(b) What least number must be added to each of the n umber 5, 11, 19 &

1.	(b) What least number must be added to each of the n umber 5, 11, 19 & 37 so that they are inproportion? (3)
Answer» 5++ x / 11 + x = 19 + x / 37 + x (5 + x)(37 + x) = (19 + x)(11 + x) x2+ 42x + 185 = x2+ 30x + 209 42x - 30x = 209 - 185 12x = 24 x = 24 / 12 x = 2 Ans: 2 The least number is 2 Check: (5 + 2) / (11 + 2) = (19 + 2) / (37 + 2) 7 / 13 = 21 / 39 7 / 13 = 7/13

(b) What least number must be added to each of the n umber 5, 11, 19 & 37 so that they are inproportion? (3)

Answer»

5++ x / 11 + x = 19 + x / 37 + x

(5 + x)(37 + x) = (19 + x)(11 + x)

x2+ 42x + 185 = x2+ 30x + 209

42x - 30x = 209 - 185

12x = 24

x = 24 / 12

x = 2

Ans: 2

The least number is 2

Check:

(5 + 2) / (11 + 2) = (19 + 2) / (37 + 2)

7 / 13 = 21 / 39

7 / 13 = 7/13