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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
draw a closed curve having line segment |
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| 2. |
(i) A curve is said to be closed if its ends are joined |
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Answer» Yes, a curve is said to be closed if its ends are joined. |
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| 3. |
30. A bucket is in the form of a frustum of a cone and hold 28.490 litres of water. Theradii of the top and bottom are 28 em and 21 cm respectively. Find the height of thebucket |
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Answer» Here,The volume = 28.49cmRadius r1 = 28 cmRadius r2 = 21 cm so volume of the frustum =1/3 πh [r1²+r2²+r1 x r2]so...1/3 x 22/7 x h [28²+21²+28x21]28490=5698/3x hh = 15 |
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| 4. |
A bucket is in the form of a frustum with a capacity of 45584 cubic cm. If the radii ofthe top and bottom of the bucket are 28 cm and 7em respectively, find its height andsurface area. |
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| 5. |
A vertical tower stands on a horizontal plane-and is surmounted by a vertical flagstaff ofheight 5 m. At a point on the plane, the angles of elevation of the bottom and the top ofthe flagstaff are respectively 30P and 60° Find the height of the tower. |
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| 6. |
if we divide 96 chocolates between Ravindraand Sreenivas rad in the ration: 7 thenfind the no: Of chocolates, did Ravindraget |
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Answer» Number of ravindra got chocolate is 40 share of ravindra in chocolate 96×5/12=40 |
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| 7. |
) वह संख्या, जो 8000 से 160 % अधिक है |
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Answer» 8000 + 8000×160/100 = 8000 + 12800 = 20800 |
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| 8. |
capacity of a oboidal tank is 50000 litres of water. Find the breadds of the tf its leagth and depth ane5 m and 10 m. |
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| 9. |
The capacity of a cuboidal tank is 50000 litres of water. Find the breadth of the tank.if its length and depth are respectively 2.5 m and 10 m.5. |
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Answer» 1000 L = 1 m³ so, 50000L = 50m³ now volume = L*B*H => 2.5*10*B = 50=> B = 50/25 =2m |
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| 10. |
5. The capacity of a cuboidal tank is 50000 litres of water. Find the breadth of the taiif its length and depth are respectively 2.5 m and 10 m. |
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| 11. |
If x<-6, then the minimum value of Ix + 2l isbi 5 |
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Answer» when x < -6 |x+2|<|-6+2|< |-4| <4 minimum value is 4 |
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| 12. |
Write the coordinates of a point P on x-axis which is equidistant from thepoints A(-2, 0) and Bi(6, 0) |
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| 13. |
a simple closed curve made up of only.....................is called a polygon |
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| 14. |
Blazed by the three animalsand oustum of a cone holds 28.490 liters of watertively. Findheight of thetopne bucket bottom are 28cm & 21cm respec |
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Answer» R = 28 cmr = 21 cmLet height of frustum be h cm ∴Volume held by bucket = 28.490 litres = 28490 cm³Also, Volume of frustum = π(R²+Rr+r²)h/3=> 28490 = 22*(784+588+441)*h/(3*7)=> 1813h =28490*21/22=> h = 27195/1813 = 15cm |
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| 15. |
s Give an example of a horizontal plane and a vertical plane from your environment |
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Answer» 1. Ceiling of a room is an example of a horizontal plane in our environment. 2. Wall of a room is an example of a vertical plane in our environment. |
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| 16. |
Give an example of a horizontal plane and a vertical plane from yourenvironment. |
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Answer» ceiling of the room is the example of the horizontal plane.wall of the room is the example of the vertical plane in the surrounding. |
