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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
CULLERAU11. True or FalseThe #'s below are equivalent.4%100(a) If your answer is TRUEcolor the head/face grey.(b) If your answer is FALSEcolor the head/face brown. |
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Answer» A) trueThis is the answer Yes this statement is true yes this statement is true Option A is the answer. the answer to the question is true A is the correct answer the answer is truethanks B is the correct answer...... 😆😆🤗 false is the right answer the right answer is (b) FALSE If your answer false color the head B is the false is the best answer |
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| 2. |
hj |
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Answer» 55 ,69,85,61 that's The answet 5 Best Funny Paheliyan | Part 7 | Paheliyan in Hindi with Answer | Hindi Paheli – Mr. Gyan. 5 Best Funny Paheliyan | Part 7 | Paheliyan... HJ may refer to: Science, technology, and mathematics[edit]. Hall–Janko group, a mathematical group; Heterojunction, the interface... |
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| 3. |
6) Two and a quarter metreighteen and a half metresns. |
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| 4. |
Exercise 12.2L Threemore than twice a number is equal to four less than the number. Find thenumber |
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Answer» According to thequestion 2x+3= x-4 2x-x= -7x= -7please like the solution 👍 ✔️ Let the number be x. Three more than twice the number 2x + 34 less than the number x - 4 2x + 3 = x - 42x - x = -4 - 3 x = -7 |
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| 5. |
Rs 355 have been divided among A, B, Cin such a way that A had Rs 20 morethan B and C had Rs 15 more than AHow much was C's share? |
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Answer» Let the money of B is x so, A has x+20 and C has (x+20) +15 = x+35 summing all together = (x)+(x+20)+(x+35) = 3x+55 = 355=> 3x = 355-55 = 300=> x = 300/3 = 100. so, C has x+20+15 = 135 |
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| 6. |
0.60.50.22-S2-6.362-20 -a322x +30llz -18H12tate b- |
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| 7. |
C.1. In the given figure:a) HI Klb) HJ KJ8I. A..AHIJ A KIJtate the congruence criterion used. |
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Answer» this is no correct answer |
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| 8. |
The length of Femur, the longest bone in teWrite this as a mired1012human body isnumber.(a) 5(c) 50(b) 250(d) 100 |
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| 9. |
| Five lakh forty thousand six hundredfifty 500 |
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Answer» 5,40,650 is answer of the question 5,40,650your answer is 5,40,650 |
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| 10. |
(x-)c + s0, (x10,()+)and50e four angles of a quadrilateral are 2four angles.(i İPh |
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| 11. |
(id The four angles of a quadrilateral are 2 10) 30)50and20.Findalltfour angles. |
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| 12. |
14. Divide 25000 between A, B and C so that A getsof B and C gets 2 of A and B. |
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Answer» as per given conditions we will geta=7b/8 (1)a/b=7/8 as per other conditionc=2(a+b)/3 (2)a+b+C =25000(3) by putting the value of (1) and (2) in (3) 7b/8+b+2(a+b)/3=250007b/8+b+2(7b/8+b)/3=25000(7b+8+b)(1+2/3)=25000(7b+8b)/8(5/3)=25000(15b/8)x5/3=2500075b/24=25000b=25000x24/75b=8000now a=7b/8a=7x8000/8=7000c=(a+b)x2/3c=(7000+8000)x2/3c=15000x2/3=10000 Answera=7000b=8000c=10000 Verificationa+b+c=250007000+8000+10000=25000verified |
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| 13. |
The four angles of a quadrilateral are in the ratio 1:2:3:4. Find the angles. |
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Answer» Let∠∠A = 2x∘.Then∠∠B = (4x)∘;∠∠C = (5x)∘and∠∠D =(7x)∘Since the sum of the angles of a quadrilateral is360o, we have:2x+ 4x+ 5x+ 7x= 360∘⇒18x= 360∘⇒x= 20∘∴∠∠A= 40∘;∠∠B= 80∘;∠∠C= 100∘;∠∠D= 140∘ |
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| 14. |
16. In the given figure, a circle of diameter 21 cm is given. Instde this circle.two circles with diameters 2and of the diameter of the big circle have233s shown in the given figure. Find the area of the shadedregion.Hint. Required area 211(22 21,2122 x7 x7Hint. Required area-l(22x2×2)-(7x7x7)-(,cmecm(722 |
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| 15. |
2°= 128, find the value oftate the tomuc |
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Answer» We know that2^7= 128by comparing it 2^7= 2^xx = 7 |
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| 16. |
