मर e ——— रेस,__“$-__#_LL___% e o _an_ WP it ) % & 7 bomb “वध वी नए Seased [ 7 4" e£ पाए 22 हा.के ————————————————

मर e ——— रेस,__“$-__#_LL___% e o _an_ WP it ) % & 7

1.	मर e ——— रेस,__“$-__#_LL___% e o _an_ WP it ) % & 7 bomb “वध वी नए Seased [ 7 4" e£ पाए 22 हा.के ————————————————
Answer» We need to find in this question is a 15th term of an ap. So let start Sol..... A8=a+7d=a+d/2 2(a+7d)=a+d 2a+14d= a+d 2a-a+14d-d=0 a+13d=0. ...... (i) A+10d=a+3d/3+1 A+10d=(a+3d+3)/3 3(a+10d)=a+3d+3 3a-a+30d-3d-3=0 2a+27d=3. ... (ii) Solve (i)&(ii) Eq(i) multiply by 2 2a+26d=0......(iii) 2a+27d=3.......(iv)Solve (iii) & (iv) D=3Put d in (i) A+39=0 A= -39* D=3A15=a+14d =. - 39+14(3)=. - 39+42=. 3A15 is 3 Answer is 3...