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2x+7=2(-2)+7=3; x^2-2=(-2)^2-2=4-2=2; 3x-2, 3(3)-2=9-2=7;

2,x,18thenx=(2+18)/2x=10ans

2,X,8then,X=(18-2)/2X=8is the right answer

2,x, 18 are in continued proportion so 2/x= x/18or x × x = 2× 18or x^2 = 36or x = 6

x= 6 is the right answer

Completing the Square is a method used to solve aquadratic equationby changing the form of the equation so that the left side is aperfect squaretrinomial.

To solveax2+bx+c=0by completing the square:

1. Transform the equation so that the constant term,c, is alone on the right side. 2. Ifa, the leading coefficient (the coefficient of thex2term), is not equal to1, divide both sides bya.

3. Add the square of half the coefficient of thex-term,(b2a)2to both sides of the equation.

4. Factor the left side as the square of a binomial.

5. Take thesquare rootof both sides. (Remember:(x+q)2=ris equivalent tox+q=±r.)

6. Solve forx.

1204. hsfcbwhgvwvhgvwbshgce

12r*r - 25r + 12 = 0 12r*r - 16r - 9r + 12 = 0 4r(3r-4)-3(3r-4) = 0 (4r-3)(3r-4) = 0 so r=3/4 or 4/3

87/27= as 27*3= 81so 3 and remainder= 6

98/32= 32*3= 96so quotient = 3remainder = 2

Given:

A circle with Centre O, P is the midpoint of Arc APB. PT is a tangent to the circle at P.

To Prove:

AB || PT

Construction: join OA ,OB, & OP

Proof: OP ⟂PT

[Radius is ⟂ to tangent through point of contact]

∠OPT= 90°

Since P is the midpoint of Arc APB

Arc AAP =arc BP

∠AOP = ∠BOP

∠AOM= ∠BOM

In ∆ AOM & ∆BOM

OA= OB= r

OM = OM (Common)

∠AOM= ∠BOM (proved above)

∠AOM≅∠BOM (by SAS congruency axiom)

∠AMO = ∠BMO (c.p.c.t)

∠AMO + ∠BMO= 180°

∠AMO = ∠BMO= 90°

∠BMO = ∠OPT= 90°

But, they are corresponding angles. Hence, AD||PT

answer of a is 3/5 and answer of b is 1/6

the correct answer is a 3/5 b 1/6

answer of a is 3/5 and b is 1/6

this qus is wrong due to which u can't solve this qus

thanks

Given:- Perimeter of the parallelogram=22 cm∴Perimeter=2×(longer side+ shorter side)=>22=2×(6.5+shorter side)=>shorter side=4.5 cm ans.

=3x-[2x-{x+(2y-x-y)}]=3x-[2x-{x+2y-x-y}]=3x-[2x- x -2y+ x +y]=3x-[2x+y]=3x -2x -y=(x- y)

27x³+ y³+ z³- 9xyz = (3x)³+ y³+ z³- 3 × (3x) × y × z = [3x + y + z ][(3x)²+ y²+ z²- (3x) × y − y × z − z(3x)] [Since (a + b + c )(a²+ y²+ z²- ab−bc−ca)] = [3x + y + z ][9x²+ y²+ z²- 3xy − yz − 3zx]

Use a² - b² = (a-b) (a+b)

4p² - 9q²(2p)² - (3q)²(2p - 3q) ( 2p + 3q)

Shape = Square Side of the square = 9 cmArea = Side × Side = 9 cm × 9 cm = 81 sq.cm

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we can check via following way 2×8 = 16 = 4×4 ac=b*b so yes these 3 are in proportion.

Suppose his present age is xnowafter 10 yearshe will be y years oldnowy= 5x

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thnku

1 9 4 3 5 7 2 8 is the answer of the

1943572is the correct answer of the following8

1 94 35 72 8is the correct answer

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2XY7 is divisible by 3sum of digit should be multiple of three2+X+Y+7=9+X+Yif we add 3 to the 9 it will be multiple of 3.Therefore, x+Y = 3The least value of (X+Y) is 3.

2XY is divible by 3sum of digit should be multiple of three2+X+Y+7=9+X+YIf we add 3 to the 9 it will be multiple of 3There fore, X+Y=3The least value of (X+Y)is 3

3 is the correct answer of the given question is

x^2+y^2=a^sin^2+a^2cos^2=a^2(1)=a^2as sin^2+cos^2=1

x/a + y/b = 2ay + xb = 2ab----------( 1 )

ax - by = a² - b²---------( 2 )

from-----( 1 ) &-------( 2 )multiply ( 1 ) by "a" ( 2 ) by "b"

abx + a²y = 2a²babx - b²y = ba² - b³-------------------------------------------------y(a² + b²) = 2a²b - ba² + b³

y(a² + b²) = a²b + b³

y(a² + b²) = b(a² + b²)

y = b [ put in -----( 1 )]

we get,

ay + xb = 2ab

a(b) + xb = 2ab

xb = 2ab - ab

x = ab/b

x = a

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x + 1/x = 9

Sqauring both sides

x² + 1/x² + 2 = 81

x² + 1/x² = 79

Sqauring again

x⁴ + 1/x⁴ + 2 = 79²

x⁴ + 1/x⁴ = 6241 - 2 = 6239

We know √5 is irrational.

Let 3 + √5 be rational

So, 3 + √5 = r, where r be any rational

√5 = r - 3

this is an absurd result because LHS is irrational and RHS is rational therefore a contradiction to our assumption that 3 + root 5 is irrational so 3 + √5 is irrational

Yes the statement is true because complex number are in form of a+bi, where i² = -1 and a, b belongs to set of real numbers .To get real numbers set b = 0 there form will be only a i.e. the set of real numbers

16 / 6 = 8 / 3 = 2 2/3

Let the no be x.4x=4 times of the no.12-4xX2=square of the noX2=12-4xX2+4x-12=0By solving,(x=2&x=-6)Answer =-6

SoP/6= 6/9p/6= 2/39P= 36P= 4

Ans hoba 611.8333333333 Ans to Right

answer is 611.83 and soon

your answer is 611.833

Symbol of Mole is Mothanks

option (b) Mo is the correct answer

Thanks

Given it's one root of the equation x² - 2kx - 6 = 0

one of its root x = 3 for finding the value of k put the value of x in this equation.

(3)² - 2k(3) - 6 = 0

9 - 6k - 6 = 0

6k = 3

k = 3/6

k = 1/2

hence,the value of k = 1/2

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