Two roads cross each other at an intersectionforming four angles as shown in the fig.. If one ofthe angles is 40, what is the measurement ofother three angles? |
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Answer» Angle COB=40(Vertically opposite angles)Angle AOC=180-40(Angle sum property)=140Angle AOC=Angle BOD=140(Vertically opposite angles) |
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| 17. |
The four angles of a quadrilateral are in the ratio 3:4:5: 6. Find the angles. |
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Answer» Let the ratio be x so angles are3x, 4x, 5x, 6x , therefore sum of angles is 360°. 3x + 4x + 5x + 6x = 360°18x = 360°x = 20° So angles are,54°, 72°, 90°, 108° |
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| 18. |
2. The angles of a quadrilateral are in the ratio3:5:7: 9. Find the four angles. |
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| 19. |
Rs. 58 is divided among 150 children such that each airl and each boy gets 25 p and 50 p respectivelyThen how many girls are there?(1) 52(2) 54(3) 68(4) 62 |
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Answer» let no of girls be xthen no. of boys will be 150-xa/c to que x/4+(150-x)/2=58300-x=232x=68option3 option c is the correct answer c option is the right answer |
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| 20. |
If 510.be divided among A, B, C in such a way that A gets2/3 of what B get and B gets 1/4 of what C gets then theirshares are respectively- |
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Answer» Let amount of c=xB=1/4xA=(2/3)*(1/4)x=2/12x=1/6xSo x+.25x+0.16x=rs5101.416x=510X=510/1.416=360.17rsSo,a=360.17rsB=.25*360.17=rs90.04C=0.16*360.17=57.63rs |
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| 21. |
45464850umber of boys89the median for the following data: |
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Answer» 21 ke bad 50 Kaise Aaya |
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| 22. |
al Calculate the list price of an article whose selling price is81.20 and includes 14% discount |
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Answer» all so to FB KC RV it egg oh RV not each |
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| 23. |
(4) In the figure, seg AB and seg CD intersect at thepoint O. OA 15 cm, OB 12 cm, OC 10 cm,OD 8 cm. State whether AAOC and ABOD aresimilar or not. If so, by which test? |
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| 24. |
(4) In the figure, seg AB andnt O. OA: 15 cm. OB-12 cm,seg CD intersect at thecm, OC10 cm.tate whether AAOC and ABOD aresimilar or not. If so, by which test?0olve the following question |
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| 25. |
23. ABCD is a quadrilateral and O is the mid-point of AC.Prove that ar (quad. ABOD) =-ar (quad. ABCD). |
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| 26. |
\begin{array} { l } { \text { Find the difference between the } } \\ { \text { greatest number of four-digits and } } \\ { \text { the least number of five-digits. } } \\ { \text { (a) } 99991 } & { \text { (b) } 8999 } \\ { \text { (c) } 11 } & { \text { (d) } 1 } \end{array} |
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Answer» 10000-9999=11is the answer d. 1 is the answer 9999 is the grratest of 4 digits and 10000 is the least number of five digitstherefore 10000-9999 is 1 |
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| 27. |
3.The ratio of four angles of a quadrilateral is 3:7:5:9. Find the angles. |
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| 28. |
Writethe following numbers in figures using1) Forty five thousand six hundred eighteen. |
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Answer» It is 45, 618 is figures. |
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सो 3807 मैं यदि 2: «3.८0 «6.207 हो तो ८ (7 का मान है-(1) ¥’ (2) 603) 90 (4) 100 (1) |
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Answer» hit like if you find it useful |
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| 30. |
MATICSFind-y-, if xat, y2a.ах |
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Answer» Thnk uhh😊 |
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| 31. |
Fig. 6.79x + y1. The degree measure of three angles of a triangle are x, y and z.If2 then find tdhe value of z. 4120matics-tx |
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| 32. |
George bought a V.C.R at the list price ofRs 18,500. Ifthe rate ofVAT was 8%, find the amounthe had to pay for purchasing the V.C.R.a) Rs 19,9008,b) Rs 19,500c) Rs 19,980d)Rs 20,000 |
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| 33. |
Locate 10 on umber line |
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Answer» thanks |
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| 34. |
