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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Fig. 5.38,. In figure 5.39, PQRS and OMNRL arerectangles. If point M is the midpoint of side PRthen prove that, () SL. LR, (ii) LN So.L.2Fig. 5.39 |
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| 2. |
29, ABCD is a parallelogram where A(x, y),B(5, 8), C(4, 7) and D(2, -4). Find(i) co-ordinates of A(ii) equation of diagonal BD.[2011 |
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| 3. |
20. The cost of 2 pencils and 2 pens is Rs. 46whereas 3 pencils and 5 pens together cost Rs. 74.Find the cost of one pencil and that of one pen. Or |
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Answer» Put in equation formlet pencil be X and pen be y2x+2y=46....X+y=23.....*3=3x+3y=693x+5y=74subtract both the equations-2y=-5y=5/2put in 15/2+X=23x=23-5/2x=20.5 |
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| 4. |
Doyo !oS13ye fp9an9adso: D PUE IR SIITUELN Jo suwipaw 23w g pae 1y 5 B |
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Answer» Like my answer if you find it useful |
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| 5. |
2+ V3x23 |
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| 6. |
1 hour 17 minute to minute ? |
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Answer» 1 hour = 60 minute 1 hour 17 minute = 60 minute + 17 minute = 77 minute If you find this answer helpful then like it. |
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| 7. |
14. A circle having its centre in the first quadrant touches the y-axis at the point (0, 2) andpasses through the point (1, 0). Find the equation of the circle. |
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| 8. |
The minute hand of a circular clock is 15 cm.How far does the tip of the minute hand move in 1 hour?(Take π-3.14) |
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Answer» Inone 1 hour, the tip will complete one rotationradius = 15 cmso, distance = 2πr = 2×π×15 =30π cm = 94.2 cm |
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| 9. |
The minute hand of a circular clock is 15 cm long. How far does the tip of the minutehand move in 1 hour. (Take π = 3.14)17. |
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Answer» can you gave me simple paper class9 science |
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| 10. |
circle. Find the angle subtended by the chord ata point on the minor arc and also at a point on themajor arc.3. In Fig. 10.37, PQR 100, where P, Q and R arepoints on a circle with centre O. Find ZOPR |
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Answer» Reflex ∠POR = 2 × ∠PQR = 2 × 100° = 200°∴ ∠POR = 360° - 200° = 160°In ΔOPR,OP = OR (radii of the circle)∠OPR = ∠ORPNow,∠OPR + ∠ORP +∠POR = 180° (Sum of the angles in a triangle)⇒ ∠OPR + ∠OPR + 160° = 180°⇒ 2∠OPR = 180° - 160°⇒ ∠OPR = 10° |
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| 11. |
Achord of a circle is equal to the radius of thecircle. Find the angle subtended by the chord ata point on the minor arc and also at a point on themajor are |
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| 12. |
6. Lipika reads a book for 12 hours everyday. She reads the entireHow many hours in all were required by her to read the book?book in 6 days.4 |
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| 13. |
DOWNLC II SL6. Lipika reads a book for 1 hours everyday. ShHow many hours in all were required by her to4ay. She reads the entire book"Were required by her to read the book |
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Answer» 10 hours and 30 minutes need to read book |
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| 14. |
20. The cost of 2 pencils and 2 pens is Rs. 46whereas 3 pencils and 5 pens together cost Rs. 74.Find the cost of one pencil and that of one pen. OrThe sum of two numbers is 18 and their difference |
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Answer» Let pencil be X and pen be yhence2x+2y=46...*3--6x+6y=1383x+5y=74....*2----6x+10y=148subtract both4y=10y=2.5henceput in equation. 1x=20.5 |
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| 15. |
6. Lipika reads a book for 1 hours everyday. She reads the entire book in 6 days.How many hours in all were required by her to read the book? |
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| 16. |
Lipika reads a book for 1-hours everyday. She reads the entire book in 6 deHow many hours in all were required by her to read the book? |
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| 17. |
6. Lipika reads a book for 1 - hours everyday. She reads the entire book in 6 dayHow many hours in all were required by her to read the book? |
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| 18. |
मर e ——— रेस,__“$-__#_LL___% e o _an_ WP it ) % & 7 bomb “वध वी नए Seased [ 7 4" e£ पाए 22 हा.के ———————————————— |
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Answer» We need to find in this question is a 15th term of an ap. So let start Sol..... A8=a+7d=a+d/2 2(a+7d)=a+d 2a+14d= a+d 2a-a+14d-d=0 a+13d=0. ...... (i) A+10d=a+3d/3+1 A+10d=(a+3d+3)/3 3(a+10d)=a+3d+3 3a-a+30d-3d-3=0 2a+27d=3. ... (ii) Solve (i)&(ii) Eq(i) multiply by 2 2a+26d=0......(iii) 2a+27d=3.......(iv)Solve (iii) & (iv) D=3Put d in (i) A+39=0 A= -39* D=3*A15=a+14d =. - 39+14(3)=. - 39+42=. 3A15 is 3* Answer is 3... |
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| 19. |
e Loocijo'c ondS em and bom du१७ ५५) . 03.0.A ko |
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Answer» In Parallelogram opposite sides are equal Given two adjacent sides length 5 cm and 6 cm Then, other two sides length are 5 cm and 6 cm opposite to given sides. Perimeter of Parallelogram= 5 + 5 + 6 + 6= 22 cm |
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| 20. |
Findcirclepointthe length of 2 tongends of aof radicy bom from an doternaidom above the circle. |
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Answer» Given, radius of the circle=6cm angle made by the chord at the center=60° let the other angles in the triangle be x because the radii of the circle are equal we know that, sum of the angles in the triangle=180° =>x+x+60°=180° =>2x+60°=180° =>2x=120° =>x=60° such that given triangle is equilateral triangle. hence, in the equilateral triangle all sides are equal. chord of the circle is 6 cm |
