22 - 1/2 tan 43 . tan 47. tan 12. tan 60 . tan 78

⇒3 sin 22 . cosec 22 - 1/2 cot 47 .tan 47 .cot 78 .√3 . tan 78

(since cos 68 = sin 22, tan 43 = cot 47,tan 12 = cot 78 and tan 60 =√3)

⇒3 * 1/cosec 22 * cosec 22 - 1/2 cot 47 * 1/cot 47 . cot 78 . 1/cot 78 *√3

⇒3 -√3/2

⇒(6 -√3)/ is the answer 2

x^2/5/3+y^2/5/2=1y=mx+-√5m^2/3+5/2passing through (1,2)4m^2+24m-9=0M1+m2=-6and m1m2=-9/4tan^2A=(m1+m2)^2-4m1m2/(1+m1m2)^2=144/5tanA=12/√5A=tan^-1(12/√5)

Use parametric differentiation to do it first calculate dy/d(theta) =bcos() now dx/d(theta)=-asin() now y`=-bcos/asin and then dy`/d(theta)= -b/a×(-sin^2-cos^2)/sin^2=bcosec^2/a now d^2y/dx^2=(bcosec^2/a)-asin=-b/a^2 cosec^3

please find the common difference

x = at²

y = 2at

dy/dx

d(2at)/ d(at²)

divide by dt

d(2at)dt/dt d(at²)

2a/ 2at

1/t

Any quadratic equation having a and b as zeroes can be written as

x² - ( a + b)x + ab = 0

x² - ( 1/4 + 1) x + 1/4 × 1 = 0

x² - 5x/4 + 1/4 = 0

4x² - 5x + 1 = 0

1+sin^2 theta=3 sintheta cos theta (we know that sin^2 theta + cos^2 theta =1)

= ( sin^2 theta + cos^2 theta ) + sin ^2 theta = 3 sin theta cos theta

= sin^2 theta + cos^2 theta + sin ^2 theta = 3 sin theta cos theta

= cos^2 theta + 2 sin^2 theta = 3 sin theta cos theta

On dividing by cos^2 theta, we get

= 1 + 2 tan^2 theta = 3 tan theta

Let tan theta = b

2b^2 - 3b + 1 = 0

= (2b-1)(b-1) = 0

b = 1 or 1/2

So, tan theta = 1 or 1/2.

(1-cosx+sinx)/(1+cosx+sinx)=(2sin^2x/2+2sinx/2cosx/2)/(2cos^2x/2+2sinx/2cosx/2)=2sinx/2(sinx/2+cosx/2)/2cosx/2(sinx/2+cosx/2)=tanx/2

it's shortcut. hope u like this answer

i) Let the 1st term of the AP be 'a' and its common difference be 'd'

ii) As the number of terms are odd, the nth term is (2n + 1)

iii) Hence nth term (last tern) is: a + (2n + 1 - 1)d = a + 2nd

iv) So Arithmetic mean between 1st & last term is:(a + a + 2nd)/2 = 2(a + nd)/2 = a + nd

v) The middle term of (2n + 1)th term is: (2n + 1 + 1)/2 = (n + 1)Hence middle term is (n + 1)th term = a + (n + 1 - 1)d = a + nd

Thus from steps (iv) & (v),

Middle term = AM of 1st and last terms.

Sum = (100 * 210)/(15/4 * 7/3)

= 21000 * 4/35

= 2400.

use dividend=quotient*divisor+remainder Answer is 2800

quotient*divisor=dividend28*100=2800

use dividend=quotient*divisor+remainder answer is 2800

quotient*divisor= divident28*100=2800

the answer is 2800 use this answer

dividend is 2800 becoz it is due to dividend=divisor*quotient

quotient*divisor=dividend 28*100=2800

100×28=2800divisor× quotient=divident

use formula : Dividend= divisor*quotient + remainder then answer would be 100*28+0=2800

dividend=divisor*quotient+remainder= 100*28+0=2800+0=2800

Divident=quotient*divisor +remainder Formula is a=bq+r And answer is 2800

Let divident be xas we know, x÷100=28now, we transposed 100 in to R. H. S. then we get, x=28*100x=2800

2800 is the answer of this question

twenty eight hundred

28 X 100 + 0= 2800 dividend

quotient*divisor=divident 28*100=2800

quotient*fivisor=divident 28*100=2800

2800dividend=divisor*quotient+remainder

dividend =answer is 2800

dividend=quotient*divisor+remainder answer is 2800

dividend =divisor × qutent + remainderdividend=100×28+0=2800

dividend=quotienti division+remainder answer is 2800

the correct Answer is 2800

is. question answer zero

if the divisor qootient and remainder are 100,28 and zero respectively then the dividend is

100*28+0 = 2800 so the dividend is 2800

use divide =quentent divisor+reminder and answer is 2800

use dividend=quotient*divisor+ remainderanswer is 2800

2800 is the right answer

quotient ×divisor =divident 28×100=2800

use dividend = quotient*divisor+remainderanswer is 2800

use dividend=question*divisor+remainder Answer is 2800

2800 is. the answer

By using Dividend= Divisor* Quotient + Remainder , dividend = 100*28+0= 2800

2800 is the right answer........

the dividend is 2800

28*100=2800 is right answer

Dividend_is_2800 Becoz_it_DueDividend=Divisor*Quotientcorrect_answer

divident=divisor*quotient+remainder2800

this answer is 1000%sure 2800

2800 is the answer of the question

2800 is the answer i am correct

28×100=2800quotient*divison=dividend

the answer is 2800 it's correct answer

if the divisor qootien and remainder are 100,28 and zero respectively then the dividend is

dividend is 3.5714285714

The divine r is 3.5714285714

dividend=divisor * quotient +remainderthen we get dividend= 100*28+0 =2800+0 =2800

quotient ❌ divisor= dividend 28❌100= 2800

28×100dividend =divisor*quotient+remainder

2800 as dividend= diviser* quotient+ reminder

2800 is the correct answer

28*100dividend =divisor *quotient +reminder

use dividend=divisor×quotient+remainder therefore answer is 2800

my answer is 2800 bro am I right

use divided = question*divisor+remainder answer is 2800

Dividend=divisor×quotient+remainder =100×28+0dividend=2800 ✓

I don't know about it

right answer is 2800

2800 is the answer quotient *divisor +reminder

100*28=2800this is right answer.

use dividend=quotient*dividor+remainder answer is 2800

dividend=divisor*quotient+remainder,so,100*28+0=2800

28*100=2800 use is Answers

Dividend=Queficient *divisor+remainder 2800

if the divisor qootint and remainder are 100,28 and

answer is 2800 and so on

Dividend=quotient*divisor+remainder answer is 2800

2800 divided answer this question on my mind

Number of stidents that passed= 42 * 6/7 = 36 students

Number of students that failed= 42 - 36 = 6.

15,30,45,60,75,90,105,130,135,150so average=(15+30+45+60+75+90+105+120+135+150)/10=825/10=82.5

Herea= 6d= 6n= 10so Sn= n/2(2a+(n-1)d)

= 5(12+54)66*5= 330