5. A sum of Rs. 3600 as a profitis to be divided among A, Band C in such a way that A:B= 15:8 and B:C= 7:8. Whatis A's share?(A) Rs. 1680(B) Rs. 1,024(C) Rs. 896(D) Rs. 796(1) D (2) C(3) B(4) A |
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Answer» A:B = 15:8B:C = 7:8A : B : C = 105 : 56 : 64Total = 105 + 56 + 64 = 225A's share = (105/225) × 3600 = 1680 |
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| 35. |
Find the larest umber whichdevi des 7o and 125 leaving remaindersnumbex h5 and 8 espestivey |
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Answer» The largest number by which x , y divisible and gives the remainder a , and b is the HCF of ( x - a ) and ( y - b) __________________________ According to the given problem , The largest number which divides 70 and 125 leaving remainders 5 and 8 respectively are HCF of ( 70 - 5 ) = 65 and ( 125 - 8 ) = 117 65 = 5 × 13 117 = 3 × 3 × 13 HCF ( 65 , 117 ) = 13 Required number is 13. |
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| 36. |
7. A milkman sold two of his buffales ont 2011hOn one he made a gain of 59, and onthe efher abod10%. Find his overall gain or loss. (Hint: FindCP of each) |
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| 37. |
(ii) 3形范讶LABC = 90°, LBAC = 60°60 |
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Answer» Thanks |
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| 38. |
3L Find four rational number between 2 and |
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| 39. |
-1 213nal.G) A + B(iii) 3A 2B (GTU, Jan. 2012) (iv) 2A 3B(ii) A - B |
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| 40. |
N 108909000121121 , N=210010ăcompound interest is for 2 years.10) =Practice Set 14.2onstruction work of a flyover bridge there were 320 workers1. On theinitially. The numbthe number ofumber of workers after 2 years.on sheen with him Find the number of sheens with him a |
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Answer» Initial number of workers=320Rate of increase=25% per year∴Number of workers after 2 years=320(1+25/100)²=500 |
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| 41. |
a Fathar has 3 times old has son 5 year ago father age was 4 times his son age. find there present age |
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Answer» let son present age=xfather age= 3x5 years agoson age= x-5father age= 3x-5A/S4(x-5)=3x-54x-20=3x-54x-3x= 20-5x=15son present age = 15 yearsfather present age= 3x= 15×3=45 years sons present age 15 yearsfather present age 45 years son present age 15 yearFather present age 45 year son=15,..................... |
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| 42. |
(b) What least number must be added to each of the n umber 5, 11, 19 & 37 so that they are inproportion? (3) |
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Answer» 5++ x / 11 + x = 19 + x / 37 + x (5 + x)(37 + x) = (19 + x)(11 + x) x2+ 42x + 185 = x2+ 30x + 209 42x - 30x = 209 - 185 12x = 24 x = 24 / 12 x = 2 Ans: 2 The least number is 2 Check: (5 + 2) / (11 + 2) = (19 + 2) / (37 + 2) 7 / 13 = 21 / 39 7 / 13 = 7/13 |
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17. A sum of Rs 8.85 is made up of 124 coins which are either10-paise coins or 5-paise coins; how many are there of each? |
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| 44. |
A sum of Rs. 36.90 is made up of 180 coins which areeither 10 paise coins or 25 p coins. The number of 10 pcoins iS:(a) 48(d) 60(b) 54 (c) 56(e) of these |
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| 45. |
The number of days left in the month of September are one fifth the number of days alreadyHow many days have already passed in the month of September? |
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Answer» let passed days = xthen left days = 1/5(x) now September has 30 days so,x + 1/5(x) =305x + x =1506x = 150x = 25so passed days in September are 25 days. 25 days ........... |
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| 46. |
Represent 7.5 onthe umber line |
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| 47. |
MATICSEXERCISE 1.27.-51) Represent these numbers on the number line. |
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| 48. |
Exercise 31Represent each of the following fractions on the number line.41.2.3. |
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Answer» 1) 3) |
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| 49. |
।।न-44. */4 )6- ५- । ५ ) ) *०/7// 2.11*/ 244( |
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| 50. |
46. 24, 60 3 90 44. fhTT ?The HCF of 24, 60 and 90 is:(A) 4(C) 3(B) 6(D) 12 |
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Answer» HCF of 24, 60 and 90 Factors of 24, 60 and 9024 = 2*2*2*360 = 2*2*3*590 = 2*3*3*5 HCF = 2*3 = 6 (B) is correct option |
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