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S.D.Prove that cos 10 cos 50 cos 70° =3/8 |
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Answer» To prove:cos 10° cos 50° cos 70°=√3/8LHS,cos 10° cos 50° cos 70°=cos(60-Q) cosQ cos(60+Q) where, Q=10 such that cos(60-Q) cosQ cos(60+Q)=1/4(cos 3Q |
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