SIONS OF BINOMIAL ANDTupel DETERMINING THE NUMBER OF TERMS IN THE EXPA

1.	SIONS OF BINOMIAL ANDTupel DETERMINING THE NUMBER OF TERMS IN THE EXPANSIONS OF AMEXPRESSIONSEXAMPURT Find the number of terms in the expansions of the following:(i) (2x - 3y)(ii) (1 +5.2 x) + (1 -52x)=1
Answer» (i) ans=Answer: See a solution process below: Explanation: First, find the y-intercept:Setx=0and solve fory: (2⋅0)−3y=9 0−3y=9 −3y=9 −3y−3=9−3 y=−3or(0,−3) Next, find the x-intercept:Sety=0and solve forx: 2x−(3⋅0)=9 2x−0=9 2x=9 2x2=92 x=92or(92,0) We can next plot the two points on the coordinate plane: graph{(x^2+(y+3)^2-0.075)((x-(9/2))^2+y^2-0.075)=0 [-20, 20, -10, 10]} Now, we can draw a straight line through the two points to graph the line: graph{(2x - 3y - 9)(x^2+(y+3)^2-0.075)((x-(9/2))^2+y^2-0.075)=0 [-20, 20, -10, 10]} ( 2x - 3y )^9 = (9C 4)(2x)^6(3y)^3= (216) (64x^6)(27 y^3)= 373, 243( x^6)( y^3)

SIONS OF BINOMIAL ANDTupel DETERMINING THE NUMBER OF TERMS IN THE EXPANSIONS OF AMEXPRESSIONSEXAMPURT Find the number of terms in the expansions of the following:(i) (2x - 3y)(ii) (1 +5.2 x) + (1 -52x)=1

Answer»

(i) ans=Answer:

See a solution process below:

Explanation:

First, find the y-intercept:Setx=0and solve fory:

(2⋅0)−3y=9

0−3y=9

−3y=9

−3y−3=9−3

y=−3or(0,−3)

Next, find the x-intercept:Sety=0and solve forx:

2x−(3⋅0)=9

2x−0=9

2x=9

2x2=92

x=92or(92,0)

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+3)^2-0.075)((x-(9/2))^2+y^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(2x - 3y - 9)(x^2+(y+3)^2-0.075)((x-(9/2))^2+y^2-0.075)=0 [-20, 20, -10, 10]}

( 2x - 3y )^9 = (9C 4)(2x)^6(3y)^3= (216) (64x^6)(27 y^3)= 373, 243( x^6)( y^3)