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Given expression (3a^2 + 2a*5 - 4)/4 +5a - 2

For a = 4Value of expression = (3*4*4 + 2*4*5 - 4)/4 + 5*4 - 2= (48 + 40 - 4)/4 + 20 - 2= 84/4 + 18= 21 + 18= 39

pqr = 1

r = 1/pq

1/r = pq

(1/1+p+q^-1) + (1/1+q+r^-1) + (1/1+r+p^-1)

(1/(1+p+1/q) + (1/(1+q+pq) + (1/(1+1/pq+1/p)

(1/(q+pq+1/q) + (1/(q+pq+1) + (1/(q+pq+1/pq)

(q/q+pq+1) + (1/q+pq+1) + (pq/q+pq+1)

(q+pq+1) / (q+pq+1)

= 1

Let the vertices be as follows,A(-1,0) ; B(3,1) ; C(2,2); D(x, y)

The line segments that make up our parallelogram is AD is parallel to BC, and CD is parallel to AB. Since the definition of a parallelogram is a quadrilateral with 2 pairs of parallel sides, we can use this fact to find the coordinate to the 4 vertex. A pair of parallel side also means that these 2 lines have the same slope. So if we do this on both pairs of parallel lines, we should have 2 equations with 2 variables, which should be simple to solve.

Slope of CD =Slope Slope of AB(y - 2)/(x - 2) = (1 - 0)/(3 - - 1)(y - 2)/(x - 2) = 1/44(y - 2) = (x-2)4y - 8 = x-2equation #1: 4y - x = 6

A(-1,0) ; B(3,1) ; C(2,2); D(x, y)Slope of AD = Slope of BC(y - 0)/(x - -1) = (2 - 1)/(2 - 3)(y)/(x + 1) = 1/-1-1(y) = (x + 1)-y= x+1equation #2: y+x = - 1

We now we have 2 equations with 2 variables, and we can use any method (substitution, linear combination, matrix)to solve for the x and y coordinates.

equation #1: 4y - x = 6equation #2: y + x = - 1

Add equation 1 to equation 2

equation 1: 4y - x = 6equation 2: y + x = -1eq 1 + eq 2: 5y = 5y = 1

Using the equation#2 to solve for x:

y + x = -11 + x = - 1x=-2

So the 4th vertex will be (-2,1)

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By using distance formula, take two points B(8,2) and D(p,3) distance formula is √(x₂-x₁)²+(y₂-y₁)² in point B 8 is x₁ and 2 is y₁ in point D p is x₂ and 3 is y₂Now, =√(p-3)²+(3-2)² =√(p-8)²+(1)² =p-8+1 =p-7 ⇒p=7

The coefficient of x is -52.

-52 is the co efficient of x

a

-3 is the right answer......

a"0.6b."1.6c"15d"15

3÷5 = 0.65÷3 = 1.6673×5 = 155×3 =15

-3 ,is the right answer...

-3 is the right answer

-3 is the right answer

-3 is the right answer

-3 is the right answer

-3 is the right answer

-3 is the right answer

-3 is the right answer

No it is not trinomialbecause it can added and written as 6x+3y

No, is is not trinomialbecause it can be written as 6x+3y

This answer is right .thanks

tq

but there is( k-4)cube

Equation is a statement of an equality containing one or more variables. Solving the equation consists of determining which values of the variables make the equality true. Variables are also called unknowns and the values of the unknowns that satisfy the equality are called solutions of the equation

Thus (iv) 2x +1 = 15 is only equation

3 times a=3a2 more than 3 times a = 3a +2

3a+2 is the answer for your question

3 times a = 3a2 more than 3 times a=3a+2

181 is the right answer

do like this sun in photo

Like my answer if you find it useful!

tana=5/12=opposite/adjacentnowhypotenuse^2=opposite^2+adjacent^2hypotenuse^2=12^2+25^=144+25=169hypotenuse=13hencesecA=hypotenuse/adjacent=13/12

terms are 2x² , 3x and 1

other expression= 6x^3 -2xy +4y^2 -4xy +2y^2= 6x^3 -6xy +6y^2

Total number of students = 472Let number of students in each bus is n

Then,9n + 4 = 4729n = 472 - 49n = 468n = 468/9 = 52

Number of students in each bus is 52

2(28-6)=2(22)=44is the value

2(28-6)=2×22=44

=2×28-2×6=56-12=44

Average of 5 students is 10 years so total 10×5 = 50 years A student of 14 years drops out so remaining weight = 50 - 14 = 36 So average of 4 students = 36/4 = 9 years

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Thanks

thanks

No, (0,7) and (7,0 ) are two different points.

P is on y axis and Q is on x axis

aree. yaar question Kya hai answer kya de rahe ho

2x^2-8=( x+4)( 2x-2); x^2-5x+6; x^2-3x+2x+6; x( x-3)+2( x-3); ( x+2)( x-3); x=-2, 3

1st term 2x^2-8=2(x^2-4)= 2(x-2)(x+2)2nd term= x^2-5x+6=x^2-3x-2x+6=x(x-3)-2(x-3)(x-3)(x-2)LCM= 2(x-2)(x+2)(x-3)= 2(x^2-4)(x-3)

X=-2, 3 is correct answer

correct answer is área. 👉22

area of rectangle = L × B = 6 × 3 = 18area of square =( a)2 = ( 2 )2 = 4 Total of area = area of rectangle + area of square = 18 + 4 = 22

(6×3)+(2×2)18+422 sq. inches. ans.

A. terms are x²y and +2 B. terms are 3xy² and -7x²y

answer will be C....y=3cotx+5cosecx...

Original cost = ₹1120

Loss price = ₹ 28

Selling price = CP - Loss

Selling price = ₹1120 - ₹28 = ₹1092

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Number of rows=xNumber of benches in each row=x/3Total benches=x*x/3=x²/3

Number of of students accommodate in 1 bench=4Number of of students accommodate in x²/3 benches=4*x²/3=4x²/3

Wanda sits in the seat next to the last seat in the last row in Room Thirteen. She sits there because her feet are normally caked with dry mud and that corner of the classroom is usually dirty with mud.

Plz mention which class and which chapter as all might not have the same syllabus...

thanks

thank u bro

(i) ans=Answer:

See a solution process below:

Explanation:

First, find the y-intercept:Setx=0and solve fory:

(2⋅0)−3y=9

0−3y=9

−3y=9

−3y−3=9−3

y=−3or(0,−3)

Next, find the x-intercept:Sety=0and solve forx:

2x−(3⋅0)=9

2x−0=9

2x=9

2x2=92

x=92or(92,0)

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+3)^2-0.075)((x-(9/2))^2+y^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(2x - 3y - 9)(x^2+(y+3)^2-0.075)((x-(9/2))^2+y^2-0.075)=0 [-20, 20, -10, 10]}

( 2x - 3y )^9 = (9C 4)(2x)^6(3y)^3= (216) (64x^6)(27 y^3)= 373, 243( x^6)( y^3)

cosec(x) = 1/sin(x), and

cot(x) = cos(x)/sin(x) .

So, cosec(x)cot(x) = cos(x)/sin^2(x).

∫cos(x)/sin^2(x) dx : substitute sin(x) = u, du/cos(x) = dx.

Substituting in, we have

∫u^(-2)du = -u^(-1) + C.

Since u = sin(x), we have that ∫ = -1/sin(x) + C,

or ∫ = -cosec(x) + C.