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| 17. |
X^2-(2+i)X-(1-7i)=0 |
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Answer» x^2-(2+i)x-=1-7i)=0; x^2-2x-ix =1+7i=0; x(x-2)-ix=1+7i; x( x-2)=1; x+2=1; x=7; x^2-2x-1; a=1; b=2; c=-1; -b+-Vb^2-4ac/2a; -2+-V(2)^2-4(1)(-1)/2(1) -2+-V4+4/2; -2+-2V2/2=1-+V2; (1+V2, 7)(1-V2,7) |
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| 18. |
6. Find the modulus of3+4iI-7i |
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| 19. |
Find the cube root of i) 8000 i) 13824 |
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Answer» 1. 20*20*20 = 8000. Therefore 20 is ans.2. 24*24*24 = 13824. Therefore 24 is ans. |
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| 20. |
The average marks obtained by 5 students is55. The average score of the top threeperformers out of these five is 65. Whatisthe average score of the other two? |
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| 21. |
(x - 7)^((x^2 - 29*x %2B 154)/(x^2 - 12*x %2B 32)) |
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Answer» 1 is the correct answer of the given question |
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| 22. |
The value of v 27-ě-4+4th wilbe-(A) V3(B) 2 3(C) 0(D)3/3 |
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| 23. |
1. Solve.a, 2x + 6-8 |
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Answer» 2x = 8-6 =2 x = 1 So the value of x is 1. |
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| 24. |
esin a horizontal plane are horizontal. |
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Answer» because slope is 0 , for all horizontal lines . |
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| 25. |
देHo Fsfld nemad ax tbx*+a |
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Answer» ax² + bx² + ay² + by² x² ( a + b) + y² ( a + b) ( x² + y²) ( a + b) |
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| 26. |
. Find the projection of the vector i+3j+ 7k on the vector 7i-j+8i |
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Answer» glt h |
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| 27. |
10, Prove that the sum ois a zero vector.f the vectors represented by the sides of a closed polygon taken in order |
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Answer» Lets take an example of a hexagon, and according to your question, vectorsa1, a2, a3, a4, a5, a6make the side of the hexagon in the order as shown in the figure. Now, from triangle law of vector addition, a1+a2=b1 b1+a3=b2 b2+a4=b3 b3+a5=b4 Also,b4=-a6 So,b4+a6 = 0 So, the vectors added in an order gave a null vector. Similarly,If a set of vectors taken in a given order gives a closed polygon, then the resultant of these vectors, will be a null vector. |
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| 28. |
Prove that f(x)-bi is continous ax 0 |
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| 29. |
5 A truck carries 65 boxes. Each of these Bo2es OUpackages contains 15 toy soldiers. How many toy soldiers are being carried in the truck?o The capacity of a water tank in a housing colony is 64 kilolitres. This is sufficient for 80 families inthe colony for 4 days. What is the average quantity of water used per day per household?ls 8 g of ingredients, how many cookies can be made with |
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Answer» capacity of water tank=64kilolitresno. of families using this water=80no. of days it is used=4water used by 1 family in 1 day=64/(80×4)=64/320=0.2kilolitres=200litres |
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| 30. |
16) Find the equation of the line passing through the point A(5,4,3) and parallel to the line,x-1 y-7 z342 |
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Answer» why ((1)2(-5) why ((1)(2)(-5)) |
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| 31. |
the average markes obtained by 5 studentis 55. the average of the top three performsout of these is 65. what is the average scoreof the other two ? |
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| 32. |
Solve for(1)3x + 5 = 2x+8 |
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Answer» 3x + 5 = 2x + 83x - 2x = 8 - 5 (by transposing)x = 3 3x + 5 = 2x + 83x - 2x = 8 - 5 x = 3 3x+5=2x+8 .....(Rearranging)3x-2x=8-5x=3Thus,the value of x in the given equation is 3. |
