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The number of zeros=number of intersection of graph with x-axis=1

2 is the smallest prime number

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Radii of circleOC, OE, OB, OD, OA

Diameter of circleCD, AB

3:5 ratio of their circumstances

the circumference is also same becausecircumference=2πr2πr/2πrr/r2/32;3

7x+9y

sin /cos= tan xplease like the solution

Given that one zero of polynomial x^2 + 3x + k is 2

Then,For x = 2 given polynomial will be equal to 0

Hence,(2)^2 + 3(2) + k = 04 + 6 + k = 0k = - 10

Therefore, value of k = - 10

the question is submitted is incomplete please post the complete question

-3

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the value of b in wrong the value is 8

Circumference = 2*(22/7)*rr = 7.9/2= 3.95 units.

Circumference = 2*(22/7)*3.95= 24.83 units

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The ratio between the radii of two circles is 5:3.2Pi is constant i.e 3.14.The radius is directly proportional to the circumference of the circle. P=2×Pi×R

3y² + 7y + 2 = 3y² + 6y + y + 2 = 3y(y + 2) + (y + 2) = (3y + 1)(y + 2)

4x² - 13xy + 3y²4x² - 12xy - xy + 3y²4x(x - 3y) -y ( x - 3y)(4x - y) ( x - 3y)

3y^2 -20=160-2y^23y^2+2y^2=160+205y^2=180y^2=36y=6

3y^2+2y^2= 1805y^2= 180y^2= 180/5y^2= 36y= 6

no b

Given 18, a, b, -3 So, a - 18 = b-a = -3 - bSo a - 18 = b-a2a - b = 18 ......(1)

b-a = -3 -ba -2b = 3 ......(2)

Solving (1) and (2) we get, eq (1) - 2× eq(2)2a - b = 182a -4b = 6

So , -b + 4b = 124b = 12b = 3Therefore, a = 3 + 2ba = 3 + 6 = 9So, no option is correct as a = 9 and b = 3

u go frst

Sorry for inconvenience there are some calculations mistake is previous one

Let , f(x) = x²-xsinx – cosx

F’(x) = 2x – xcosx – sinx +sinx

F’(x) = 2x – xcosx

=(0,-1)

F(0) = -1

So, if we see there exists only two points as the point (0,-1) makes a curve at two points

Hence , it has two solutions

The answer is two.

1. x² +X -20=0=> x² +5x -4x -20=0=> x(X+5)-4(X+5)=0=> (x-4)(X+5)=0=> X = 4, -5.

4. 9y² -12y +2 = 0=> y ={ +12±[(-12)² -4(9)(2)]½ }/2(9)=> y = [ 12± 6√2 ] / 18=> y = (2/3) ± (√2/3)

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2(2y-1)=3(y+2)4y-2=3y+64y-3y=6+2y=8

2(2y-1) =3(y+2)4y-2=3y+64y-3y= 6+8y= 8

the correct answer is C

greatest number= 12002,124smallest number= 2853,124

greatest number is 12002smallest number is 124,so answer is a) 12002, 124

ans is number a 120022,124

3y^2+2y^2= 1805y^2= 180y^2= 180/5y^2= 36y= 6

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Thanks...

x + y = 10.......(1)x - y = 2...........(2)(1) + (2)2x = 12;x = 6;y = 4

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It is an arithmetic seriesa = -4, d = +3-4 - 1 + 2 +..... + x = 437

Sum of the series Sn=> [2a + (n-1)d ]n /2 = 437 [ -8 + 3(n-1) ] n /2 = 437 - 11n + 3n² = 874 3 n² -11n - 874 = 0 n =(11 + 103 )/6 = 114/6 = 19 (as n is +ve only)

So x = a + (n-1)d x = -4 + 3 (19-1) = 50