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| 21. |
1. If the cost of 18 pens is 423, find the cost of 25 such pens. |
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Answer» Cost of 18 pens=423Cost of 25 pens=(423*25)/18=587.5 |
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| 22. |
stepsDivide: (7x2+ 14x)2)5 cm. Write the steps of construct |
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Answer» 7x^2+14x/(x+2)Taking 7x comman 7x(x+2)/(x+2)7x will be the answer can u solve it again in a simpler manner pls |
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| 23. |
ÂĽ bz 1o 1 Frd valug (P2-2p âlap |
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| 24. |
11. ) How much energy can consumed a motor of 6Mw1 minute ? Write the result in kilowatt-hour |
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Answer» Energy=power*timeNow 6Mw=6*10^3Kwand 1 minute=1/60hourhence Energy=6000Kw*1/60=100Kw-hr |
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| 25. |
. Answer the following questions:a. What causes Tuberculosis? |
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Answer» Tuberculosis (TB) is caused by a type of bacterium calledMycobacterium tuberculosis. It's spread when a person with active TB disease in their lungscoughsorsneezesand someone elseinhalesthe expelled droplets, which contain TB bacteria. |
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| 26. |
Tuberculosis is caused by what |
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Answer» Tuberculosis (TB) is caused by a type of bacterium called Mycobacterium tuberculosis. |
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| 27. |
question of quadratic equations |
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Answer» how much terms of the arithmetic sequence 5,9,13... should be added to get the sum 434 |
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| 28. |
tion2.Bind the values of k for each of the following quadratic equations, so that they have tworoots.(i)2x2 + kx + 3-0(i) kx (r-2)+60 |
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Answer» i) 2x^2 + Kx + 3 = 0 Where, a = 2b = k c = 3 [ According to ax^2 + bx + c , we just compared equation with this ] We know, that equation has two equal roots, that means, D = 0 We know, D = b^2 - 4ac = 0 Keeping the values in it, (k)^2 - 4 × 2 × 3 = 0 k^2 - 24 = 0 k^2 = 24 k = (±)√24 ii) Kx^2-2kx +6=0 Equal roots implies that D=0 This implies that b^2-4ac=0 (-2k)^2 -24k=0 4k^2-24k=0 4k(k-6)=0 4k=0 This implies that k=0 And k-6=0 This implies that k=6 So,k=0,6 Like my answer if you find it useful! |
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| 29. |
o T o 25Frd SN2 (2 = % |
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| 30. |
4) Write any two quadratic equations. |
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Answer» x²-2x+4=0 2x²-x+6=0 |
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| 31. |
A.1 quadrant B. quaraltNumber of cubes of 3m length can form from a cuboid of volume 162m3.C. 54D. 18 |
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| 32. |
Rootsofthe quadratic equations 2x2 + x-528 = 0 is |
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Answer» Like if you find it useful |
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| 33. |
} ::I Joule = . |
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Answer» It is equal to the energy transferred to (orworkdone on) an object when aforceof onenewtonacts on that object in the direction of its motion through a distance of onemetre(1 newton metre or N⋅m). |
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| 34. |
q is:(1) 4x2 -8x +4 |
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| 35. |
8x+4 = 68 |
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Answer» 8x= 68-48x = 64x = 8 |
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| 36. |
oip (N2 - 3) |
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Answer» (a-b)^2 =a^2+b^2-2ab a=√2 b=3So the equation becomes,= 2+9-2(3)(√2) =11-6√2 |
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| 37. |
Simplify (8m2-n2)-(Sn2 + 8n-3) |
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Answer» please like my answer if you find it useful Thank you |
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| 38. |
8x +4 =3 (x-1)+ 7 |
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| 39. |
a metallic cuboid measuring 9cmx6cmx4cmis melted & formed into cube. find the side of the cube |
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| 40. |
8X + 4 = 3 (x-1) +7 |
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| 41. |
8x+4=3(x-1)+7 |
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Answer» 8x=3(x-1)+7-48x=3(x-1)+38x=3x-3+38x=3x-08x=3xx=3x/8 8x-3(x-1)=7-48x-3x+3=35x+3=35x=3-35x=0x=5 |
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| 42. |
(2) Write any two quadratic equations. (Open ended question.) |
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Answer» i) 2x² + 5x + 7 = 0ii) 6x² + 7x + 9 = 0 |
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| 43. |
v/3x22 V3↓ +10V6× 2+3÷5 |
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Answer» thank you very much |
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| 44. |
7, Solve for x: x2-W3 + 1)x + V3 = 0 |
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Answer» LIKE THE SOLUTION |
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| 45. |
V3-2V3.72of x2 + y2 + xy3 N2and y =,find the value |
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Answer» but answer of this question is 99. Apologies for the confusion! Here is the right one. |
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| 46. |
nd the surface area of the cuboid measuring 3 m x 2 m x 1.5 m. |
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| 47. |
4. 4x2-4x-3 |
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| 48. |
4x2 -8x 4 |
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Answer» 4x² - 8x + 4 4x² - 4x - 4x + 4 4x ( x - 1) -4 ( x - 1) ( 4x - 4) ( x - 1) 4 ( x - 1)² |
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| 49. |
1) 4x2 - 8x +4 |
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| 50. |
EXERCIS1. Check whether the following are quadratic equations:(ii) (x+ 1) 2(x3 |
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Answer» thx |
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