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| 33. |
x^2 - 12*x %2B 32 |
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Answer» x²-12x+32=0sum=-12; product=32numbers=-8,-4x²-4x-8x+32=0x(x-4)-8(x-4)=0x=4,8 |
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| 34. |
1. For what value of 'a' so that thevectorf-(ax+2y 42)j (2x-3y+3z)j+(3x + 2y -2z)kis solenoidal.(A) 3(B) 4(C) 5(D) 6 |
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| 35. |
Find the HCF of the following by prime factorisation method :(a) 25, 65(e) 459, 527i) 930, 942,948 (j) 512, 1108, 2012(b) 48, 64(1) 112, 532, 476(c) 175, 180(g) 540, 315, 360(d) 210, 480(h) 476, 1386,1246 |
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| 36. |
j) Write the direction cosines of the line-=--, z=2.x-22y-5=, 2=2. |
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| 37. |
.12 keand 16 kg: What is the total1. A coolis carries three suitcases weighing 11carried by the coole? |
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Answer» Total weight of suitcases =23/2 + 51/4 + 76/5 =230+255+304/20=789/20=39.45kg |
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| 38. |
L IR निज अल ऊै,.. ..सिद्ध कीजिए कि 8x = 2y 2]5. सभी खंड कीजिए।(क) निम्न समीकरण युग्म को रैखिक समीकरणों के युग्म में बदलकर हलकीजिए 14]1 12 7 & iy + = + oo+ 8 J-2y) B uEct . SRyजहाँ, 2८ + 3y = 0T 3x- 2y रू0 है।- Y\ -4 जा |
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Answer» hit like if you find it useful |
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| 39. |
Jl i oi andIf PR 6.4 cm, then find PT). The angle of elevation of the top of a building from the foot of a tower is 30 and the angle ofelevation of the top of the tower from the foot of the building is 60° If the tower is 50 m high, thefind the height of the building |
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Answer» Let AB be the height of the building. BC be the distance between the foots of the building and the tower. Elevation is 30° and 60° from the tower and the building respectively. ATP In right ΔBCD, tan 60° = CD/BC ⇒ √3 = 50/BC ⇒ BC = 50/√3 also, In right ΔABC, tan 30° = AB/BC ⇒ 1/√3 = AB/BC ⇒ AB = 50/3 Thus, the height of the building is 50/3. |
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| 40. |
Solve2x 30S18 |
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| 41. |
J.4lo find the value of m.3. lf the point Px.y) is equidistant from the point A(5,1) and B(-1,5),w that 3x-2y |
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| 42. |
6 %2B 32 |
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Answer» 32+6=38ans is thrityeight 38 answer is thirty-eight 32+6=38 right answer |
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| 43. |
a^6 %2B 32*a^3 - 64 |
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Answer» a^6+ 32a³– 64 a^6+ 8a³– 64 + 24a³ ⇒(a²)³+ (2a)³+ (- 4)³- 3×(a²)×(2a)×(- 4) … (i) We use the identity a³+ b³+ c³- 3abc = (a + b + c) (a²+ b²+ c²- ab - bc - ca) substitution in (i) we get (a²)³+ (2a)³+ (- 4)³- 3×(a²)×(2a)×(- 4) = (a²+ 2a - 4) (a⁴+ 4a²+ 16 - 2a³+ 8a + 4a²) ⇒(a²+ 2a - 4) (a⁴+ 8a²+ 16 - 2a³+ 8a) (a²+ 2a - 4) (a⁴- 2a³+ 8a²+ 8a + 16) |
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| 44. |
2 ^ 2 x - 3 \cdot 2 ^ ( x %2B 2 ) %2B 32 = 0 |
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| 45. |
x^2 - x %2B 2=32 |
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Answer» x^2-(x-2)^2=32x^2-x^2-4+4x=324x=32+4x=36/4x=9 |
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| 46. |
27. Prove that: (sin 6 + 00860 6) + (८08 0 न 860 605 > 7 + दा 9+ cot? 0. |
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| 47. |
| - 0089() (00860 9-०० पद८5:७ |
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| 48. |
6. 00860% - 00% बराबर होगा |
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Answer» please do like if you found it helpful |
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| 49. |
sin 30° + tan 45° - 00860(iv) T e- sec 30° + cos 60° + cot 45° |
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| 50. |
S.D.Prove that cos 10 cos 50 cos 70° =3/8 |
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Answer» To prove:cos 10° cos 50° cos 70°=√3/8LHS,cos 10° cos 50° cos 70°=cos(60-Q) cosQ cos(60+Q) where, Q=10 such that cos(60-Q) cosQ cos(60+Q)=1/4(cos 3Q |
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