Saved Bookmarks
| 1. |
11, गुणनखंडन कीजिए: 27 + +293yz |
|
Answer» 27x³+ y³+ z³- 9xyz = (3x)³+ y³+ z³- 3 × (3x) × y × z = [3x + y + z ][(3x)²+ y²+ z²- (3x) × y − y × z − z(3x)] [Since (a + b + c )(a²+ y²+ z²- ab−bc−ca)] = [3x + y + z ][9x²+ y²+ z²- 3xy − yz − 3zx] |
|