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The number of points in (-oo, oo), for which x2-x sinx-cosx = 0, is(A) 6(B) 4[JEE (Adva(C) 2 |
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Answer» Let , f(x) = x²-xsinx – cosx F’(x) = 2x – xcosx – sinx +sinx F’(x) = 2x – xcosx =(0,-1) F(0) = -1 So, if we see there exists only two points as the point (0,-1) makes a curve at two points Hence , it has two solutions The answer is two. |
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